What is a3 if an=64(12)n−1

Answers

Answer 1
Answer:

Answer:

\huge\boxed{a_3=9,216}

Step-by-step explanation:

a_n=64(12)^(n-1)\n\n\text{substitute}\ n=3:\n\na_3=64(12)^(3-1)=64(12)^2=64(144)=9,216


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Events A and B are mutually exclusive. Suppose event A occurs with probability 0.02 and event B occurs with probability 0.73. Compute the probability that B occurs or A does not occur (or both). Compute the probability that either B occurs without A occurring or A and B both occur

Answers

Answer:

1. The probability that B occurs or A does not occur (or both) is 0.73.

2. The probability that either B occurs without A occurring or A and B both occur is 0.73.

Step-by-step explanation:

It is given that the events A and B are mutually exclusive. It means the intersection of A and B is 0.

P(A\cap B)=0

Given information:

P(A)=0.02

P(B)=0.73

We get,

P(A')=1-P(A)=1-0.02=0.98

P(B')=1-P(B)=1-0.73=0.27

(1) We need to find the probability that B occurs or A does not occur (or both).

P(B\cup A')+P(A\cap B)=P(B)+0

P(B\cup A')+P(A\cap B)=0.73+0

P(B\cup A')+P(A\cap B)=0.73

Therefore the probability that B occurs or A does not occur (or both) is 0.73.

(2) We need to find the probability that either B occurs without A occurring or A and B both occur.

P(B\cup A')+P(A\cap B)=P(B)+0

P(B\cup A')+P(A\cap B)=0.73+0

P(B\cup A')+P(A\cap B)=0.73

Therefore the probability that either B occurs without A occurring or A and B both occur is 0.73.

Final answer:

For mutually exclusive events A and B, the probability that B occurs or A does not occur is approximately 1.45. The probability that either B occurs without A occurring or A and B both occur is 0.73 because A and B are mutually exclusive.

Explanation:

Events A and B are defined as mutually exclusive, which means they cannot occur at the same time. Hence, the probability that A and B both occur (referred to as P(A AND B)) is 0. In this question, for the first scenario, we need to compute the probability that B occurs or A does not occur which is denoted as P(B OR not A). Since events A and B are mutually exclusive, not A occurs with probability 1 - P(A) = 0.98. So, P(B OR not A) = P(B) + P(not A) - P(B AND not A) = 0.73 + 0.98 - (0.73 * 0.98) = 1.45 (approximately).

For the second scenario, we need to calculate the probability that either B occurs without A occurring or A and B both occur which is expressed as P((A and B) OR (B and not A)). But as we know P(A and B) = 0 for mutually exclusive events, there only remains P(B and not A). Again, as A and B are mutually exclusive, we can be sure that if B is happening, A is not, so the answer is P(B) = 0.73.

Learn more about Mutually Exclusive Events here:

brainly.com/question/28565577

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What is the least What is the least common multiple of four and 12

Answers

Answer: LCM(4,12) = 12

Step-by-step explanation:

This of this as singing all the multiples of 4

4, 8, 12.

4 + 4 + 4.

Answer:

2

Step-by-step explanation:

10 is equal or less than j + 5

Answers

Answer:

10 is equal or less than (sign that opens up to the right with line underneath) j+5

Answer:

10 is less than j + 5

Step-by-step explanation:

because 10 lies between two consecutive perfect squares (in increasing order)...

The sum of three consecutive numbers is 318. What is the third number in the series?

Answers

Answer:

106

Step-by-step explanation:

x + x + 1 + x + 2=318

3x + 3=318

3x=318-3

3x=315

x=104 1st number

3rd no=104 + 2 = 106

I need help with this! thanks​

Answers

Answer:

it should be about 6. try measuring the the 3 line with paper or something then put it on the other line

Step-by-step explanation:

Find cardinality of set B

B = {∅, {1}, {1, 2}, {1, 2,3}, · · · , {1, 2, · · · , m}}

Answers

Answer:

m + 1

Step-by-step explanation:

Given set,

B = {∅, {1}, {1, 2}, {1, 2,3}, · · · , {1, 2, · · · , m}},

Since, the elements of S are,

{} , {1}, {1, 2}, {1, 2, 3}....... {1, 2,.....m }

Thus, every next set contains one more succeeding natural number than the previous set.

So, if the last set contains m natural numbers.

Then there are 'm + 1' sets in B ( m sets included ∅ )

Hence, the number of elements in B is 'm+1'

I.e. Cardinality of B is m + 1.