Answer:
A bricklaying job
Explanation:
To start with an acute strain is a type of inury that occurs when heavy objects are improperly lifted an individual in ways that the person's muscles becomes overstressed.
There are a number of jobs that are likely to cause acute strain including bricklaying jobs. People engaged in bricklaying jobs tend to improperly lift heavy objects, an activity that leads to repititive and prolonged overuse of muscles and tendons which is known as acute strain.
Another example of a job that can lead to acute strain is furniture moving.
Answer:
true
Explanation:
true
Answer:
The mass of the second weight is approximately 0.477 kg
Explanation:
The given parameters are;
The acceleration experienced by the two weights = 3.8 m/s²
The mass of the first weight = 1.08 kg
The formula for the acceleration, a, of weights attached to a friction pulley, is given as follows;
Where;
a = The common acceleration of the two weights
g = The acceleration due to gravity = 9.81 m/s²
M = The mass of the first weight = 1.08 kg
m = The mass of the second weight
Therefore, we have;
The mass of the second weight = m ≈ 0.477 kg
The mass of the second weight ≈ 0.477 kg.
Answer:
1. Evaporation: The water evaporates from the water bodies like seas and oceans.
Transpiration: The water evaporates from the plant's leaves.
2. Condensation: The evaporated water condenses to liquid droplets which to form clouds.
3. precipitation: When the cloud becomes heavy, water rains down. This is known as precipitation.
The water rains down in rivers and seas and oceans. From rivers, it runs off back into the seas.
D = distance between the cars at the start of time = 680 km
v₁ = speed of one car
v₂ = speed of other car = v₁ - 10
t = time taken to meet = 4 h
distance traveled by one car in time "t" + distance traveled by other car in time "t" = D
v₁ t + v₂ t = D
(v₁ + v₂) t = D
inserting the values
(v₁ + v₁ - 10) (4) = 680
v₁ = 90 km/h
rate of slower car is given as
v₂ = v₁ - 10
v₂ = 90 - 10 = 80 km/h
The slower car travels at 75 km/hr while the faster car travels at 85 km/hr. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.
The subject of this question is algebra - specifically involving rates of speed and time. Here's how you would find the answer:
The result would be 75 km/hr for the slower car and 85 km/hr for the faster car. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.
#SPJ12
Answer:
A.) 3.975 m/s
B.) 0.925 m/s
Explanation:
Given that a person walks first at a constant speed of 4.90 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.05 m/s.
A) What is her average speed over the entire trip?
The average speed = (4.90 + 3.05)/2
Average speed = 7.95/2
Average speed = 3.975 m/s
B) What is her average velocity over the entire trip?
Since velocity is a vector quantity, that is, we consider both the magnitude and direction
Average velocity = ( 4.90 - 3.05)/2
Average velocity = 1.85/2
Average velocity = 0.925 m/s