How do you calculate the initial speed given time and displacement?The question is: The longest kick in CFL history was 83.2m. If the ball remained in the air for 4.12s, determine its initial speed.
I calculated it several times and got the same answer, 40.38m/s, but the textbook says it's 28.6m/s.

Answers

Answer 1
Answer: Let's first find the velocity in the x-direction which is constant.
d = vt \n v = (d)/(t) \nv = (83.2m)/(4.12s) \n v= 20.2m/s

Now, we need the velocity in the y-direction
d = v_(o)t +  (1)/(2)a t^(2) \n d - (1)/(2)at^(2) = v_(o)t\nv_(o) = (0 - (1)/(2)(-9.81)(4.12)^(2))/(4.12)\nv_(o) = 20.2m/s

Finally, we need to put the two velocities together using pythagorean theorem
v_(t)^(2) = v_(x)^(2) + v_(y)^(2)
v_(t) =  \sqrt{20.2^(2) + 20.2^(2)}
v = 28.6m/s

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Answers

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Answers

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Answers

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Hope this helps!
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Answers

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Answers

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