A group of students must collect at least $160 to organize a science fair. They have already collected $20. Which graph best represents the possible amounts of money the students still need to collect? (1 point) Number line graph with closed circle on 160 and shading to the right. Number line graph with closed circle on 140 and shading to the right. Number line graph with closed circle on 20 and shading to the right Number line graph with closed circle on 180 and shading to the right.

Answers

Answer 1

Answer:

Answer:

Number line graph with closed circle on 20 and shading to the right or c

Step-by-step explanation:

This is the best answer because you start of at 20 dollars and need to continue collecting money till you have 160 dollars.

Answer 2

Answer:

Answer:

The 3rd one

Step-by-step explanation:

You have already collected $20. You need at least $160, but having even more money would be great. You need $160, but any number to the right of 160 would be even better as your goal.

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Marcy has 567 earmuffs in stock if she can put 18 earmuffs on each shelf how many shelves does she need for all of the earmuffs I also need to estimate the whole problem

Answers

She's going to need about 30.

Estimate 34.
567 divide 18 =31.5
therefore she needs 32 shelves to stock all the earmuffs.

Your hot air balloon is rising at the rate of 4 feet per second. Another aircraft nearby is at 7452 feet and is losing altitude at the rate of 30 feet per second. In how many seconds will your hot air balloon be at the same altitude as the other aircraft?

Answers

Answer:

$219.2\ sec$

Step-by-step explanation:

Let

y ----> the altitude in feet

x ----> the time in seconds

we know that

The linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope ot unit rate

b is the y-intercept or initial value

In this problem we have

Your hot air balloon

The slope is equal to $m=4\ (ft)/(sec)$

The y-intercept is $b=0$ ---> represent a proportional relationship

The linear equation is

$y=4x$ ----> equation B

Another aircraft

The slope is equal to $m=-30\ (ft)/(sec)$ ---> is negative because is a decreasing function

The y-intercept is $b=7,452\ ft$

The linear equation is

$y=-30x+7,452$ ----> equation B

Equate equation A and equation B

$4x=-30x+7,452$

solve for x

Adds 30x both sides

$4x+30x=7,452$

$34x=7,452$

Divide by 34 both sides

$x=219.2\ sec$

Please anyone help me on this question

Answers

Answer:

a) 60

b) 0.24

c) 150

Step-by-step explanation:

a) P(green) = ⅕

Expected no. = 300 × ⅕

= 60

b) total = 300

P(purple) = 72/300

= 6/25 = 0.24

c) P(blue) = 45/300

= 3/20 = 0.15

Expected no.: 1000 × 0.15

= 150

If someone could help me with this problem it'd be very much appreciated!! *sorry for the quality btw

Answers

Okay, lets write down what we do know...

4 out of the 12 cups are decaf, so the odds of selecting a decaf cup by random is 4/12 or 1/3

Alternatively 8 of the 12 cups are caffeinated, so the odds of selecting a caffeinated cup by random is 8/12 or 2/3

P(decaf)=1/3
P(caf)=2/3

But those odds are only for the first cup picked. The second cup has 4 probabilities...

1. Picking a decaf cup for the second time

2. Picking a decaf cup for the first time

3. Picking a caf cup for the second time

4. Picking a caf cup for the first time

So lets find the probability of each event...

1. Picking a decaf cup for the second time. If a decaf cup has already been picked, then the odds of drawing another one is 3/11

2. Picking a decaf cup for the first time. If a decaf cup hasn't already been picked, then the odds of drawing one is 4/11

3. Picking a caf cup for the second time. If a caf cup has already been picked, then the odds of drawing one is 7/11

4. Picking a caf cup for the first time. If a car cup hasn't already been picked, then the odds of drawing one is 8/11.

Okay, so now we can solve for the various possibilities.

1. Picking a decaf cup for the second time
1/3*3/11=3/33

2. Picking a decaf cup for the first time
2/3*4/11=8/33

3. Picking a caf cup for the second time
2/3*7/11=14/33

4. Picking a caf cup for the first time
2/3*8/11=16/33

Both cups were caffeinated, so neither were decaf.

Answer= Neither cup is decaf.

What is the next number in this pattern?4,16,64,256,_

A 260
B 448
C 504
D 1024