MATHEMATICS HIGH SCHOOL

A line has a gradient of 4 and passes through the post (1,7). what is the equation?

Answers

Answer 1
Answer:

Answer:

The equation is y = 4x+3

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 4x + b

Substitute the x and y value into the equation

7 = 4(1)+b

7 = 4+b

Subtract 4

7-4 =b

3=b

The equation is y = 4x+3
Answer 2
Answer:

Answer:

y = 4x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 4, thus

y = 4x + c ← is the partial equation

To find c substitute (1, 7) into the partial equation

7 = 4 + c ⇒ c = 7 - 4 = 3

y = 4x + 3 ← equation of line

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Simplify the product using the distributive property. (-4h +2)(3h +7)
(4x4 + 3x3 +2x + 1)/ (x2 + x+2)
9) Which equation represents the line that passes through the point (3,4) and is parallel to the x-axis?A x = 4 B x = 3 C y = 4 D y = 3
Simple Question: What is 5x6-3/9?
The data set below has an outlier.2, 10, 10, 11, 11, 12, 12, 12, 13, 14, 14 Which value is changed the most by removing the outlier? A: the range B: the median C: the lower quartile D: the interquartile range

Trey is sewing a pentagonal button into a shirt, as shown in the figure below. The button has holes at each of its 5 corners. How many different stitches would Trey need to make in order to stitch a piece of thread across every possible pair of non-adjacent holes?

Answers

To stitch a piece of thread across every possible pair of non-adjacent holes in a pentagonal button with 5 corners, you can use the combination formula.

For a pentagon, there are 5 corners, and you want to choose 2 holes to stitch between, so it's a combination of 5 holes taken 2 at a time.

The combination formula is:

C(n, k) = n! / (k!(n-k)!)

Where:
- n is the total number of items to choose from (in this case, 5 holes).
- k is the number of items to choose (in this case, 2 holes).

C(5, 2) = 5! / (2!(5-2)!)

Now, calculate the combinations:

C(5, 2) = 5! / (2!(3!))

C(5, 2) = (5 * 4 * 3!) / (2! * 3!)

Now, simplify:

C(5, 2) = (5 * 4) / (2!)

C(5, 2) = (20) / (2)

C(5, 2) = 10

So, Trey would need to make 10 different stitches to stitch a piece of thread across every possible pair of non-adjacent holes in the pentagonal button.

What are the eight-digit grid coordinates for spot elevation 85?

Answers

Answer:

EG02439358 ± 20 meters


Step-by-step explanation:

7a-3=3-2a
I don't know how to solve this question

Answers

7a-3=3-2a
9a-3=3 (add 2a to both sides)
9a=6 (add 3 to both sides)
a=6/9 (divide by 9 to both sides)
get all variables (in this case, "a") on one side by adding "2a" to both. this cancels the "-2a". then, combine like terms. also move "-3" to the other side, by adding "3". finally, divide the "6" and "a" by "9" to get variable alone. therefore, "a = 2/3".
7a-3=3-2a
+2a     +2a
9a-3=3
   +3  +3
    9a=6
      a=2/3

What is 15% of 120 and how do you do it

Answers

15%*120=15/100*120=15/10*12 ( u can cancel 1 0 from 100 &120)=3/2*12( by cancelling by 5)=3*6( by cancelling by 2 )=18 ans,,

Ramon drives his car 150 miles in 3 hours. What is Ramon's driving rate?

Answers

You would divide 150 by three to get 50 miles an hour
50 miles an hour
You would pretty much go 5 miles slower than the speed limit

Need help in solving this problem. Section is under limits at infinity, horizontal asymptotes...(a) A tank contains 5000L of pure water. Brine that contains 30g of salt per liter of water is pumped into the tank at a rate of 25L/min. Show that the concentration of salt after t minutes (in grams per liter) is
C(t)+ 30t/200+t
(b) what happens to the concentration as t--> infinity?

Answers

 (a) you can show the concentration by: 

amount of salt / amount of water 


amount of salt 

= 30g / L 

= [ 30 * 25g ] / [ 25L ] , 25L = 1 min 

= [ 30 * 25g ] / min 


amount of water 

= 5000 + 25t 


[ 30 * 25t ] / [ 5000 + 25t ] 

= [ 30 * 25t ] / 25*[ 200 + t ] 

= 30t / [ 200 + t ] yeah 


(b) 


lim t->∞ [ 30t / ( 200 + t ) ] 

= lim t->∞ [ ( (1 / t) * 30t ) / ( (1 / t) * ( 200 + t ) ) ] 

= lim t->∞ [ 30 / ( (200 / t) + 1 ) ] 

= 30 / ( (200 / ∞) + 1 ) 

= 30 / 1 

= 30


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