MATHEMATICS HIGH SCHOOL

A football coach is trying to decide: When a team is ahead late in the game, which strategy is better? Play the "regular" defense. Play a "prevent" defense that guards against long gains but makes short gains easier. The coach reviews the outcomes of 100 games. Compare the probability of winning when playing regular defense with the probability of winning when playing prevent defense. Draw a conclusion based on your results.

Answers

Answer 1

Answer:

B. P(win | regular) = 0.84

P(win | prevent) = 0.70

Conclusions : You are more likely to win by playing regular defence.

What is probability ?

The ratio of favourable outcomes of an event and total outcomes of an event is called probability of that event.

What is the conclusion of the problem ?

The number of outcomes of winning by regular defence is 42 out of 50.

∴ P(win | regular) = 42/50 = 0.84

The number of outcomes of winning by prevent defence is 35 out of 50.

∴ P(win | prevent) = 35/50 = 0.70

Conclusion : You are more likely to win by playing regular defence.

Hence the option B is correct.

Learn more about probability here :

brainly.com/question/24756209

#SPJ2

Answer 2

Answer:

Answer: B

Step-by-step explanation:

The probability of winning when playing regular defense is 42 over the total 50.

42/50 = 0.84

The probabilty of also winning when playing Prevent defense is 35 over the total 50 also.

35/50 = 0.70

0.84 is greater than 0.70 so your more likely to win playing regular defense.

Related Questions

Write a linear function with the values f(6)=8 and f(9)=3*PLEASE HELP IM SO LOST*
Identify the pattern for the following sequence. Find the next three terms in the sequence.5, 2, -1, -4, ____, ____, ____,... a. Subtract 3; -7, -10, -13 b. Add 3; -7, -10, -13 c. Subtract -3; 7, 10, 13 d. Add 3; 1, 4, 7
Round 38217 to 2 significant figures
If y* -4x+1 were changed to y =- 2x + 6, how would the graph of the new line
Let h(x) = 8x-3 What is h(5)? A. 40 B. 37 C. 43 D. 45

For f (x), evaluate the following:
a, f(0)
b. f(6)

Show all of your work

Answers

Answer:

a). f(0) = 4

b). f(6) = 8

Step-by-step explanation:

a). When x < 5, piecewise function to be considered,

f(x) = x + 4

Since, x = 0 is less than x = 5

f(0) = 0 + 4

f(0) = 4

b). When 5 ≤ x < 7,

Piecewise function to be considered,

f(x) = 8

Therefore, for x = 6,

f(6) = 8

Solve the following equation for x, in terms of an and b. Enter the numerator of the fraction in blank 1 and the denominator in blank 2 and 3. X=_/_- , _

Answers

Answer:

I can help you solve the equation for x, in terms of a and b. Here are the steps and the results:

To solve the equation for x, we need to isolate x on one side of the equation and simplify the expression on the other side, we can write:

x + a = b x = b - a

Therefore, the solution for x is x = b - a. This is a fraction with numerator b - a and denominator 1. To enter the answer in the blanks, we can write:

x = b - a / 1 - , _

I hope this helps you understand how to solve equations for x. If you have any questions, please let me know.

If m < 0 and b > 0, the graph of y = mx + b does not pass through which quadrant?Quadrant I
Quadrant II
Quadrant III
Quadrant IV

Answers

Answer:

Quadrant III

Step-by-step explanation:

The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.

The graphs shown are of the functions:

$y=-2x+1$

$y=-3x+3$

$y=-x+0.5$

$y=-5x+2$

So, any linear function of the form $y=mx+b$ with $m<0$ and $b>0$ does not pass through Quadrant III. Answer choice 3 is correct.

The graph will not past at quadrant III. I think thats the best answer, hope that helps.

Which shows the factored form of x2 – 12x – 45?(x + 3)(x – 15)
(x – 3)(x – 15)
(x + 3)(x + 15)
(x – 3)(x + 15)

Answers

Hi!

(x+a)·(x+b) = x²+xa+xb+ab = x²-12x-45

x² = x²
xa+xb = (a+b)x = -12x ⇒ (a+b) = -12
ab = -45

When (a+b) = -12 and ab = -45?

+3-15 = -12 and (+3)(-15) = -45
-3-15 = -18 and (-3)(-15) = +45
+3+15 = +18 and (+3)(+15) = +45
-3+15 = +12 and (-3+15) = -45

Answer:

(x+3)(x-15)

What is the simplified base for the function f(x) = 2(3√27(2x)?2
3
9
18

Answers

Answer:

option C is correct i.e. 9

Step-by-step explanation:

We have given that : $f(x)=2 \sqrt[3]{27^(2x)}$

To find : The simplified base of the function f(x)

Solution:

Now, we solve the equation

$f(x)=2 \sqrt[3]{27^(2x)}$

$f(x)=2(27^x)^{(2)/(3)}$

$f(x)=2(3^(2x))$

$f(x)=2((3^2)^(x))$

$f(x)=2(9^(x))$

Therefore, the simplified base of the function f(x) is 9

Answer:

Option C is correct

9 the simplified base for the given function f(x)

Step-by-step explanation:

Using exponent rules:

$(x^m)^n = x^(mn)$

$\sqrt[n]{x^b} = x^{(b)/(n)}$

Given the function:

$f(x) = 2\sqrt[3]{27^(2x)}$

We can write 27 as:

$27 = 3 \cdot 3 \cdot 3 = 3^3$

then;

$f(x) = 2\sqrt[3]{(3^3)^(2x)}$

Apply the exponent rules:

$f(x) = 2\sqrt[3]{3^(6x)}$

Apply the exponent rules:

$f(x) =2 \cdot (3^(6x))^{(1)/(3)} = 2 \cdot 3^(2x)$

⇒ $f(x) = 2 \cdot (3^2)^x = 2 \cdot 9^x$

⇒ $f(x) =2 \cdot 9^x$

On comparing with exponential function $f(x) = ab^x$ where, b is base of the exponent function, then

b = 9

Therefore, the simplified base for the given function is, 9

Blair's garden is four feet shorter than double its width. The perimeter of the garden is 64 feet. The width of the garden is ___ feet.

The length of the garden is ____ feet.