Which statement best illustrates using the vertical line test to determine if the graph below is a function of x? The graph is not a function of x because the line x = 0 intersects the graph at two points. The graph is a function of x because the line x = 5 does not intersect the graph. The graph is not a function of x because the line y = 0 intersects the graph at two points. The graph is a function of x because the line y = 5 does not intersect the graph.
Which statement best illustrates using the vertical line test to - 1

Answers

Answer 1
Answer:

Answer:

The graph is not a function of x because the line x = 0 intersects the graph at two points.

Step-by-step explanation:

This graph is not a function because it fails the vertical line test, since several vertical lines would intersect the graph at 2 points.

This answer choice is correct, as the line x = 0 intersects the graph at 2 points, (0, 2) and (0, -2).

Answer 2
Answer:

Answer:

A

Step-by-step explanation:


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Verify the identity sec(beta) - 1 / cos(beta) = sec(beta)

Answers

(sec(\beta)-1)/(1-cos(\beta))=sec(\beta)

we know that

sec(\beta)=(1)/(cos(\beta))

then, lets replace it

((1)/(cos(\beta))-1)/(1-cos(\beta))=(1)/(cos(\beta))

multiple each member by cos(\beta)

(1-cos(\beta))/(1-cos(\beta))=1

simplifying

1=1

To verify the given identity sec(beta) - 1 / cos(beta) = sec(beta), we need to manipulate the left side of the equation to match the right side. By simplifying the expression step by step and using trigonometric identities, we can show that the given equation is true.

To verify the given identity sec(beta) - 1 / cos(beta) = sec(beta), we need to manipulate the left side of the equation to match the right side.

  1. Start by finding the common denominator of the fractions on the left side, which is cos(beta).
  2. The expression becomes (sec(beta) - 1)/cos(beta).
  3. Next, simplify the numerator: sec(beta) - 1 = (1/cos(beta)) - 1 = (1 - cos(beta))/cos(beta).
  4. Substituting this back into the original expression, we have (1 - cos(beta))/cos(beta) / cos(beta).
  5. Simplify further by multiplying the numerator and denominator by cos(beta) to get (1 - cos(beta))/(cos^2(beta)).
  6. Using the identity sec^2(beta) = 1 + tan^2(beta), we rewrite cos^2(beta) = 1 - sin^2(beta) as 1/(1 - sin^2(beta)).
  7. Therefore, (1 - cos(beta))/(cos^2(beta)) = (1 - cos(beta))/(1 - sin^2(beta)) = sec(beta).

Thus, we have verified that sec(beta) - 1 / cos(beta) = sec(beta).

Learn more about trigonometric here:

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Gloria earns 1.5 times her normal hourly pay for each hour that she works over 40 hours in a week. Here normal pay is $9.70 per hour. Last week Gloria earned $489.85 How many hours did she work last week?

Answers

She earns ($9.70x40) for a 40 hour week=$388
She earned $489.85-$388 extra= $101.85
She gets paid $9.7x1.5 for every extra hour=$14.55
She worked $101.85/$14.55 hours extra=7hours
She worked 7+40 hours that week=47 hours

Givivn h(x)=-x+1, solve for x when h(x)=0

Answers

Answer:

x = 1

Step-by-step explanation:

given h(x) = - x + 1

when h(x) = 0 , that is

- x + 1 = 0 ( subtract 1 from both sides )

- x + 1 - 1 = 0 - 1 ( simplify both sides )

- x = - 1 ( multiply both sides by - 1 )

- 1 × - x = - 1 × - 1 , that is

x = 1

Nicole deposited $2,000 at 6% simple interest. How long will it be before she has $2,600 in her account?

Answers

\bf \qquad \textit{Simple Interest Earned Amount}\n\nA=P(1+rt)\qquad \begin{cases}A=\textit{accumulated amount}\to &2,600\nP=\textit{original amount deposited}\to& \$2,000\nr=rate\to 6\%\to (6)/(100)\to &0.06\nt=years\end{cases}

solve for "t"

If p varies directly with q, and p = 10 when q = 5, what is the value of p when q = 20? A.p = 40

B.p = 1

C.p = 100

D.p = 28

Answers

A. p=40 because if you look at your question carefully q is half of p so if q=20 which is half of 40 then that means p=40

If two congruent angles form a linear pair, then __________.A.
one angle is acute and the other angle is obtuse
B.
they are both right angles
C.
they are both acute angles
D.
they are both obtuse angles

Answers

The correct answer is option B. If two congruent angles form a linear pair, then they are both right angles. Two figures are said to be congruent when they have the same shape and size or if one object is a mirror image of the other object.