Select 222 strategies that we can use to subtract 563-192563−192563, minus, 192. Choose 2 answers: Choose 2 answers: (Choice A) A Add 100+90+2100+90+2100, plus, 90, plus, 2. (Choice B) B Evaluate (563-200)+8(563−200)+8left parenthesis, 563, minus, 200, right parenthesis, plus, 8. (Choice C) C Subtract 571-200571−200571, minus, 200.

Answers

Answer 1
Answer:

Final answer:

The most effective strategies to subtract 563 from 192 are by rounding the number (Choice B) or by step-by-step addition and subtraction (Choice A), with rounding being the preferred method for ease of calculation.

Explanation:

To subtract 563 from 192, two effective strategies can be used. The first strategy (Choice B) simplifies the problem by rounding 192 to 200, subtracting to get 563 - 200 = 363, and then adding back the difference of 8 (since 200 - 192 = 8), resulting in the final answer of 363 + 8 = 371.

The second strategy (Choice A) is to add the constituent parts of 192, which are 100, 90, and 2, to perform step-by-step addition and subtraction. This method, however, is less efficient than the rounding technique and is prone to errors in a manual calculation process.

Learn more about Subtraction Strategies here:

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Answer 2
Answer: The answer to this will not prolly be 20

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If P + 77 = 101, then P equals
Anybody know the answer ? Please help :(

the lengths of the sides of a right triangle are con-secutive even integers. find these lengths. (hint: use the pythagorean

Answers

Answer:

The lengths are 6, 8, and 10

Step-by-step explanation:

6²+8²=10²

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What is the area of this polygon?

Answers

The middle is a square with side length of 12cm

Area of the square = 12 x 12 = 144 cm^2

There are 4 triangles with base of 13cm and height of 8 cm

Area of triangle = 1/2 x base x height

Area = 1/2 x 12 x 8 = 48cm^2 each

48 x 4 = 192 cm^2

Total area = 144 + 192 = 336 cm^2

5. Find the next 4 terms of the sequence
47, 45, 40, 32, 21, , , , ,

Answers

Answer:

7      -10     -30     -53

Step-by-step explanation:

47-2 = 45

45-5 = 40    (2+3=5)

40-8 = 32   (5+3=8)

32-11 = 21(8+3=11).........

21-14 = 7

7-17 = -10

-10 -20 = -30

-30-23 = -53

Jabari owns 100 shares of Stock A and 45 shares of Stock B. For the past month, his stocks have been fluctuating inversely each week. Stock A decreased by m cents per share and Stock B increased by n cents per share. Which equation can be used to find the total change in value of Jabari's shares?

Answers

This is how we solved and make the equation.
Stock A = 100
Stock B = 45

For the past months, his stocks inversely decreased.
Stock A = m cents / share
Stock B = n cents * share

So the equation is
= 100 (0.01m) + 45 (0.01n)
= m + 0.45n

5x + 4y = 6 and y = 5/4x + 5

Answers

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(−7/5,13/4)

Equation Form:

x=−75,y=134x=-75,y=134

What is 5*5+100-99*76

Answers

Answer:

-7399

Step-by-step explanation:

5*5+100-99*76

25 + 100 - 7524

= -7399

Answer:

-7399

Step-by-step explanation:

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