MATHEMATICS COLLEGE

Consider the diagram and the proof below.Given: In △ABC, AD ⊥ BC
Prove: StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction

Triangle A B C is shown. A perpendicular bisector is drawn from point A to point D on side C B forming a right angle. The length of A D is h, the length of C B is a, the length of C A is b, and the length of A B is c.

A 2-column table has 7 rows. The first column is labeled Statement with entries In triangle A B C line segment A D is perpendicular to line segment B C, In triangle A D B sine (uppercase B) = StartFraction h Over c EndFraction, c sine (uppercase B) = h, In triangle A C D, sine (uppercase C) = StartFraction h Over b EndFraction, b sine (uppercase C) = h, question mark, StartFraction sine (uppercase B) Over b EndFraction = StartFraction sine (uppercase C) Over c EndFraction. The second column is labeled Reason with entries given, definition of sine, multiplication property of equality, definition of sine, multiplication property of equality, substitution, and division property of equality.

What is the missing statement in Step 6?

b = c

StartFraction h Over b EndFraction = StartFraction h Over c EndFraction
csin(B) = bsin(C)

bsin(B) = csin(C)

Answers

Answer 1

Answer:

Answer:

c- the right triangle altitude theorem

Step-by-step explanation:

i did it on edge! ; )

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Decrease 520 by 15% what Is the answer?

Answers

The number is 442 which is obtained after decreasing 520 by 15% the answer is 442.

What is the percentage?

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

Let x be the number that is obtained after decreasing 520 by 15%

= (100 - 15)% of 520

= 85% of 520

= 0.85×520

= 442

Thus, the number is 442 which is obtained after decreasing 520 by 15% the answer is 442.

Learn more about the percentage here:

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#SPJ2

Answer:

442

Step-by-step explanation:

If you want to decrease 520 by 15%, you have to multiply 15% by 520 first, which is 78. Next, you have to minus 78 from 520. Now you get 442!

Amanda buye a book for $7.85. If the tax added on to the price lis $0.75 how much will the book cost in total? What if Amanda donates SLSO to the Love of Reading Foundation? How will thie affect the total coet of the book? (Hint: there is no tax added on to the donation). Estimate what the total cost will be and then check your answer.

Answers

Answer:

$8.60 I don't know what SLSO means

Step-by-step explanation:

. Emma is making bracelets for her friends. She noticed that 12 out of 20 of her beads are red. What decimal is equivalent to the fraction of Emma's beads that are red?

Answers

Answer:

0.6

Step-by-step explanation:

12/20 = 6/10 = 0.6

Which is NOT a multiple of 15?

Answers

Answer:

2, 4, 6, 7, 8, 9, 10, 11, 12, 13, 14, 16 and anything else after 16

Step-by-step explanation:

I can’t see any answer choices so the multiples of 15 are: 15,30,45,60,75,90,105,120,135,150,165,180,195,210,225,240,255,270,285,300,315,330,345,360,375,390,405,420,435,450,465,480,495,510,525,540,555,570,585,600,615,630,645,660,675,690,705,720,735
So I guess anything but those numbers, hope this helps

A meteorologist is studying the speed at which thunderstorms travel. A sample of 10 storms are observed. The mean of the sample was 12.2 MPH and the standard deviation of the sample was 2.4. What is the 95% confidence interval for the true mean speed of thunderstorms?

Answers

Answer:

The 95% confidence interval for the true mean speed of thunderstorms is [10.712, 13.688].

Step-by-step explanation:

Given information:

Sample size = 10

Sample mean = 12.2 mph

Standard deviation = 2.4

Confidence interval = 95%

At confidence interval 95% then z-score is 1.96.

The 95% confidence interval for the true mean speed of thunderstorms is

$CI=\overline{x}\pm z*(s)/(√(n))$

Where, $\overline{x}$ is sample mean, z* is z score at 95% confidence interval, s is standard deviation of sample and n is sample size.

$CI=12.2\pm 1.96(2.4)/(√(10))$

$CI=12.2\pm 1.487535$

$CI=12.2\pm 1.488$

$CI=[12.2-1.488, 12.2+1.488]$

$CI=[10.712, 13.688]$

Therefore the 95% confidence interval for the true mean speed of thunderstorms is [10.712, 13.688].

Select the statements that describe a normal distribution.The density curve is symmetric and bell‑shaped.The normal distribution is a continuous distribution.The normal distribution is a discrete distribution.The density curve is a flat line extending from the minimum value to the maximum value.Approximately 32% of values fall more than one standard deviation from the mean.Two parameters define a normal distribution—the median and the range.

Answers

Answer:

The density curve is symmetric and bell‑shaped.

The normal distribution is a continuous distribution.

Approximately 32% of values fall more than one standard deviation from the mean.

Step-by-step explanation:

Lets take a look at each statement.

The density curve is symmetric and bell‑shaped.

True.

The normal distribution is a continuous distribution.

True, the value of the measure can be a decimal number, like 10.5, for example.

The normal distribution is a discrete distribution.

False. Either the distribution is continuous, or it is discrete. In this case, it is continuous.

The density curve is a flat line extending from the minimum value to the maximum value.

False. This statements describes the uniform probability distribution.

Approximately 32% of values fall more than one standard deviation from the mean.

True. 68% are within 1 standard deviation of the mean and 32% are more than one standard deviation from the mean.

Two parameters define a normal distribution—the median and the range.

False. It is the mean and the standard deviation.

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