Answer:
D.
Explanation:
Based on the information provided surrounding this scenario, it can be said that the most likely next course of action would be to create an alternate user ID to maintain persistent access. This would allow the attacker to have continuous access into the network in the case that the system administrators detect that the operator's user ID and password have been compromised. Thus also giving the attacker ample time to infiltrate and find vulnerabilities in the network through an alternate hidden user ID.
B. -2
C. "Open"
D. +2
Answer:
D. +2
Explanation:
The given function is an IF function where the first argument is a logical test, the second argument is the result if the logical test is true and the third argument is the result if the logical test is false. Depending on whether the result of the logical test is true or false, the respective value will be returned.
IF(logical_test, value_if_true, value_if_false)
In this case, the logical test first compares the value of B3 and D5. As B3 is not greater than D5, the result is false and the value for false will be returned. The value for false result of the logical test is equated by D5-B3 which is equal to 2. Thus the result of the IF function is +2.
Internet Protocol (IP) are guideline about how data should be sent across the internet.
Internet Protocol (IP) work hand in hand with packet as they are connected to every packet which therefore means that any internet users who connect to the internet will be allocated with a unique Internet Protocol (IP) address.
This Internet Protocol (IP) address will enables the user devices to connect and communicate across the internet with ease once the packets are connected to the each Internet Protocol (IP) address allocated to them.
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(2) Complete the GetNumOfCharacters() function, which returns the number of characters in the user's string. Use a for loop in this function for practice. (2 pts)
(3) In main(), call the GetNumOfCharacters() function and then output the returned result. (1 pt) (4) Implement the OutputWithoutWhitespace() function. OutputWithoutWhitespace() outputs the string's characters except for whitespace (spaces, tabs). Note: A tab is '\t'. Call the OutputWithoutWhitespace() function in main(). (2 pts)
Ex: Enter a sentence or phrase: The only thing we have to fear is fear itself. You entered: The only thing we have to fear is fear itself. Number of characters: 46 String with no whitespace: The only thing we have to fear is fear itself.
Answer:
See solution below
See comments for explanations
Explanation:
import java.util.*;
class Main {
public static void main(String[] args) {
//PrompT the User to enter a String
System.out.println("Enter a sentence or phrase: ");
//Receiving the string entered with the Scanner Object
Scanner input = new Scanner (System.in);
String string_input = input.nextLine();
//Print out string entered by user
System.out.println("You entered: "+string_input);
//Call the first method (GetNumOfCharacters)
System.out.println("Number of characters: "+ GetNumOfCharacters(string_input));
//Call the second method (OutputWithoutWhitespace)
System.out.println("String with no whitespace: "+OutputWithoutWhitespace(string_input));
}
//Create the method GetNumOfCharacters
public static int GetNumOfCharacters (String word) {
//Variable to hold number of characters
int noOfCharactersCount = 0;
//Use a for loop to iterate the entire string
for(int i = 0; i< word.length(); i++){
//Increase th number of characters each time
noOfCharactersCount++;
}
return noOfCharactersCount;
}
//Creating the OutputWithoutWhitespace() method
//This method will remove all tabs and spaces from the original string
public static String OutputWithoutWhitespace(String word){
//Use the replaceAll all method of strings to replace all whitespaces
String stringWithoutWhiteSpace = word.replaceAll(" ","");
return stringWithoutWhiteSpace;
}
}
screen.
O Your app is functioning and ready to test.
O You have defined a use case.
O In this step, you defined your target audience and main goal.
The statements that are true about this step are:
A mobile application, sometimes known as an app, is a computer program or software application that is meant to operate on a mobile device, such as a phone, tablet, or watch.
An app is a software program that allows users to do certain functions on their mobile or desktop device. Apps are either pre-installed on your device or downloaded through a specialized app store, such as the Apple App Store. Apps are usually created in a variety of programming languages.
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They make it easier for computers to connect to one another. WANs provide more options for communication than LAN networks, which are more constrained and limited in scope.
A local area network, or LAN, is a network of computers created within a restricted area, like a home, business, or group of buildings. On the other hand, a wide-area network (WAN) is a computer network that spans a large geographic area. Users can transport data more quickly across LANs than they can via WANs, which have a significantly slower data transmission rate.
LANs are straightforward networks that are used to link computers and other gadgets in a constrained space, such as a home, business, or campus. WLANs are entirely wireless in comparison to traditional LANs, which connect the devices using Ethernet cables. WLANs
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Answer:
Following are the program in c++ language
#include<iostream> // header file
using namespace std; // namespace
int main()
{
int n1,i; // variable declaration
cout<<"Enter Number: ";
cin>>n1; // input number
for(i=n1;i>1;i=i-2) // check the condition
{
n1 = n1-2; // decrement the value of number by -2
}
if(n1==0) // check if it is 0
cout<<"number is EVEN"<<"\n"; // print even
else
cout<<"number is ODD"<<"\n"; // print odd
return 0;
}
Output:
Enter Number: 45
number is ODD
Again run the program
Enter Number:10
number is EVEN
Explanation:
In this program, we input the number by a user in variable n1. After that, we iterate the for loop and initialize the value of a variable" i" in for loop and check the condition.
In each iteration, the variable n1 is decrement by 2 and store it n1.
Finally, check if n1==0 then it print number is EVEN otherwise it print number is ODD.