MATHEMATICS HIGH SCHOOL

John goes running every morning. He can run 3 miles in 1 hour. How many miles would he be able to run in 1 and ½ hours?

Answers

Answer 1

Answer:

Answer:

4.5 or 4 1/2 miles

Step-by-step explanation:

$\frac{3\text{ miles}}{\text{hour}}\cdot 1.5 \text{ hours}= 3\cdot 1.5=4.5$

Hope this helps!

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What is the quotient (x^3+8)/(x+2)

Answers

Answer:

Step-by-step explanation:

The easiest way to do this is by using synthetic division (I really hope you know what I'm talking about!)

If the factor is x + 2 = 0, then the solution or the root is x = -2. We will put -2 outside the "box" and the coefficients from the terms of the polynomial inside the "box":

-2| 1 0 0 8

Bring down the first number and multiply it by the -2. Put the product up under the first 0 and add:

-2| 1 0 0 8

-2

1 -2

Now multiply the -2 by the -2, put the product up under the next 0 and add:

-2| 1 0 0 8

-2 4

1 -2 4

Now multiply the 4 by the -2, put the product up under the 8 and add:

-2| 1 0 0 8

-2 4 -8

1 -2 4 0

Those bold numbers are the coefficients to the quotient, which is another polynomial, but is one degree less than the one you started with:

x² - 2x + 4 = 0

Since there is no remainder, then x = -2 is a zero of x³ + 8, and (x + 2) is a factor.

There is a whole world of stuff to learn about quadratics!!

HELP NOW PLEASE HOW DO I FIGURE THIS OUT?

Answers

Hello,

∛72=∛(2^3*3^2)=2*∛3^2=2∛9
Answer C

What is $40 with a 30% markup?

Answers

the answer is 52 because to solve this you have to multiply 30 percent or 0.30 * 40 which equals 12 dollars then you add the 12 dollars to your 40 dollars and you get 52 dollars now that is what i call markup

Bryan’s monthly electric bill is determined by adding a flat administration fee to the product of the number of kilowatt hours of electricity used and the cost per kilowatt hour. When he uses 1,100 kilowatt hours of electricity, his bill is $113. When he uses 1,500 kilowatt hours of electricity, his bill is $153. What is the monthly administration fee?

Answers

We will form the equations for this problem:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
z = ? Monthly administration fee is notated with z, and that is the this problem's question.
Number of kilowatt hours of electricity used are numbers 1100 and 1500 respectively.
Cost per kilowatt hour is notated with y, but its value is not asked in this math problem, but we can calculate it anyway.
The problem becomes two equations with two unknowns, it is a system, and can be solved with method of replacement:
(1) 1100*y + z = 113
(2) 1500*y + z = 153
----------------------------
(1) z = 113 - 1100*y [insert value of z (right side) into (2) equation instead of z]:
(2) 1500*y + (113 - 1100*y) = 153
-------------------------------------------------
(1) z = 113 - 1100*y
(2) 1500*y + 113 - 1100*y = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y + 113 = 153
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 153 - 113
------------------------------------------------
(1) z = 113 - 1100*y
(2) 400*y = 40
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 40/400
------------------------------------------------
(1) z = 113 - 1100*y
(2) y = 1/10
------------------------------------------------
if we insert the obtained value of y into (1) equation, we get the value of z:
(1) z = 113 - 1100*(1/10)
(1) z = 113 - 110
(1) z = 3 dollars is the monthly fee.

Answer:

Step-by-step explanation:

correct on ed (:

3-2r+5=2-8/3 is simplified to what?