A compound is found to contain 18.28 % phosphorus , 18.93 % sulfur , and 62.78 % chlorine by mass. To answer the question, enter the elements in the order presented above. QUESTION 1: The empirical formula for this compound is . QUESTION 2: The molar mass for this compound is 169.4 g/mol. The molecular formula for this compound is

Answers

Answer 1
Answer:

Answer:

1. EF = PSCl₃; 2. MF = PSCl₃  

Explanation:

1. Empirical formula

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our first job is to calculate the molar ratio of P:S:Cl.

Assume 100 g of the compound.

(a) Calculate the mass of each element.

Then we have 18.28 g P, 18.93 g S, and 67.28 g Cl.

(b) Calculate the moles of each element

\text{Moles of P} = \text{18.28 g C} * \frac{\text{1 mol P}}{\text{30.97 g P}} = \text{0.5902 mol P}\n\n\text{Moles of S} = \text{18.93 g S} * \frac{\text{1 mol S}}{\text{32.06 g S }} = \text{0.5905 mol S}\n\n\text{Moles of Cl} = \text{62.78 g Cl} * \frac{\text{1 mol Cl}}{\text{35.45 g Cl }} = \text{1.771 mol Cl}

(c) Calculate the molar ratio of the elements

Divide each number by the smallest number of moles

P:S:Cl = 0.5902:0.5905:1.898 = 1:1.000:3.000 ≈ 1:1:3

(d) Write the empirical formula

EF = PSCl₃

The empirical formula for this compound is PSCl₃.

2. Molecular formula

(a) Calculate the ratio of the molecular and empirical formula masses

n = (169.4 u)/(169.40 u) = 1.000 ≈ 1

(b) Calculate the molecular formula

MF = (EF)ₙ = (EF)₁ = PSCl₃

The molecular formula for this compound is PSCl₃.

Answer 2
Answer:

The empirical formula of the compound is PSCl₃.

To find the empirical formula, we first need to find the moles of each element in the compound. We can do this by dividing the mass of each element by its molar mass. The molar masses of the elements are:

P = 30.97 g/mol

S = 32.06 g/mol

Cl = 35.45 g/mol

The mass percentages given are for 100 g of the compound. So, the mass of each element in 100 g of the compound is:

P = 18.28 g

S = 18.93 g

Cl = 62.78 g

The moles of each element are then:

P = 18.28 g / 30.97 g/mol = 0.590 mol

S = 18.93 g / 32.06 g/mol = 0.590 mol

Cl = 62.78 g / 35.45 g/mol = 1.770 mol

The smallest whole number ratio of the moles of each element is 1:1:3. So, the empirical formula of the compound is PSCl3.

The molecular formula of the compound can be the same as the empirical formula, or it can be a multiple of the empirical formula. The molecular formula is not given, so we cannot say for sure what it is. However, we can say that the molecular formula must be a whole number multiple of the empirical formula PSCl3.

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Iron has density of 7.9g/cm3. What is the mass of a cube with the length of one side equal to 1.64x10squared cm3?

Answers

Given data:

Density of iron (Fe) = 7.9 g/cm3

Length of one side of the iron cube = 1.64 * 10^2 cm

Now, the volume (V) of a cube in which the length of the side is 'a' cm is given as:

V = a^3

Volume of iron cube = (1.64 *10^2 cm)^3 = 4.41 * 10^6 cm3

The density (D) of an object of mass (m) and volume (V) is given as:

D = m/V

or, m = D*V

Therefore, mass of iron cube = 7.9 g/cm3 * 4.41 * 10^6 cm3

                                                = 34.84 *10^6 g

Which of the following Ph levels would indicate the weakest base?15

8

6

2​

Answers

Answer:

8

Explanation:

7 is neutral any anything above it is basic and anything below is acidic which means 8 would be the lowest base

Answer:

The pH of a weak base falls somewhere between 7 and 10.

Explanation:

Like weak acids, weak bases do not undergo complete dissociation; instead, their ionization is a two-way reaction with a definite equilibrium point

What would be considered more dilute? sweet tea or unsweetened tea

Answers

Answer:

Unsweetened tea

Explanation:

A concentrated solution is a solution that has more of the solute in it than the solvent (water).

A diluted solution is a solution that has more solvent (water) than the solute.

From the above we can say that the sweet tea contains more of the tea than water i.e it is concentrated hence, the taste is sweet. On the other hand, we can say that the unsweetened tea contains more water than the tea i.e it is diluted hence, the unsweetened taste.

Describe the range of radii of most atoms in nanometers (nm)

Answers

Final answer:

The range of radii of most atoms is typically in the nanometer scale (nm) and can be measured using the covalent radius. The size of an atom's nucleus is much smaller than the atom itself. The Bohr model provides a formula to calculate the radius of hydrogen-like atoms.

Explanation:

The range of radii of most atoms is typically in the nanometer scale (nm). The covalent radius, which is defined as half the distance between the nuclei of two identical atoms when they are joined by a covalent bond, provides a practical way to measure the size of atoms. As we move down a group in the periodic table, the covalent radius generally increases, indicating a larger size of the atom. For example, the covalent radius of the halogens increases as we move from fluorine to iodine.

The size of an atom's nucleus, on the other hand, is much smaller than the atom itself. The nucleus has a diameter of about 10-15 meters, while the typical atom has a diameter of the order of 10-10 meters. This difference in size illustrates the emptiness of atoms, with the distance from the nucleus to the electrons being typically 100,000 times the size of the nucleus.

The Bohr model provides a formula to calculate the radius of hydrogen-like atoms, which depends on the principal quantum number (n) and the atomic number (Z). The calculated radii of the orbits of the hydrogen atom have been experimentally verified to have a diameter of a hydrogen atom.

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Final answer:

The range of radii of most atoms is typically measured in nanometers (nm). Covalent radius and hydrogen-like orbits are two methods used to estimate the size of atoms. The size of an atom can vary depending on the element and measurement technique, but most atoms have radii on the order of nanometers (nm).

Explanation:

The range of radii of most atoms is typically measured in nanometers (nm). The size of an atom can be estimated using various techniques. One commonly used measure is the covalent radius, which is defined as one-half the distance between the nuclei of two identical atoms when they are joined by a covalent bond. The covalent radii of different elements can be found in tables and can vary depending on the element and its position in the periodic table.

Another way to estimate the size of atoms is by looking at the sizes of their orbits in hydrogen-like atoms. These orbits are given in terms of their radii by a mathematical expression that includes a constant called the Bohr radius, which is approximately 5.292 × 10-11 m.

Overall, the size of an atom can vary depending on the element and the specific measurement technique used, but most atoms have radii on the order of nanometers (nm).

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4.What volume of 0.120 M HNO3(aq) is needed to
completely neutralize 150.0 milliliters of 0.100 M
NaOH(aq)?
A. 62.5 mL
B. 125 ml
C.
180. mL
D. 360. mL

Answers

Answer:

B) 125 mL

Explanation:

M1V1=M2V2

(0.120M)(x)=(150.0 mL)(0.100M)

x= 125 mL

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1. In a hydrogen fuel cell, hydrogen gas and oxygen gas are combined to form water. (1) Write the balanced chemical equation describing this reaction using the lowest whole number coefficients. (2) Identify the oxidizing agent and reducing agent. (3) Determine the number of electrons transferred in the balanced chemical equation

Answers

Explanation:

Hydrogen + Oxygen --> Water

(1) Write the balanced chemical equation describing this reaction using the lowest whole number coefficients.

2H2(g) + O2(g) ---> 2H2O(g)

(2) Identify the oxidizing agent and reducing agent.

Oxidizing agent = O (There is decrease in oxidation number from 0 to -2)

Reducing agent = H (There is increase in oxidation number form 0 to  +1)

(3) Determine the number of electrons transferred in the balanced chemical equation

2H2(g) -->  4H+   + 4e- (4 hydrogen atom lost a single electron each)

O2 + 4e-  --> 2O2- (Two oxygen gain 2 electrons each)

Total number of electrons transferred in the balanced chemical equation is 4.