Helpppppp , quick answer with work pleaseeee​
helpppppp , quick answer with work pleaseeee​ - 1

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

√(x-2)+8=x\n\n√(x-2)=x-8\n

Square both sides,

x-2=(x-8)^(2)\n\nx-2=x^(2)-2*x*8+8^(2)\n\nx-2=x^(2)-16x+64\n\nx^(2)-16x+64=x-2\n\nx^(2)-16x+64-x+2=0\n\nx^(2)-17x+66=0

Sum = - 17

Product = 66

Factors = -6 , -11

x² - 6x -11x + (-6)*(-11) = 0

x(x - 6) -11(x - 6) = 0

(x-6) (x - 11) = 0

x -6 = 0   ; x - 11 = 0

x = 6   ; x =11

Here,  x = 6 is a extraneous solution


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What is the lowest common multiple of 20 and 60

Answers

Answer:

60

Step-by-step explanation:

Find the quotient and remainder using long division.x + x - 13
x - 2
The quotient is
The remainder is

Answers

Answer:

\text{The quotient is}~ x^2 +2x +5 \n\n\text{The remainder is}~ -3

Step-by-step explanation:

Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a standard deviation of 10.2. Construct a 90% confidence interval for the mean test score.

Answers

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - (1 - 0.9)/(2) = 0.95. So we have T = 2.064

The margin of error is:

M = T(s)/(√(n)) = 2.064(10.2)/(√(25)) = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work in temperatures of 200-500 degrees. In a test of one type of mask, 24 of 55 were found to have their lenses pop out at 325 degrees. Construct and interpret a 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees.

Answers

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{(\pi(1-\pi))/(n)}

In which

z is the zscore that has a pvalue of 1 - (\alpha)/(2).

For this problem, we have that:

n = 55, \pi = (24)/(55) = 0.4364

93% confidence level

So \alpha = 0.07, z is the value of Z that has a pvalue of 1 - (0.07)/(2) = 0.965, so Z = 1.81.

The lower limit of this interval is:

\pi - z\sqrt{(\pi(1-\pi))/(n)} = 0.4364 - 1.81\sqrt{(0.4364*0.5636)/(55)} = 0.3154

The upper limit of this interval is:

\pi + z\sqrt{(\pi(1-\pi))/(n)} = 0.4364 + 1.81\sqrt{(0.4364*0.5636)/(55)} = 0.5574

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Find the value of y when x = -5

Answers

Answer:

there isn't even a y here

Step-by-step explanation:

Did you not write the while question?

HELPP!!! BRAINLYESTTTTT!!!!!!


GRAPH THE FUNCTION:

Answers

Answer:


Step-by-step explanation:

We are given the function f(x) = -3/4(x) +6.

We know that the slope intercept form of a line is y = mx + b

Here, the slope m = -3/4.

The y-coordinate of the y intercept is b = 6 so the y-intercept is at the point (0,6) [x is always 0 at the y-intercept]

If you have to points you can graph the line, we only have the point (0,6).

To find the second point we use the slope.

We add the bottom point of the slope to the x coordinate of the y-intercept and we add the top part of the slope to the y coordinate of the y-intercept, so our second point is (0 + 4, 6 +(-3)) = (4, 3).

You then plot the points we have: (0,6) and (4,3) and draw the line through them.