Answer:
3.79 g of N2.
Explanation:
We'll begin by writing the balanced equation for the reaction.
This is given below:
4NH3 + 3O2 → 2N2 + 6H2O
Next, we shall determine the mass of O2 that reacted and the mass of N2 produced from the balanced equation.
This is illustrated below:
Molar mass of O2 = 16x2 = 32 g/mol
Mass of O2 from the balanced equation = 3 x 32 = 96 g
Molar mass of N2 = 2x14 = 28 g/mol
Mass of N2 from the balanced equation = 2 x 28 = 56 g
Summary:
From the balanced equation above,
96 g of O2 reacted to produce 56 g of N2.
Finally, we shall determine the mass of N2 produced by reacting 6.50 g of O2.
This can be obtained as follow:
From the balanced equation above,
96 g of O2 reacted to produce 56 g of N2.
Therefore, 6.50 g of O2 will react to produce = (6.50 x 56)/96 = 3.79 g of N2.
Therefore, 3.79 g of N2 were obtained from the reaction..
Answer:
Mg has two valence electrons
Explanation:
Na has only one valence electron, so it readily donates that electron to other atoms to achieve an octet.
Mg must lose two valence electrons to get an octet. It takes extra energy to remove the second electron. In addition, the two electrons are in a filled s subshell, which has added stability.
B.meiosis
C.photosynthesis
D.mitosis
Answer:
The correct answer is A.respiration
Explanation:
Cellular respiration is a process which produces ATP (adenosine triphosphate) and methabolites. ATP is an "energy coin" which provides energy for biochemical processes in all cells. The other options are not correct: meiosis is the division process of sexual cells, mitosis is the division process of somatic cells and photosynthesis ocurrs in plant cells to obtain energy (not in animal cells of muscle tissue).
B. Killing cancerous cells
C. The transmutation of hydrogen into helium
D. Detecting art forgeries
Detecting art forgeries is one common use of neutron activation analysis. Hence, option D is correct.
NAA is a non-destructive analytical technique that can be used to determine the elemental composition of a sample.
It is particularly useful for the analysis of trace elements, as it is highly sensitive and can detect even very small amounts of elements.
In the field of art conservation, NAA is used to analyze the composition of pigments and other materials used in artworks, which can help to authenticate or identify forgeries.
Neutron activation analysis is a highly versatile and powerful analytical technique that can provide valuable insights into the elemental composition of a wide range of samples. Its sensitivity and accuracy make it an important tool in many scientific fields, including art conservation.
Thus, option D is correct.
To learn more about the neutron activation analysis, follow the link:
#SPJ3
The correct label for a solution is; a homogeneous mixture. Option A is correct.
A solution is a type of homogeneous mixture. A homogeneous mixture is one in which the components are uniformly distributed and evenly mixed at a molecular or atomic level. In other words, all parts of the mixture are the same throughout, and there are no visible boundaries or distinct phases between the different components.
In a solution, one or more substances, called solutes, are dissolved in a solvent. The solute(s) become uniformly dispersed at the molecular or atomic level within the solvent, creating a single phase with consistent properties. This even distribution is achieved through the interactions between the solute particles and the solvent particles.
Examples of solutions include;
Saltwater: Sodium chloride (salt) is dissolved in water (solvent) to create a homogeneous solution.
Sugar water: Sucrose (sugar) is dissolved in water to form a homogeneous mixture.
Solutions are essential in various applications, such as in chemistry, biology, medicine, and everyday life. They are commonly encountered and used for various purposes, including in cooking, pharmaceuticals, cleaning agents, and many industrial processes.
Hence, A. is the correct option.
To know more about homogeneous mixture here
#SPJ6
• The solubility of Solute ___ increases the most as temperature increases.
• The solubility of Solutes C and D is the same at __°C.
• As the temperature increases from 0 to 100, the solubility only changes by about __ grams for Solute B.
Answer:
Decreases
E
20
5
Explanation:
Answer:
Decreases
E
20
5
Explanation: