Step-by-step explanation:
10858100817910891900
B. Locate the ordered pair (0, –6). From that point on the graph, move up 2, left 1 to locate the next ordered pair on the line. Draw a line through the two points.
C.Locate the ordered pair (–6, 0). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points.
D.Locate the ordered pair (–6, 0). From that point on the graph, move up 2, left 1 to locate the next ordered pair on the line. Draw a line through the two points.
Answer:
A is the correct option.
Step-by-step explanation:
The slope of the line is 2 and the y-intercept is -6.
y-intercept is the point where x is zero. Hence, the point is (0,-6)
When we graph a linear function by slope-intercept method, first of all we plot the y-intercept.
Hence, first of all we plot the point (0,-6)
Now, slope is given by
if rise is positive then we move up from the y -intercept and if negative then move down. We keep run always positive and hence we move right from the rise point.
rise = 2
run = 1
Rise is positive hence, we move 2 units up from the point (0,-6) and then move 1 unit right to get the next point. Then we draw a line passing through these points.
A is the correct option.
Answer:
Probability: (About) 0.8
Step-by-step explanation:
~ Provided that point X is randomly plotted on the line segment JM, we must calulculate the probability with which it lands on KM the first time ( implied ) ~
1. We know that the line segment JM, by the Partition Postulate ⇒ JK + KL + LM. With that being said JM = 3 + 7 + 4 = 14 units
2. Now line segment KM, by the Partition Postulate ⇒ KL + LM. With the assigned values, we can tell that KM = 7 + 4 = 11 units
3. If we were to determine the porbability that X lands on the line segment KM, considering the first try it would be KM/JM ⇒ Probability: 11/14
Hi Panda
m²/5f²/m/f³
= m²/5f^5m
= m/5f^5
I hope that's help:0
Step-by-step explanation:
Let be the distance between Kayden and safe zone at any time.
It is given that initially
Lrt her speed be
Since the speed is constant,the distance covered by her in seconds=
So,the distance between her and safe zone after seconds is
It is given that after seconds,
So,
So,
Answer:
y=-25x+160
Step-by-step explanation: