If I have a cylinder, the radius is 9.3 ft and the height is y, the volume of the whole thing is 3000ft, then what does y equal?
Answers
Answer:
Step-by-step explanation:
r = 9.3 ft
h = y ft
Volume = 3000 ft
πr²h = 3000
3.14 * 9.3 *9.3 * y = 3000
y = 11.05 ft
Related Questions
1. The midpoint of the segment joining points (a, b) and ( j, k) is: a. (j-a,k-b) b. ((j-a)/2,(k-b)/2) c. (j+a,k+b) d. ((j+a)/2,(k+b)/2)2. Point T is the midpoint of JH . The coordinate of T is (0, 4) and the coordinate of J is (0, 2). The coordinate of H is: a.(0, 6) b.(0, 3) c.(0, 7) d.(0, 11) 3. What about this one Point (-4, 3) lies in Quadrant a.I b.II c.III d.IV 4. Point (6, 0) lies on the. a.x-axis b.y-axis c.line y = x 5. Any line with no slope is parallel to the a.x-axis b.y-axis c.line y = x 7. If the point (a,3) lies on the graph of the equation 5x + y = 8, then a= a.1 b.-1 c.-7 8. If the equation of a circle is (x + 5)^2 + (y - 7)^2 = 36, its center point is a.(5, 7) b.(-5, 7) c.(5, -7) 9. If the equation of a circle is (x + 5)^2 + (y - 7)^2 = 36, its radius is a.6 b.16 c.36 10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6). True or False.
Solve Mathematics question. Photo
Ryan buys a 2 kilogram bag of trail mix for a hike. He wants to make 5- ounce bags to share with his hiking friends. There are approximately 35 ounces in 1 kilograms. How many 5- ounces bags can Ryan make
Three years ago,Joe brought $750 worth of stock in the software company. Since then the value of his purchase has been increasing at the average rate of 12 1/5 % per year. How much is the stock worth now?
(ii) Prove that, Cos^2A + Cos^2B-Cos^2C = 1-2SinA.SinB.Cos.C
(iii) Prove that, CosA+CosB-CosC = -1+4CosA/2. CosB/2.SinC/2
Answers
A+B+C = pi
B+C = pi-A
sin(B+C) = sin(pi-A)
sin(B)cos(C)+cos(B)sin(C) = sin(pi)cos(A)-cos(pi)sin(A)
sin(B)cos(C)+cos(B)sin(C) = sin(A)
sin(B)cos(C) - sin(A) = -cos(B)sin(C)
(sin(B)cos(C) - sin(A))^2 = (-cos(B)sin(C))^2
sin^2(B)cos^2(C) + sin^2(A) - 2sin(A)sin(B)cos(C) = cos^2(B)sin^2(C)
-2sin(A)sin(B)cos(C) = cos^2(B)sin^2(C) - sin^2(B)cos^2(C) - sin^2(A)
(ii)
cos^2(A) + cos^2(B) - cos^2(C) = 1-2*sin(A)*sin(B)*cos(C)
cos^2(A) + cos^2(B) - cos^2(C) = 1+cos^2(B)sin^2(C) - sin^2(B)cos^2(C) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(cos^2(B)sin^2(C) - sin^2(B)cos^2(C)) - sin^2(A)cos^2(A) + cos^2(B) - cos^2(C) = 1+((cos(B)sin(C))^2 - (sin(B)cos(C))^2) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(cos(B)sin(C)-sin(B)cos(C))(cos(B)sin(C)+sin(B)cos(C)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(sin(C)cos(B)-cos(C)sin(B))(sin(C)cos(B)+cos(C)sin(B)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+sin(C-B)sin(C+B) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(1/2)*(cos(2B)-cos(2C)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(1/2)*(2cos^2(B)-1-(2cos^2(C)-1)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(1/2)*(2cos^2(B)-1-2cos^2(C)+1) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+(1/2)*(2cos^2(B)-2cos^2(C)) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1+cos^2(B)-cos^2(C) - sin^2(A)
cos^2(A) + cos^2(B) - cos^2(C) = 1 - sin^2(A) + cos^2(B) - cos^2(C)
cos^2(A) + cos^2(B) - cos^2(C) = cos^2(A) + cos^2(B) - cos^2(C)
Answers
Answers
2. y = -3
Answers
Answer:
1. x=6
2. y=2
Step-by-step explanation:
If x=5, the line is vertical, so we need a vertical line so that we are parallel. A vertical line is x= a constant
We can choose the value for x as long as it is not 5, that would make it the same line. I will choose x=6
If y=-3=5, the line is horizontal, so we need a horizontal line so that we are parallel. A horizontal line is y= constant
We can choose the value for y as long as it is not -3, that would make it the same line. I will choose y=2
(1,2), (-3,2)
Answers
2-2 over -3-1
= 0 over -4
your slope is 0
Triangle with two angles labeled