Multiply c^2(c^2-10c+25)
Answers
Step-by-step explanation:
c^2( c^2-10c+25)
=c^4 - 10c^3 + 25c^2
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(x - y)^2 + 4z(x - y) +3z^2 (and btw ^2 means squared and this is going for 10 points)
What is the slope of a line parallel to y = -5x + 2?
Mara's family is driving to her grandmothers' house. The family travels 239.4 miles be-tween the hours of 9:10 a.m. to 1:40 p.m. Write an equation that Mara can use to deter-mine their average rate of travel, rounded to the nearest mile per hour.Use the given numbers and operations to complete an equation.
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B.1/15
C.7/15
D.2/45
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B is the answer.
Hope i become the brainliest
Answers
u divide 15 by 50 the times it by 100 (if u were wondering how I did it)
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If = 8765432/9000000, then 0.8765432 = decimal
Answer:70/100
Step-By-Step:
Well you should simplify 70/100 which would be 7/10, so now that is a decimal and will move one step to the left which is 0.7 in decimal form
15abc^2 and 25a^3bc
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So GCF of 15 and 25 would be 5
GCF of a = a^1 or a
GCF of b = b^1 or b
GCF of c = c^1 or c
Put everything together to find the GCF.
GCF = 5abc.
Answers
is always a square.
343 = 7³
If the area is 343 m², then the rectangle with the smallest perimeter
is the square with sides of
√343 = (7)^ ¹·⁵ = 7 √7 meters
Final answer:
To find the dimensions of a rectangle with the smallest possible perimeter given an area of 343 m², we must determine the dimensions that will minimize the sum of the lengths of the four sides. The dimensions of the rectangle are 7 m by 49 m.
Explanation:
To find the dimensions of a rectangle with the smallest possible perimeter given an area of 343 m², we must determine the dimensions that will minimize the sum of the lengths of the four sides. Since the perimeter is the sum of the lengths of the opposite sides of a rectangle, we can rewrite the perimeter formula as P = 2l + 2w, where l represents the length and w represents the width.
Now, let's solve for the dimensions:
1. Start with the formula for the area of a rectangle: A = lw.
2. Substitute the given area: 343 = lw.
3. Rewrite the perimeter formula: P = 2l + 2w.
4. Express one variable in terms of the other using the area formula: l = 343/w.
5. Substitute the expression for l in the perimeter formula: P = 2(343/w) + 2w.
6. Simplify the equation: P = (686/w) + 2w.
7. To find the minimum perimeter, differentiate the equation with respect to w and set it equal to zero: 0 = (686/w²) + 2.
8. Solve the equation for w: (686/w²) + 2 = 0. Subtract 2 from both sides: 686/w² = -2. Multiply both sides by w²: 686 = -2w².
9. Divide both sides by -2: -343 = w². Take the square root of both sides (ignoring the positive value since the width cannot be negative): w = -√343 = -7.
10. Substitute the value of w back into the area formula: 343 = l(-7). Solve for l: 343 = -7l. Divide both sides by -7: l = 343/-7 = -49.
Since both dimensions cannot be negative, we ignore the negative values and take the absolute values of w and l: w = 7 and l = 49.
Therefore, the dimensions of the rectangle with an area of 343 m² and the smallest possible perimeter are 7 m by 49 m.
Learn more about Dimensions of a rectangle here:
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how do i solve this.
Answers
(-8)^3=-8 times -8 times -8=-512
2^3=8
-512/8=-64
the other way that you are supposed to do it is
factor
-8=-1 times 2^3
(-8)^3=-1 times (2^3)^3=-1 times 2^9
when dividing exponents, subtract
put the -1 to the side
(-1/1) times (2^9)/(2^3)=(-1/1) times 2^(9-3)=(-1/1) times 2^6=-1 times 64=-64