A doctor diagnoses a man with an acute strain. Which job is most likely to cause an acute strain?

Answers

Answer 1
Answer:

Answer:

A bricklaying job

Explanation:

To start with an acute strain is a type of inury that occurs when heavy objects are improperly lifted an individual in ways that the person's muscles becomes overstressed.

There are a number of jobs that are likely to cause acute strain including bricklaying jobs. People engaged in bricklaying jobs tend to improperly lift heavy objects, an activity that leads to repititive and prolonged overuse of muscles and tendons which is known as acute strain.

Another example of a job that can lead to acute strain is furniture moving.


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Astronauts in orbit are not truly weightless. Please select the best answer from the choices provided T F

Answers

That's true. There's plenty of gravity in Earth orbit, and things have plenty of weight there.

Answer:

true

Explanation:

true

An ultra-low friction pulley deal is as shown. The two weights experience an acceleration of 3.8m/s2. The first weight has 1.08kg. Find the mass of the second weight

Answers

Answer:

The mass of the second weight is approximately 0.477 kg

Explanation:

The given parameters are;

The acceleration experienced by the two weights = 3.8 m/s²

The mass of the first weight = 1.08 kg

The formula for the acceleration, a, of weights attached to a friction pulley, is given as follows;

a = (g \cdot (M - m))/(M + m)

Where;

a = The common acceleration of the two weights

g = The acceleration due to gravity = 9.81 m/s²

M = The mass of the first weight = 1.08 kg

m = The mass of the second weight

Therefore, we have;

m = (M\cdot (g -a ))/(g + a) = (1.08* (9.81 -3.8 ))/(9.81 + 3.8) \approx 0.477

The mass of the second weight = m ≈ 0.477 kg

The mass of the second weight ≈ 0.477 kg.

Which is the correct order of events in the water cycle?

Answers

Answer:

1. Evaporation: The water evaporates from the water  bodies like seas and oceans.

Transpiration: The water evaporates from the plant's leaves.

2. Condensation: The evaporated water condenses to liquid droplets which to form clouds.

3. precipitation: When the cloud becomes heavy, water rains down. This is known as precipitation.

The water rains down in rivers and seas and oceans. From rivers, it runs off back into the seas.

Evaporation, Transpiration, Condensation , Precipitation Absorption, Infiltration, Ground water, and then runoff 

Two cars leave towns 680 kilometers apart at the same time and travel toward each other. one car's rate is 10 kilometers per hour less than the other's. if they meet in 4 hours, what is the rate of the slower car?

Answers

D = distance between the cars at the start of time = 680 km

v₁ = speed of one car

v₂ = speed of other car = v₁ - 10

t = time taken to meet = 4 h

distance traveled by one car in time "t" + distance traveled by other car in time "t" = D

v₁ t + v₂ t = D

(v₁ + v₂) t = D

inserting the values

(v₁ + v₁ - 10) (4) = 680

v₁ = 90 km/h

rate of slower car is given as

v₂ = v₁ - 10

v₂ = 90 - 10 = 80 km/h

Final answer:

The slower car travels at 75 km/hr while the faster car travels at 85 km/hr. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.

Explanation:

The subject of this question is algebra - specifically involving rates of speed and time. Here's how you would find the answer:

  1. Begin by understanding that it is not two separate trips but merely one trip where they are traveling towards each other. This means collectively they've traveled 680 kilometers.
  2. Denote the slower car's rate as 'r'. The faster car would then have a rate of 'r + 10' km/hr.
  3. Since they are traveling towards each other for the same duration, you can set up the formula 'distance = rate * time' for BOTH cars, i.e.:
    4r (slower car's distance covered) + 4(r + 10) (faster car's distance covered) = 680km.
  4. Solve the equation for 'r'.

The result would be 75 km/hr for the slower car and 85 km/hr for the faster car. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.

Learn more about Algebra here:

brainly.com/question/24875240

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A person walks first at a constant speed of 4.90 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.05 m/s.A) What is her average speed over the entire trip?B) What is her average velocity over the entire trip?

Answers

Answer:

A.) 3.975 m/s

B.) 0.925 m/s

Explanation:

Given that a person walks first at a constant speed of 4.90 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.05 m/s.

A) What is her average speed over the entire trip?

The average speed = (4.90 + 3.05)/2

Average speed = 7.95/2

Average speed = 3.975 m/s

B) What is her average velocity over the entire trip?

Since velocity is a vector quantity, that is, we consider both the magnitude and direction

Average velocity = ( 4.90 - 3.05)/2

Average velocity = 1.85/2

Average velocity = 0.925 m/s

Which is larger? 1 L or 1 m ³

Answers

1 m^3 =1000 L
1 L = 0.001 m^3

So 1m^3 is larger