The seventh-grade class is building target areas for a PE activity. The bases for the game will be in a circular shape. The diameter of each circle is 3 feet. Approximately, how many square feet of the turf need to be painted for a base circle? Use 3.14 for π and round your answer to the nearest tenth. 7.1 square feet
9.4 square feet
18.8 square feet
28.3 square feet
Answers
Answer:
7.1 square feet
Step-by-step explanation:
Since the diameter of a circle is twice the radius, the radius of each circle is 3/2=1.5. The area of a circle is . Hope this helps!
Answer:
18.8
Step-by-step explanation:
Related Questions
Can someone please help me with this math question PLEASE HELP THIS IS URGENT
Walters savings account has a balance of $273. After 5 years, what will the amount of interest be at 5% compounded quarterly?
Choose the correct name for these sets of numbers.
One person can do a certain job in ten minutes, and another person can do the same job in fifteen minutes. How many minutes will they take to do the job together? If x represents how many minutes to do the job together, then how much of the job does the slowest person do? 1. x/152. x/103. 15/x
A. –7
B. –3
C. 41
D. 25
Answers
zero
one
infinite
Answers
Answers
Answer:
Denote the two points are A and B, the balloon is C. Then we have,
Side AB = 9 miles
Angle CAB (angle A) = 27 deg
Ange CBA (angle B) = 45 deg
=> Angle ACB (angle C) = 180 - 27 - 45 = 108 deg
Applying the sine theorem:
AB/sinC = BC/sinA
=> BC = AB x sinA/sinC = 9 x sin27/sin108 = 4.3 miles
Denote CH as the height from C to side AB (or distance from ground to balloon), we have:
CH = BC x sin B = 4.3 x sin*45 = ~3.04 miles
=> Distance from ground to balloon: ~3.04 miles
Hope this helps!
:)
Answer:
3.0 miles
Step-by-step explanation:
Let h be the height
Tan(27) = h/b
h = btan(27)
Tan(45) = h/(9-b)
(9-b)tan(45) = h
(9-b)tan(45) = btan(27)
9tan(45) = b[tan(45) + tan(27)]
b = 5.962138633
h = btan(27) = 3.037861367
Answers
Answer:
Multiply by 1/7
Step-by-step explanation:
14*1/7=2
21*1/7=3
Why?
Answers
Final answer:
The liters of milk remaining in the tank after leaking for t weeks is represented by an exponential function. An exponential function is a mathematical function in which the independent variable appears as an exponent.
Explanation:
The function that represents the liters of milk remaining in the tank after leaking for t weeks is an exponential function. An exponential function is a mathematical function in which the independent variable appears as an exponent. In this case, the liters of milk lost each week is constant, so the amount of milk remaining in the tank is decreasing exponentially over time.
Formula for exponential decay: M = P * (1 - r)^t, where M is the amount of milk remaining, P is the initial amount of milk, r is the rate of decay, and t is the number of weeks.
In this case, the initial amount of milk, P, is 600 liters and the rate of decay, r, is 60/600 = 0.1 (10%). So the exponential function that represents the liters of milk remaining after t weeks is M = 600 * (1 - 0.1)^t.
Learn more about Exponential decay here:
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