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PLEASE ANSWER!!!!!!!! Which system of equations does this graph represent? Linear graph and parabola. They intersect at 2, negative 1 and negative 3, 4 (1 point) A. y = x2 − 5 y = −x + 1
B. y = x2 − 5 y = −x − 1
C. y = x2 + 5 y = −x + 1
D. y = x2 + 5 y = −x − 1

Answers

Answer 1

Answer:

Answer:

Option (A)

Step-by-step explanation:

For equation of the line,

Let the equation is, y = mx + b

Slope 'm' of the line passing through two points (-3, 4) and (2, -1),

m = $(y_2-y_1)/(x_2-x_1)$

= $(4+1)/(-3-2)$

= -1

y-intercept of this line, b = 1

Now we substitute these values in the equation,

y = -x + 1

Let the equation of the parabola is,

y = a(x - h)² + k

Here, (h, k) is the vertex of the parabola,

Since vertex of the given parabola is (0, -5),

then the equation will be,

y = a(x - 0)²- 5

y = ax² - 5

Since a point (2, -1) lies on this parabola,

-1 = a(2)² - 5

5 - 1 = 4a

a = 1

Equation of the parabola will be,

y = x² - 5

Therefore, Option (A) will be the answer.

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I need a reason how sort from least to greatest I don’t understand

Determine the value of x

1)70
2)140
3)40
4)280

Answers

180-140= 40

Im not so sure of my answer so I might be wrong so enjoy!!

according to the line plot what is the total distance that was run by Runners who each ran for 1/3 of a mile

Answers

The total distance that was run by Runners who each ran for 1/3 of a mile will be 4/3.

What is distance?

The distance is defined as the length of the space between the two points separated from each other.

From the graph, the distance of 1/3 miles is covered by 4 runners so the total distance will be calculated as:-

Distance = 1/3 x 4

Distance = 4/3 miles

Hence the total distance that was run by Runners who each ran for 1/3 of a mile will be 4/3.

To know more about distance follow

brainly.com/question/2854969

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So you would do 1/3 times 4 so that is 1 and 1/3

Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time it takes to produce the product using the new machine is significantly less than the production time using the old machine. To test the claim, independent random samples were taken from both machines. You are given the following results.New Machine Old Machine
Sample Mean 25 23
Sample Variance 27 7.56
Sample Size 45 36
As the statistical advisor to Ajax, would you recommend purchasing Allied's machine? Explain.

Answers

Answer:

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean x₁ = 25

Sample variance s₁ = 27

Sample size n₁ = 45

Old machine

Sample mean x₂ = 23

Sample variance s₂ = 7,56

Sample size n₂ = 36

Test Hypothesis:

Null hypothesis H₀ x₂ - x₁ = d = 0

Alternative hypothesis Hₐ x₂ - x₁ < 0

CI = 90 % ⇒ α = 10 % α = 0,1 z(c) = - 1,28

To calculate z(s)

z(s) = ( x₂ - x₁ ) / √s₁² / n₁ + s₂² / n₂

s₁ = 27 ⇒ s₁² = 729

n₁ = 45 ⇒ s₁² / n₁ = 16,2

s₂ = 7,56 ⇒ s₂² = 57,15

n₂ = 36 ⇒ s₂² / n₂ = 1,5876

√s₁² / n₁ + s₂² / n₂ = √ 16,2 + 1.5876 = 4,2175

z(s) = (23 - 25 )/4,2175

z(s) = - 0,4742

Comparing z(s) and z(c)

|z(s)| < | z(c)|

z(s) is in the acceptance region. We accept H₀ we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o

Answers

Answer:

$y=3e^(-4t)$

Step-by-step explanation:

$y''+5y'+4y=0$

Applying the Laplace transform:

$\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0$

With the formulas:

$\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)$

$\mathcal{L}[y']=s\mathcal{L}[y]-y(0)$

$\mathcal{L}[x]=L$

$s^2L-3s+5sL-3+4L=0$

Solving for $L$

$L(s^2+5s+4)=3s+3$

$L=(3s+3)/(s^2+5s+4)$

$L=(3(s+1))/((s+1)(s+4))$

$L=\frac3{s+4}$

Apply the inverse Laplace transform with this formula:

$\mathcal{L}^(-1)[\frac1{s-a}]=e^(at)$

$y=3\mathcal{L}^(-1)[\frac1{s+4}]=3e^(-4t)$

triangle NOP is similar to triangle QRS. Find the measure of Side SQ. Round your answer to the nearest tenth if necessary

Answers

The measure of side SQ from the given similar triangles is 40.9 units.

What are similar triangles?

Two triangles are similar if the angles are the same size or the corresponding sides are in the same ratio. Either of these conditions will prove two triangles are similar.

Given that, triangle NOP is similar to triangle QRS.

Since the triangles are similar,

NP/SQ = NQ/QR

10/SQ = 13/53.2

13SQ=532

SQ=532/13

SQ=40.9 units

Therefore, the measure of side SQ is 40.9 units.

To learn more about the similar triangles visit:

brainly.com/question/25882965.

#SPJ2

Answer:

Step-by-step explanation:

(7h + 7) + (7h + 8)

........

Answers

Answer:

14h+15

Step-by-step explanation:

(7h + 7) + (7h + 8)

First simplify

Eliminate redundant parentheses

(7h+7)

7h+7+7h+8

Add the numbers

7h+(7)+7h+(8) . 7+8=15

7h+15+7h

Combine like terms

(7h)+15+(7h) (7h)+(7h)=14h

14h+15

The answer would be 14h+15

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PLEASE ANSWER!!!!!!!! Which system of equations does this graph represent? Linear graph and parabola. They intersect at 2, negative 1 and negative 3, 4 (1 point) A. y = x2 − 5 y = −x + 1 B. y = x2 − 5 y = −x − 1 C. y = x2 + 5 y = −x + 1 D. y = x2 + 5 y = −x − 1

Answers

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What is distance?

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What are similar triangles?

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PLEASE ANSWER!!!!!!!! Which system of equations does this graph represent? Linear graph and parabola. They intersect at 2, negative 1 and negative 3, 4 (1 point) A. y = x2 − 5 y = −x + 1
B. y = x2 − 5 y = −x − 1
C. y = x2 + 5 y = −x + 1
D. y = x2 + 5 y = −x − 1