The following data points represent the number of points scored last basketball game by each player on the Dragons basketball team.5,8,11,7,?

If the mean of the data set is 8 points, find the missing number of points.

Answers

Answer 1
Answer:

Answer:

9

Step-by-step explanation:

There are 5 data points.  To find the mean, we add the data and divide by 5

(5+8+11+7+?) /5 = 8

Multiply each side by 5

(5+8+11+7+?) /5 *5 = 8*5

(5+8+11+7+?)  = 40

Combine like terms

? + 31 = 40

Subtract 31 from each side

? +31-31 = 40-31

? = 9

The missing number is 9

Answer 2
Answer: The missing number is 9.

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|(8.6x107):(9.1x10-8)

Answers

Answer:

9.45054*10^(14)

Step-by-step explanation:

we have

(8.6*10^(7) )/(9.1*10^(-8))=(8.6)/(9.1)*( 10^(7))*(10^(8))\n \n= (8.6)/(9.1)*( 10^(7+8))\n \n= (8.6)/(9.1)*( 10^(15))\n \n=0.945054*( 10^(15))\n \n=9.45054*10^(14)

Answer:

\large\boxed{9.45\cdot10^(14)}

Step-by-step explanation:

(8.6*10^7):(9.1*10^(-8))\n\n=(8.6)/(9.1)\cdot(10^7)/(10^(-8))\qquad\text{use}\ (a^n)/(a^m)=a^(n-m)\n\n=(86)/(91)\cdot10^(7-(-8))\n\n=(86)/(91)\cdot10^(7+8)\n\n=(86)/(91)\cdot10^(15)\n\n\approx0.945\cdot10^(15)\n\n=9.45\cdot10^(-1)\cdot10^(15)\qquad\text{use}\ a^n\cdot a^m=a^(n+m)\n\n=9.45\cdot10^(-1+15)\n\n=9.45\cdot10^(14)

In triangle LMN, the measure of m_L =75°and m_M is one-half m_N. what is m_M?

Answers

Let m(<N) be x;
We have m(<M) = 1.5x;
We solve the equation: 75 + x + 1.5x = 180;
75 + 2.5x = 180;
2.5x = 105;
x = 105 ÷ 2.5;
x = 42;
Finally, m(<M) = 63 degrees;

Find The Following. BRAINLIEST ASAP TY!!!! (precalculus)​

Answers

(q ° r) = -32
(r ° q) = 101

Answer:

Top left: -32

Bottom left: 101

at a party there were four large submarine sandwiches, all the same size during the party, 2/3 of the chicken sandwich, 3/4 of the tuna sandwich, 7/12 of the roast beef sandwich and 5/6 of the veggie sandwich were eaten. which sandwich had the least amount left ?

Answers

Answer: The answer is the Veggie Sandwich

Step-by-step explanation:  Given that there are four large submarine Sandwiches in a party and all of them are of the same size.

Some parts of each of them were eaten during the party. We are to find the Sandwich that has the least amount left.

The fractions of the Chicken Sandwich(C), Tuna Sandwich(T), Roast beef Sandwich(R) and the Veggie Sandwich(V) that were eaten during the party are given by

C=(2)/(3),\n\nT=(3)/(4),\n\nR=(7)/(12),\n\nV=(5)/(6).

Therefore, the fractions of the Sandwiches that left will be

C'=1-C=1-(2)/(3)=(1)/(3)=(4)/(12),\n\nT'=1-T=1-(3)/(4)=(1)/(4)=(3)/(12),\n\nR'=1-R=1-(7)/(12)=(5)/(12),\n\nV'=1-V=1-(5)/(6)=(1)/(6)=(2)/(12).

Out of the four fractions, V' is the smallest, so the Veggie Sandwich has the least amount left.

 

Veggi sandwich had the least amount left

Can you help me with number 12 ,13,14,and 15

Answers

12. 5 T>5,000lb 13. 18000lb=5T 14. 25lb>350oz 15. 27oz>2lb

Rita is spending more time at home to study and practice math. Her efforts are finally paying off. On her first assessment she scored 58 points, then she scores 63 and 68 on her next two assessments. If her scores continued to increase at the same rate, on which assessments will she be scoring above 85?

Answers

Answer

She will be scoring above 85 after her 7 assessment.

Explanation

We can model this situation using a line equation.

We know that on her first assessment, Rita scored 58 points, so our first point is (1, 58)

We also know that on her second assessment, Rita scored 63 points, so our second point is (2, 63)

To find the rate, which is the slope of our line, we are using the slope formula:

m=(y_(2)-y_(1))/(x_(2)-x_(1))

where

(x_(1),y_(1)) are the coordinates of the first point

(x_(2),y_(2)) are the coordinates of the second point

From our points we can infer that x_(1)=1, y_(1)=58, x_(2)=2, y_(2)=63. Let's replace the values in our slope formula:

m=(y_(2)-y_(1))/(x_(2)-x_(1))

m=(63-58)/(2-1)

m=(5)/(1)

m=5

Now we know that Rita's score is increasing 5 points every assessment.

To complete the equation of our line, we are using the point slope formula:

y-y_(1)=m(x-x_(1))

y-58=5(x-1)

y-58=5x-5

y=5x+53

Finally, we just need to replace y with 85 in our line equation and solve for x to find after which assessment she will score above 85:

85=5x+53

32=5x

x=(32)/(5)

x=6.4

Since we can't have 0.4 assessment, she will be scoring above 85 after her 7 assessment.  


This is a pattern in which you add five points to the next assessment. 
1st= 58, 2nd=63, 3rd=68, 4th=73, 5th= 78, 6th=83, 7th=88 points
So on her seventh assessment, she will get higher than 85 points. 
Hope this helps.