Answer:
Here's what I get
Step-by-step explanation:
Part A
The graph shows a polynomial of odd degree. It is probably a third-degree polynomial — a cubic equation.
Part B
The standard form of a cubic equation is
y = ax³ + bx² + cx + d
The factored form of a cubic equation is
y = a(x - b₁)(x² + b₂x + b₃)
If you can factor the quadratic, the factored form becomes
y = a(x - c₁)(x - c₂)(x - c₃)
Part C
The zeros of the function are at x = -25, x = - 15, and x = 15.
Part D
The linear factors of the function are x + 25, x + 15, and x - 15.
Part E
y = a(x + 25)(x + 15)(x - 15) = a(x + 25)(x² - 225)
y = a(x³ + 25x² - 225x - 5625)
Part F
When x = 0, y = 1.
1 = a[0³ +25(0)² - 225(0) - 5625] = a(0 + 0 - 0 -5625) = -5625a
a = -1/5625
Part G
Answer
Actually, the answer should be -0.0007(x+20)(x+5)(x-15)
Step-by-step explanation:
This is continuing off of the previous answer
PART C
The zeros should be (15,0), (-5,0), and (-20,0)
PART D
x - 15, x + 5, and x + 20
PART E
a(x - 15)(x + 5)(x + 20)
Standard:
PART F
The y-intercept is at (0,1), so we replace the x's with 0:
1 = and this gives us (0+0-0-1500) which also equals -1500
Then we do which gives us -0.0006 repeating which rounds to -0.0007
a= -0.0007
PART G
Just place the numbers where they should go and your answer is
y =-0.0007(x + 20)(x + 5)(x - 15)
the placement for (x + 20) (x + 5) and (x - 15) doesn't matter as long as they are behind -0.0007
Answer:
No
Step-by-step explanation:
18-6=12
-18+6=-12
It is the opposite because rather than subtracting from a positive, you're adding to a negative.
Hope this helps :)
B. r*12
C. r - 12
D r + 12
r ÷ 12 or r/12
Given the word phrase: the quotient of r and 12.
An algebraic expression for it is
Notes:
The quotient is the ratio of two quantities to be divided or the number obtained by division. Synonyms for the quotient are proportion, ratio, or fractions.
An algebraic expression for the quotient of a and b is
The quotient, a dividend, and a divisor represent the fundamental components of a division equation.
Another example:
A car requires 10 liters of fuel to travel 60 km. Determine the quotient of the distance of the car with fuel (in km/L).
The quotient (or ratio) is
Consider the same method as follows.
This means that the car can travel a distance of 6 km for every 1 L of fuel.
Kilometers per liter is a unit used to measure fuel economy and we see this as one example of the use of the quotient (or ratio).
Keywords: write an algebraic expression, for the word phrase, the quotient of r and 12, a dividend, a divisor, components of a division equation
The difference of a number 5 and 4/ 3 is 11/3.
Subtracting fractions include the subtraction of two or more fractions with the same or different denominators. Like fractions can be subtracted directly but for unlike fractions we need to make the denominators same first and then subtract them.
Given that, the difference of a number and 4/ 3 is 11/3.
Let the unknown number be x.
Here, x-4/3 =11/3
x= 11/3+4/3 (Transpose 4/3 to RHS of the equation)
To add like fractions, add the numerators and keep the denominator same. That is
x= 15/3
x=5
Therefore, the unknown number is 5.
To learn more about the subtraction of fractions visit:
#SPJ2
Answer:
5
Step-by-step explanation:
15/3 - 4/3 = 11/3
15/3 = 5
Answer:
Value after two years: P(2) = 4000(1.005)^24 = **** 4508.64 ***