MATHEMATICS HIGH SCHOOL

A car travels 32 km due north andthen 46 km in a direction 40° west of
north. Find the magnitude of the
car's resultant vector.

Answers

Answer 1
Answer:

Answer:

73.2km

Step-by-step explanation:

first you have to decompose 46 km into y and x components.

x=sin40°*46km

x=0.64*46km

x=29.44km

y=cos40°*46km

y=0.76*46km

y=34.96

now you add the y components together

32+34.96=66.98

finally use Pythagorean thereom to find the resultant vector.

a*a+ b*b=c*c

66.98*66.98+29.44*29.44=c*c

c*c= 4486.3+866.7

c=√5353

c=73.2 km this is the approximate value

Related Questions

There is a pizza cut into 8ths, if you eat 3/4 of it how much is left?
Blank divided by 9 equals 6
Which is a factor of x2 - 9x + 14?O X-9O X-2O x + 5O x + 7
3. Teesha is in french club. there are 19 students in the club. The french teacher will pick two students at random to guide visiting students from France. What is the probability that Teesha will not be picked up as a guide. A. 2/19 B. 17/19 C. 1/18D. 18/19
-18 - 14= whats the answer help

At noon the temperature was -4° C. Over the next two hours the temperature dropped another 11 degrees. Then every hour until 7:00 the temperature rose 3 degrees. What was the temperature at 7:00

Answers

I think it’s 0 degrees

Find the possible value or values of n in the quadratic equation 2n2 – 7n + 6 = 0.

Answers

2(n+7)(n-1)=0
because 7(-1) = -7 thats how you would get 7n and 7 - 1= 6 thats how you would get +6 and to be more specific it would be
n+7=0                       n-1=0
n=-7                          n= 1

Car rental company A charges $45 a day to rent a certain car. Car rental B charges $30 a day plus $0.20 per mile to rent a similar car. For how many miles is the cost at car rental Company B more than the cost at car rental company A?​

Answers

Answer is given below

Final answer:

The cost at car rental company B is more than the cost at car rental company A when the number of miles driven is greater than $15.

Explanation:

The cost at car rental company B is more than the cost at car rental company A when the number of miles driven is greater than $15.

To find this, you can set up an equation:

  • The cost at car rental company A is given by: $45 x d, where d represents the number of days.
  • The cost at car rental company B is given by: ($30 + $0.20m) x d, where m represents the number of miles driven.

So we need to find when ($30 + $0.20m) x d is greater than $45 x d.

($30 + $0.20m) x d > $45 x d

$30 + $0.20m > $45

$0.20m > $15

m > 75

Therefore, when the number of miles driven exceeds 75, the cost at car rental company B is more expensive.

Learn more about Car rental costs here:

brainly.com/question/34289654

#SPJ2

Prove that:{ \left( { e }^{ \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } } \right) }^{ \ln { \left( \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } \right) } }=1

Show your workings.

Answers

{ \left( { e }^{ \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } } \right) }^{ \ln { \left( \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } \right) } }=1\n{ \left( { e }^{ \sqrt { { e }^{ \ln { \left( \frac { 1 }{ 1} \right) } } } } \right) }^{ \ln { \left( \sqrt { { e }^{ \ln { \left( \frac { 1 }{1 } \right) } } } \right) } }=1\n
{ \left( { e }^{ \sqrt { { e }^( \ln 1 ) } } \right) }^{ \ln { \left( \sqrt { { e }^( \ln 1 ) } \right) } }=1\n{ \left( { e }^( \sqrt 1 ) \right) }^{ \ln { \left( \sqrt 1 \right) } }=1\n{ \left( { e }^ 1 \right) }^( \ln 1 )=1\n e ^( \ln 1 )=1\n1=1

Camp Elim obtains a $125,000, 6%, five-year loan for a new camp bus on January 1, 2021. If the monthly payment is $2,416.60, by how much will the carrying value decrease when the first payment is made on January 31, 2021?

Answers

Answer:

The loan amount is = $125000

Rate is = 6%

Term of the loan = 5 years or 60 months

EMI is = $2416.60

Now I have solved this using reducing method ans excel sheet. Please find attached the sheet.

So we can see that after 1st payment, the principle is left to $ 123,208.40  

The value decreases by : 125000-123208.40=1791.60

A construction manager needs 12 workers to complete a building project in 54 days. Find in terms of T the number of workers needed to complete the same project in T days

Answers

Answer:

2T/9

Step-by-step explanation:

A construction manager needs 12 workers to complete a building project in 54 days, we can write;

12 workers = 54 days

T find the number of workers needed to complete the same project in T days, we will write;

x workers = T days

Divide both equations

12/x = 54/T

Cross multiply

12T = 54x

x = 12T/54

x = 2T/9

Hence the number of workers needed to complete the same project in T days is 2T/9 workers
Other Questions
Change 43% into a decimal number
If you get $28 for washing 07 cars. How many dollars do you get for washing two cars?
Which of the following is not part of the converse of the triangle proportionality theorem?
Need help plz!!XY = -4