The weights, in pounds, of the upper-class men offensive line players for a college are shown below: 322, 290, 321, 326, 330, 315, 311, 292, 290 What is the average, or mean, weight of the upper-class men offensive players? Provide your answer with 3 sig figs. -311 pounds -315 pounds -290 pounds -318 pounds

Answers

Answer 1
Answer:

Answer: 311 pounds

Step-by-step explanation:

To find the average, add up all of the values and divide by the amount of values.

First add up all of the values.

322+290+321+326+330+315+311+292+290 = 2797

Now count how many values there are and divide your previous sum by it.

2797/9 = 310.78

Because you need to have 3 sig figs, round to the nearest one.

310.78 rounds up to 311.

Answer 2
Answer:

answer-311

Step-by-step explanation:

322+290+321+326+330+315+311+292+290=2797

Count the number of values and divide by 2797

2797 divided by 9 =310.77777777777777

Nearest one-311


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Write and equation in standard form for a line that is (a) parallel (b) perpendicular to the line with an equation of y= 3x - 5 that passes through the point (5,8)

Answers

Answer:

  (a) 3x -y = 7

  (b) x +3y = 29

Step-by-step explanation:

(a) The standard form of the given line is ...

  3x -y = 5

The parallel line will have a constant on the right that makes it go through (5, 8), so it will be ...

  3x -y = 3(5) -(8)

  3x -y = 7

__

(b) The perpendicular line will have coefficients for x and y swapped and one of them negated. Again, the constant is chosen to make it go through (5, 8).

  x + 3y = (5) +3(8)

  x + 3y = 29

(a+b)(d+e) How many terms and factors in this expression? Please tell me specifically how many factors are there and how many terms are there. Please help!

Answers

I think there are 4 terms; a, b, d and e and two sets of factors; (a+b) and (d+e) because they are multiplied together, but I am not 100% sure.  

What is 6 ft = how many yards?

Answers

Well, yards are equal to 3 ft. This means that all you have to do is divide the number of feet you have by three, and that is the number of yards that it is equal to. So, 6 ft.=2 yards
pfft, ha. hes right >.<^^^

.

How to do improper fractions with 3.8 repeating

Answers

3.88888=3.88888/1=38.8888888

so lets ssay our repeating decimal = a fraction x
x=3.888 is true
multiply by 10
10x=38.8888
now subtract fir frist eqation from second
10x-x=38.8888-3.888888
9x=35
divide both sides by 9
x=35/9
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anser is 3.88=3 and 7/9

Solve the problem.If $13,000 is borrowed at 5.8% simple interest for 10 years, how much interest will be paid for the loan?​

Answers

Answer:

Interest =$7540

Step-by-step explanation:

p=$13000

r=5.8%

t=10yrs

i=p*r*t/100

=13000*5.8*10/1000

=130*58

= $7540

Answer asapA football team lost 9 yards on its first play. It then gained 9 yards on its second play.


Explain A. What expression can be written to represent how many yards the football team is from where it started? Explain your reasoning.

Explain B. How many yards is the football team from where it started?

Explain C. Suppose that, instead, the football team had gained 9 yards on its first play and lost 9 yards on its second play. Would the team’s position on the field have been any different than it actually was after the first two plays? Why or why not

Answers

for A:  Do -9+9.  It is negative because they LOST yards,  which means backwards momentum xDD
For B:  They are right where they started.  -9+9=0.  They lost 9,  then gained the 9 they had lost.
C:  It would not have been different.  No matter what way you add it,  it would have been the same thing.  Instead it would be 9-9,  which is still 0.  

Hope this helps!