0riginal break even point:
285000/ 60/35 = $166,250
New break even point = new fixed costs / ( selling price - variable cost/ selling price)
New break even point = 285,000 + 15,900. / ( 60-( 35-4.50)/60
300,900 / 60-30.50/60 = $612,000
The new break even point increases.
With the new machine, Kent Co.'s break-even point in units would decrease, from 11,400 to 10,200 units. Despite increasing fixed costs, the new machine drives down variable costs, effectively lowering the total number of units needed to cover costs.
The concept under consideration here is the break-even point calculation in unit terms. The break-even point (units) is calculated by dividing the total fixed costs by the contribution margin per unit, which is sales price per unit minus variable cost per unit.
Currently, Kent Co.'s break-even point can be found using its original costs:
If Kent were to purchase the new machine, its costs would alter as follows:
Thus, purchasing the new machine would in fact lower Kent Co.'s break-even point to 10,200 units, thereby improving its cost efficiency.
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Answer:
About 5.52 feet tall.
Step-by-step explanation:
Divide 55/30. You will get 1.84. Then multiply 3 by 1.84 to get the answer :)
2. A unique solution exists in the entire xy-plane.
3. A unique solution exists in the region y ≤ x.
4. A unique solution exists in the region consisting of all points in the xy-plane except the origin.
5. A unique solution exists in the region x2 + y2 < 1.
A unique solution exists in the region consisting of all points in the xy-plane except the origin.
The correct option is 4.
The given differential equation is:
(x² + y²)y' = y²
The equation can be rewritten as:
We need to determine a region of the xy-plane for which the differential equation would have a unique solution whose graph passes through a point (x₀, y₀) in the region.
To determine the region, we can use the existence and uniqueness theorem for first-order differential equations.
According to the theorem, a unique solution exists in a region if the differential equation is continuous and satisfies the Lipschitz condition in that region.
To check if the differential equation satisfies the Lipschitz condition, we can take the partial derivative of the equation with respect to y:
dy/dx = y / (x² + y²)
The partial derivative is continuous and bounded in the entire xy-plane except at the origin (x=0, y=0).
Therefore, the differential equation satisfies the Lipschitz condition in the entire xy-plane except at the origin.
Since the differential equation is continuous in the entire xy-plane, a unique solution exists in any region that does not contain the origin. Therefore, the correct answer is:
A unique solution exists in the region consisting of all points in the xy-plane except the origin.
To learn more about the Lipschitz condition;
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The differential equation will have a unique solution in the entire xy-plane except at the origin, as both the function and its partial derivatives are continuous and well-defined everywhere except at that point.
To determine a region of the xy-plane where the differential equation (x2 + y2)y' = y2 has a unique solution passing through a point (x0, y0), we need to consider where the function and its derivative are continuous and well-defined. According to the existence and uniqueness theorem for differential equations, a necessary condition for a unique solution to exist is that the functions of x and y in the equation, as well as their partial derivatives with respect to y, should be continuous in the region around the point (x0, y0).
We note that both the function (x2 + y2)y' and its partial derivative with respect to y, which is 2y, are continuous and well-defined everywhere except at the origin where x = 0 and y = 0. Therefore, a unique solution exists in the region consisting of all points in the xy-plane except the origin.
From the given options, the correct answer is:
4. A unique solution exists in the region consisting of all points in the xy-plane except the origin.
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Answer:
The 95% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample proportion is
The sample size is
Given that the confidence level is 95% then the level of significance is mathematically evaluated as
Next we obtain the critical value of from the z-table , the value is
The reason we are obtaining critical value of instead of is because
represents the area under the normal curve where the confidence level interval ( ) did not cover which include both the left and right tail while is just the area of one tail which what we required to calculate the margin of error
NOTE: We can also obtain the value using critical value calculator (math dot armstrong dot edu)
Generally the margin of error is mathematically represented as
substituting values
The 95% confidence interval is mathematically represented as
substituting values
Answer:
-10, 40, -240, 1,920 and -19, 200
Step-by-step explanation:
Given the recurrence relation of the sequence defined as aₙ₊₁ = -2naₙ for n = 1, 2, 3... where a₁ = 5, to get the first five terms of the sequence, we will find the values for when n = 1 to n =5.
when n= 1;
aₙ₊₁ = -2naₙ
a₁₊₁ = -2(1)a₁
a₂ = -2(1)(5)
a₂ = -10
when n = 2;
a₂₊₁ = -2(2)a₂
a₃ = -2(2)(-10)
a₃ = 40
when n = 3;
a₃₊₁ = -2(3)a₃
a₄ = -2(3)(40)
a₄ = -240
when n= 4;
a₄₊₁ = -2(4)a₄
a₅ = -2(4)(-240)
a₅ = 1,920
when n = 5;
a₅₊₁ = -2(5)a₅
a₆ = -2(5)(1920)
a₆ = -19,200
Hence, the first five terms of the sequence is -10, 40, -240, 1,920 and -19, 200
b. hyperbolic paraboloid
c circular paraboloid
d.circular cylinder
e. elliptic cylinder
Following are the calculation to the given equation:
Given vector equation:
The corresponding parametric equations for the given surface is given by,
For any point (x,y,z) we have that,
So, after eliminating the parameters, we get,
Therefore, the answer is "Option c".
Learn more:
The surface represented by the given vector equation r(s, t) = s sin 4t, s2, s cos 4t is a circular cylinder. This can be inferred from the structure of the equation and the characteristics of the represented shapes.
The surface represented by the given vector equation,
r(s, t) = s sin 4t, s2, s cos 4t
, is a type of cylindrical surface due to the structure of the equation. This can be identified by the s terms being tied to sin/cos functions and an independent s^2 term. This shows that the s variable is acting as a 'driver' of the shape, while t coordinates the rotation. Owing to the periodic sin and cos functions in the vector equation, the surface does not lie in a single plane, ruling out the option of a plane. It also does not exhibit features of a paraboloid or hyperbolic paraboloid. Hence, it's shown that the vector equation represents a
circular cylinder
.
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