I need help with this one I’m stuck on it.

Answers

Answer 1

Answer:

Answer:4.5

Step-by-step explanation:

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Find the range of the following piecewise function.[0,11)
(-4,6]
(0,11]
[-4,6)

Answers

Given:

The piecewise function is

$f(x)=\begin{cases}x+4 & \text{ if } -4\leq x<3 \n 2x-1 & \text{ if } 3\leq x<6 \end{cases}$

To find:

The range of given piecewise function.

Solution:

Range is the set of output values.

Both functions $f(x)=x+4$ and $f(x)=2x-1$ as linear functions.

Starting value of $f(x)=x+4$ is at x=-4 and end value is at x=3.

Starting value: $f(-4)=-4+4=0$

End value: $f(3)=3+4=7$

Starting value of $f(x)=2x-1$ is at x=3 and end value is at x=6.

Starting value: $f(3)=2(3)-1=5$

End value: $f(6)=2(6)-1=11$

Least range value is 0 at x=-4 and 0 is included in the range because -4 is included in the domain.

Largest range value is 11 at x=6 and 11 is not included in the range because 6 is not included in the domain.

So, the range of the given piecewise function is [0,11).

Therefore, the correct option is A.

Sorry for all the math questions but I do not understand this at all. someone explain and write the equation for me please?? they are the exact words... doesn't make sense to me:the sum of three times a number (z) and 15 is equal to 21.

Answers

3Z + 15 = 21 equation

1. solution
3Z + 15 = 21
3Z = 21 - 15
3Z = 6 [:3
Z = 2

2 solution
3Z + 15 = 21 [:3
Z + 5 = 7
Z = 7 - 5 = 2

Solve for L.
P = 2L + 2W

Answers

Answer:

The answer is $L=(P-2*W)/(2)$

Step-by-step explanation:

In order to solve for L, we have to free the L variable.

Mathematically, we have to subtract, add, multiply or divide the same terms from each side of the equation. In that way, we can change the equation and free a variable.

Therefore, we have to subtract 2*W term, and then we have to divide by 2.

So,

$P=2*L+2*W\nP-2*W=2*L+2*W-2*W\nP-2*W=2*L\n(P-2*W)/(2)=(2*L)/(2)\n L=(P-2*W)/(2)$

Finally, the expression for L is $L=(P-2*W)/(2)$

subtract 2W from both sides

2L = P - 2W

divide both sides by 2

L = P/2 - W

A triangle with one obtuse angle must also have two acute sides

Answers

that would be true :D hope i helped you

That is true :))))) good job

Calcule a soma dos multplos positivos de 9 monores que 100

Answers

Calculate some two positive multiples of 9 less than 100.

Multiples of a whole number are found by taking a product of any counting number and that whole number.

Counting number whole number multiples
1 9 9
2 9 18
3 9 27
4 9 36
5 9 45
6 9 54
7 9 63
8 9 72
9 9 81
10 9 90
11 9 99

The multiples listed are all less than 100. You can choose which two positive multiples you want.

As x → −[infinity], y → ? As x → [infinity], y → ? Determine the end behavior for y = 8x^4 Determine the end behavior for y = -49 + 5x^4 + 3x Determine the end behavior for y = -x^5 + 5x^4 + 5

Answers

Problem 1

The end behavior of y = 8x^4 is:

$\text{As x} \to -\infty, \text{ y } \to \infty\n\text{As x} \to \infty, \text{ y } \to \infty$

In either case, y approaches positive infinity. This end behavior is the same as a parabola that opens upward. This applies to any even degree polynomial.

Informally we can describe the end behavior as: "Both endpoints rise up forever".

======================================

Problem 2

The end behavior of y = -49 + 5x^4 + 3x is the exact same as problem 1. Why? Because the degree here is 4. The degree is the largest exponent.

======================================

Problem 3

For this problem we have the polynomial y = -x^5 + 5x^4 + 5

This time the degree is 5, which is an odd number.

The end behavior would be

$\text{As x} \to -\infty, \text{ y } \to \infty\n\text{As x} \to \infty, \text{ y } \to -\infty$

Informally, we can state the end behavior as "Rises to the left, falls to the right".

The endpoints go in opposite directions whenever the degree of the polynomial is odd. Think of a cubic graph. The "falls to the right" is due to the negative leading coefficient.

I strongly recommend using a TI83, TI84, Desmos, or GeoGebra to graph out each polynomial so you can see what the end behavior is doing.

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