A binomial experiment consists of 16 trials. The probability of success on trial 9 is 0.48. What is the probability of success on trial 13?

Answers

Answer 1

Answer:

Answer:

p = 0.48

Step-by-step explanation:

A binomial experiment is and experiment with n trials, every trial is identical and independent and every trial has the same probability p of success and 1-p of fail.

Then, we have a binomial experiment of 16 trials. it means that every trial has the same conditions. So, if the probability of success on trial 9 is 0.48, the probability of success on trial 13 is also 0.48.

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The image of a parabolic lens is traced onto a graph. The function f(x) = 1/4 (x+8)(x-4) represents the image. Atwhich points does the image cross the x-axis?

O (-8, 0) and (4,0)
(8,0) and (-4, 0)
O (2, 0) and (-1,0)
O (-2, 0) and (1, 0)

Answers

The image of the parabolic lens crosses the x axis at the points

(-8, 0) and (4, 0)

How to find the points where the image cross x axis

To find the points where the graph of the function crosses the x axis we need to find the values of x that make f(x) equal to zero

hence we have that

f(x) = 1/4 (x + 8) (x - 4)

0 = 1/4 (x + 8) (x - 4)

x + 8 = 0

x = -8

x - 4 = 0

x = 4

hence we can say that the image of the parabolic lens crosses the x axis at the points (-8, 0) and (4, 0)

Learn more about parabolic lens at

brainly.com/question/24079297

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Toy company produces rubber balls that have a radius of 1.7 cm.A sphere has a radius of 1.7 centimeters.
What is the volume of one rubber ball? Round to the nearest hundredth of a centimeter.

Answers

Answer:

The volume of one rubber ball is 20.58 cubic centimeters.

Step-by-step explanation:

The rubber ball has a spheric format.

A sphere with radius r has volume given by the following equation:

$V = (4\pi r^(3))/(3)$

In this question:

r = 1.7 cm.

The radius is in centimeters, so the volume will be in cubic centimeters.

What is the volume of one rubber ball?

$V = (4*\pi*(1.7)^(3))/(3) = 20.58$

The volume of one rubber ball is 20.58 cubic centimeters.

Answer:

1) 20.58 cm

2) $0.09

3) $0.41

Step-by-step explanation:

You have $1000 to invest in two different accounts. To save the money you need for college, you need to average 5.7 percent interest. If the two accounts pay 4 percent and 6 percent interest, how much should you invest in each account?$550 in 4%, $450 in 6%
$300 in 4%, $700 in 6%
$700 in 4%, $300 in 6%
$150 in 4%, $850 in 6%

Answers

9514 1404 393

Answer:

$150 in 4%, $850 in 6%

Step-by-step explanation:

The fraction that must earn the highest rate is ...

(5.7 -4.0)/(6.0 -4.0) = 1.7/2 = 0.85

That is 0.85 × $1000 = $850 must be invested at 6%. Matches the last choice.

_____

If you let x represent the amount that must earn 6%, then the total interest earned must be ...

x·6% +(1000 -x)·4% = 1000·5.7%

x(6 -4) = 1000(5.7 -4) . . . . . . multiply by 100, subtract 4·1000

x = 1000·(5.7 -4)/(6 -4) = 850 . . . . as above

I will really appreciate the help because i’m stuck and need this as soon as possible This problem uses the notion that to find the closest distance from a point to a line we need the perpendicular line joining them. The idea is that the plane is heading in some direction, if we treat the takeoff point as the origin (0,0), we can make an equation of a line to the destination. Then we need to take the slope of that line, find its negative reciprocal to build a perpendicular slope, and then use that new perpendicular slope and the point where the mountain is to make a NEW line. Then we find the intersection of these two lines, a system of equations, (preferably by an algebraic process like substitution or elimination) to find the time at which the plane will be closest to the mountain on its path toward its destination.

the problem:

You're flying from Joint Base Lewis-McChord (JBLM) to an undisclosed location 245 km south and 237 km east. Mt. Rainier is located approximately 56 km east and 40 km south of JBLM. If you are flying at a constant speed of 800km / hr how long after you depart JBLM will you be the closest to Mt. Rainier?

______minutes