The theoretical probability of rolling a number greater than 2 on a standard number cube is 5/6. True or False

Answers

Answer 1

Answer:

Answer:

false- its 4/6

Step-by-step explanation:

Related Questions

Help please and hurry it is due tomorrow
Driving on the highway, you can safely drive 65 miles per hour. Which of the following functions could be used to find how far you can drive in 'h' hours?
What is the answer?please help me
If a=5,b=3,andc=2,what does a+b c equal
Convert 18/40 to a decimal

How do you solve 3(m + 5 + 9m)

Answers

Answer:

30m+15

Step-by-step explanation:

First, collect the like terms: 3(10m+5)

Next, multiply the numbers inside the brackets with 3:

3*10m=30m

3*5=15

So the answer is 30m+15

Answer:30m+5

Step-by-step explanation:

3(m+5+9m)

3m+15+27m

30m+5

Captain Jessica has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thieves. The Captain has probability 4/9 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 1/4 .If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships?

Answers

Answer: Probability that both the pirate and the Captain hit each other's ships is $(1)/(9)$

Step-by-step explanation:

since we have given that

Probability that the captain hits the pirate ship is given by

$(4)/(9)$

Probability that the pirate hits the Captains's ship is given by

$(1)/(4)$

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship" is given by

$P(\text{Captain hits})* P(\text{ Pirates hit})\n\n=(4)/(9)* (1)/(4)\n\n=(1)/(9)$

Hence, probability that both the pirate and the Captain hit each other's ships is $(1)/(9)$

The probability that both the pirate and the Captain hit each other's ships is $(1)/(9)$ . This can be calculated by calculating the joint probability of both events.

What is joint probability?

A joint probability is a probability that two events will occur together and at the same time. Simply it is the probability that A occurs at the same time when B occurs. It can be calculated as:

$P(A and B) = P(A) * P(B)$ , where P(A and B) is the joint probability of A and B occurring together, P(A) is the probability of A, and P(B) is the probability of B.

Given:

The probability of Captain hitting the pirate ship is $(4)/(9)$

The probability of pirate hitting the Captain's ship is $(1)/(4)$ .

Therefore the joint probability will be:

$(4)/(9)*(1)/(4) = (1)/(9)$

Learn more about Joint probability here:

brainly.com/question/14238558

Select all functions that have a y-intercept of (0,5).f(x)=7(b)^x-2
f(x)=-3(b)^x-5
f(x)=5(b)^x-1
f(x)=-5(b)^x+10
f(x)=2(b)^x+5

Answers

Answer:

$f(x)=7(b)^(x)-2$

$f(x)=-5(b)^(x)+10$

Step-by-step explanation:

we know that

The y-intercept is the value of y when the value of x is equal to zero

Verify each case

case 1) we have

$f(x)=7(b)^(x)-2$

For x=0

$f(0)=7(b)^(0)-2$

$f(0)=7(1)-2=5$

therefore

The function has a y-intercept of (0,5)

case 2) we have

$f(x)=3(b)^(x)-5$

For x=0

$f(0)=3(b)^(0)-5$

$f(0)=3(1)-5=-2$

therefore

The function does not have a y-intercept of (0,5)

case 3) we have

$f(x)=5(b)^(x)-1$

For x=0

$f(0)=5(b)^(0)-1$

$f(0)=5(1)-1=4$

therefore

The function does not have a y-intercept of (0,5)

case 4) we have

$f(x)=-5(b)^(x)+10$

For x=0

$f(0)=-5(b)^(0)+10$

$f(0)=-5(1)+10=5$

therefore

The function has a y-intercept of (0,5)

case 5) we have

$f(x)=2(b)^(x)+5$

For x=0

$f(0)=2(b)^(0)+5$

$f(0)=2(1)+5=7$

therefore

The function does not have a y-intercept of (0,5)

What is 61/100 in word form?

Answers

$\boxed{ (61)/(100) =sixty-one \ hundredths}$

61/100 would be sixty-one out of one hundredHOPE IT HELPS :-)

Is the gcf os a pair of numbers ever greater than both numbers ? explain with an example.

Answers

Answer:

No, G.C.F. of pair of numbers can never be greater than both numbers.

Step-by-step explanation:

G.C.F. (Greatest Common Factor) of pair of numbers is defined as the greatest factor of both the number that exactly divides both numbers.

For Example: G.C.F. of 14 and 21 =

36 = 2 × 2 × 3 × 3

48 = 2 × 2 × 2 × 2 × 3

Common Factors of 36 and 48 = 2 × 2 × 3 = 12

∴ G.C.F. = 12

As, we see that G.C.F. is factor of given number. So, it can never be greater than given numbers.

The gcf of numbers can never be greater than both numbers, because in order to be a gcf, it must be a factor that both numbers have, so if one number does not have that then it is not a gcf.

5. L1. Tisha collects old books. She has
2 shelving units, and each shelving
unit has 3 shelves. Each shelf holds
12 books. If both shelving units are
filled with books, how many books
does Tisha have in all