3What is the y-coordinate of the point that divides the
directed line segment from J to k into a ratio of 5:1?
2
AK (7.2)
1
y =
m
m+
-)(x2 - wa) + v
2 3 4 5 6 7 8 9 10 11 x
-11
-2
-3
-4
-5
-8
0-5
0 0
O 6
ibd
-10
J (1,-10)

Answers

Answer 1
Answer:

The y coordinate of the point that divides J to K in the ratio 5 : 1 is 0.

Distance

If a point O(x, y) divides the line segment AB with end points A(x₁, y₁) and B(x₂, y₂) in the ratio n:m, the coordinate of O is:

x=(n)/(n+m) (x_2-x_1)+x_1\n\ny=(n)/(n+m) (y_2-y_1)+y_1

Let O(x, y) represent the point dividing J to K in the ratio 5 : 1. K(7,2) and J(1, -10)Hence:

y=(5)/(5+1)(2-(-10)) + (-10)=0

The y coordinate of the point that divides J to K in the ratio 5 : 1 is 0.

Find out more on Distance at: brainly.com/question/17273444

Answer 2
Answer:

Answer:

0

Step-by-step explanation:

Given the points J (1,-10) and K (7, 2)

From the section formula

(x,y)=\left((mx_2+nx_1)/(m+n), (my_2+ny_1)/(m+n)\right)

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is obtained using the formula:

y=(my_2+ny_1)/(m+n)\nm=5, n=1, y_1=-10, y_2=2\nTherefore:\ny=(5*2+1*-10)/(5+1)\n=(10-10)/(6)\n=0

The y-coordinates of the point that divides the directed line segment from J to K into a ratio of 5:1 is 0.


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Answers

The sum of y and g is

y+g

5 less than this is

y+g-5

Which equations are equal to 1/4 (8x+56) =20

Answers

Following are the calculation to the given equation:

Given:

\to (1)/(4)(8x+56)=20

To find:

x=?

Solution:

\to (1)/(4)(8x+56)=20\n\n\to (8x)/(4) + (56)/(4)=20\n\n\to 2x + 14=20\n\n\to 2x = 20-14\n\n\to 2x= 6\n\n\to x=(6)/(2)\n\n\to x= 3

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2x+14=20

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Sybrina jogged 2 miles in 30 minutes. At this rate, how far would she jog in 90 minutes?At what rate did she jog each hour?

Answers

6 miles in 90 minutes and 4 miles per hour. 30 times two is 60 min so 2 miles times two is 4 miles. 

another 30 min is 90 min and another two miles is 6 miles.
2miles per 30min - 2 to 3
90/30=3x2=6
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She was jogging @ a 1mile per 15min but each hour it was 4mile per hour

Relationship B has a greater rate than Relationship A. The graph represents Relationship A.Which equations could represent Relationship B?

Choose all answers that are correct.
A. y = 3/4x

B. y = 0.6x

C. y = 2/3x

D. y = 1/4x

Help Meh

Answers

we know that

The rate of the Relationship is the slope of the function

so

Find the slope of the Relationship A

the slope is equal to

m=((y2-y1))/((x2-x1))

we have the points

(4,2)\ and\ (8,4)

Substitute in the formula above to find the slope

m=((4-2))/((8-4))

m=(2)/(4)=0.5

Compare the value of the rate of the Relationship A with each case

case a)

y = (3/4)x

In this case the rate of the equation is equal to (3)/(4)

Compare with the rate of the Relationship A

(3)/(4)>(2)/(4)

therefore

y = (3/4)x -----> This equation could represent Relationship B

case b)

y = (0.6)x

In this case the rate of the equation is equal to 0.6

Compare with the rate of the Relationship A

0.6 > (2)/(4)

0.6 > 0.5

therefore

y = (0.6)x -----> This equation could represent Relationship B

case c)

y = (2/3)x

In this case the rate of the equation is equal to (2/3)

Compare with the rate of the Relationship A

(2)/(3) >(2)/(4)

Multiply by 12 both sides

8 > 6

therefore

y = (2/3)x -----> This equation could represent Relationship B

case d)

y = (1/4)x

In this case the rate of the equation is equal to (1/4)

Compare with the rate of the Relationship A

(1)/(4) <(2)/(4)

therefore

y = (1/4)x -----> This equation could not represent Relationship B

therefore

the answer is

y = (3/4)x

y = (0.6)x

y = (2/3)x

Answer:

A,B,and C

I took the test but if you want a Step-by-step explanation comment below!

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Answers

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Where 60 is the Saturday class, 45a are the 45 minute weekday classes times a amount of classes and 285 is the total amount of minutes.

Also, here is how to solve the equation to find the number of weekday classes, which is 5. 
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-----  -----
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Answers

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