Answer:
The least number of days that will pass before Andy will have to do both chores together on the same days are 5 days.
Step-by-step explanation:
Let us start from the initial day.
Every 2 days Andy takes out the trash.
So, the days he takes out trash are second day, fourth day, sixth day , eighth day , tenth day and so on.. (1)
Every 3 days Andy sweeps the kitchen.
So, the days he sweeps the kitchen are third day, sixth day , ninth day , twelfth day and so on.. (2)
Now, on comparing both equations (1) and (2) we see the first common day to both the chores is SIXTH DAY.
Hence, the least number of days that will pass before Andy will have to do both chores together on the same days are 5 days.
Answer:
The answer in the procedure
Step-by-step explanation:
The numbers are
Compare the numbers with
a) we know that
-----> the number is less than
b) we know that
-----> the number is equal to
c) we know that
-----> the number is greater than
As suggested, we have to use the law of sines: it states that the ratio between a side and the sine of the opposite angle is constant in every triangle.
We know that one side length is 11, and the opposite angle is 27°
Another side length is 15, and the opposite angle is x.
So, the law of sines states that
Solving for we have
Which implies
Put this into a calculator to get
Answer:
x ≈ 28.2
Step-by-step explanation:
Using the sine rule then
= ( cross- multiply )
11sinx = 15sin27° ( divide both sides by 11 )
sin x = ≈ 0.61907..
x = (0.61907 ) ≈ 28.2