MATHEMATICS MIDDLE SCHOOL

Given that points A, B, and C are the midpoints of their respective sides, which of the following is true about the figure? ANSWERS: A) ∠Y ≅ ∠Z B) ∠X ≅ ∠ACB C) || D) ||

Answers

Answer 1

Answer:

Answer:

The correct option is;

$\overline{YZ}\left | \right | \overline{AC}$

Step-by-step explanation:

The dimensions given are;

YX = 2 × AX (A = midpoint of YX)

ZX = 2 × CX (C = midpoint of ZX)

∠X and ∠X are congruent (Reflexive property)

Therefore, triangle XAC is similar to triangle XYZ (SAS similarity theorem)

Since ∠XYZ = ∠XAC segments YZ and AC are parallel from having equal angle on the same side of the transversal YX

Therefore the correct option should be;

$\overline{YZ}\left | \right | \overline{AC}$

Answer 2

Answer:

Answer:ΔBCZ ≅ ΔYAB

Step-by-step explanation: since we know the midpoint are <ABC we can see the that answer is correct.

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Apply the distributive property to create an equivalent expression.

(6e−3f−4)⋅2

Answers

Answer:

$12e-6f-8$

Step-by-step explanation:

We have been given an expression: $(6e-3f-4)\cdot 2$ and we are asked to create an equivalent expression by using distributive property.

To apply distributive property let us multiply each term in parenthesis by 2.

$6e* 2-3f* 2-4* 2$

Let us combine like terms.

$(6* 2)e-(3* 2)f-(4* 2)$

Now let us simplify our expression.

$12e-6f-8$

Therefore, expression $12e-6f-8$ is equivalent to our given expression.

(6e−3f−4)⋅2

Apply the distributive property

= 6e (2) - 3f (2) - 4(2)

= 12e - 6f - 8

Hope it helps.

Brandon enters bike races.He bikes 8 1/2 miles every 1/2 hour. complete a table to find how far Brandon bikes for each time interval.

Answers

12. Since there is no table given I will assume that what you want me to do is to show that Unit rate of Brandon’s biking.SO here are the data that we need:=> 8 and ½ miles = 8.5 miles=> ½ hour = .5 hours or 30 minutesNow, let’s solve for the unit rate=> SO in every 30 minutes he bikes around 8.5 miles=> Since 1 hour is equals to 30 minutes, simply multiply 8.5 by 2=> 8.5 * 2 = 17miles=> 17 miles / hour

The distance of Brandon’s bike in each interval of time can be represented in the attached Table 1.

Further explanation:

Given:

Brandon enters in to the bike race and he bikes $8(1)/(2)\text{ miles}$ in every $(1)/(2)\text{ hour}$ .

Calculation:

It is given that in every $(1)/(2)\text{ hour}$ Brandon bikes $8(1)/(2)\text{ miles}$ .

The distance $8(1)/(2)\text{ miles}$ is in the form of mixed fraction.

Therefore, the distance $8(1)/(2)\text{ miles}$ can be written in the form of decimal as follows:

$\boxed{8(1)/(2)\text{ miles}\rightarrow8.5\text{ miles}}$

Brandon bike's $8.5\text{ miles}$ in every $(1)/(2)\text{ hour}$ .

We know that $1\text{ hour}$ is equivalent to $60\text{ minutes}$ .

So, $0.5\text{ hour}$ can be converted into minutes as follows:

$\boxed{\begin{aligned}1\text{ hour}\rightarrow60\text{ minutes}\n0.5\text{ hour}\rightarrow30\text{ minutes}\end{aligned}}$

Therefore, in every $30\text{ minutes}$ Brandon bikes $8.5\text{ miles}$ .

So, in next $30\text{ minutes}$ Brandon also bikes $8.5\text{ miles}$ .

In every $1\text{ hour}$ Brandon travels $\boxed{8.5+8.5=17\text{ miles}}$ .

In every $1:30\text{ hour}$ Brandon travels $\boxed{17+8.5=25.5\text{ miles}}$ .

Method 2:

Speed of Brandon’s bike can be calculated as ,

$\boxed{\text{Speed}=(d)/(t)}$ …… (1)

Here, $d$ is the distance and $t$ is the time.

The distance is $8.5\text{ miles}$ and time is $0.5\text{ hour}$ .

Now, substitute $d=8.5$ and $t=0.5$ in the equation (1) to obtain the speed as follows:

$\begin{aligned}\text{Speed}&=(8.5)/(0.5)\n&=17\text{ miles per hour}\end{aligned}$

Therefore, the rate of travelling of Brandon’s bike is $17\text{ miles per hour}$ .

The distance of Brandon’s bike in each interval of time can be represented in the attached Table 1.

Learn more:

1. Learn more about problem on numbers: brainly.com/question/1852063

2. Learn more about problem on function brainly.com/question/3225044

3. Learn more about problem on digits brainly.com/question/120717

Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Speed, time and distance

Keywords: Distance, Brandon’s bike, interval, time, race, mixed fraction, distance, decimal, hour, minutes, rate, fraction, velocity, 1/2 miles, 1/2 hour.

What is made up of two or more three dimensional figures

Answers

House , Computers , mobile , bottle , bags etc. are all made up of two or more three dimensional figures.

What are Three dimensional figures ?

Prisms and pyramids, as well as forms with curved surfaces, are examples of three-dimensional figures.

A prism is a three-dimensional object having two congruent parallel bases. Any polygon can be used for the bases, which are also two of the faces. Rectangles make up the rest of the faces.

The shape of a prism's base determines its name.

Everything in surrounding is made of many three dimensional figures

Example : House , Computers , mobile , bottle , bags etc.

To know more about Three dimensional figures

brainly.com/question/24303419

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Answer: triangular and rectangular prism

How many degrees in a triangle

Answers

a triangle equals 180 degrees

A triangle equals 180 degrees

4²+5[61-(5×6)] what's the answer for this

Answers

In this question we can see that there are different type of brackets used. Also there is multiplication addition and subtraction. So we need to follow the BODMAS rule.
B = Bracket
O = Of
D = Division
M = Multiplication
A = Addition
S = Subtraction
Now let us focus on the problem in hand.
4^2 + 5[ 61 - (5 * 6)] = (4)^2 + 5[ 61 - (30)]
   = (4)^2 + 5[ 61 - 30]
   = 16 + 5 [31]
   = 16 + 155
   = 171
So the answer for the question comes out to be 171. I hope the procedure is clear enough for you to understand. You can always use this method for solving similar problems in future.

If you would like to solve 4^2 + 5 * [61 - (5 * 6)], you can calculate this using the following steps:

4^2 + 5 * [61 - (5 * 6)] = 16 + 5 * [61 - 30] = 16 + 5 * 31 = 16 + 155 = 171

The correct result would be 171.

I have 7th grade common core test coming up tomorrow and I have fallen so far behind. Can someone give me some (hopefully many) tips for it?

Answers

take ur time . don't rush throw it . think thing throw

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