MATHEMATICS HIGH SCHOOL

Given the following functions, find each: f(x)=x2+5x−14 g(x)=x−2 (f+g)(x)= (f−g)(x)=

Answers

Answer 1
Answer:

Answer:

(f+g)(x) = x²+5x-14 + (x-2)

           = x²+5x-14+x-2 = x²+6x-16

(f-g)(x) = x²+5x-14 - (x-2)

          = x²+5x-14 - x+2

          = x²+5x-14-x+2 = x²+4x-12

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9p=81
helppppppppppppppppp

Answers

p = 9 becsude 9 x 9 = 81 so yeah

Two blocks are connected by a very light string passing over a massless and frictionless pulley. The 20.0 N block moves 75.0cm to the right and the 12.0 N block moves 75.0cm downward.Find the total work done on 20.0N block if there is no friction between the table and the 20.0N block.

Answers

The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus, 
1.22 a = 12.0 - T  (eqn 1)
and for the 20.0 N block: 
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction) 
2.04 a = T - 6.5  (eqn 2) 

[eqn 1] + [eqn 2] → 3.26 a = 5.5 
a = 1.69 m/s² 


Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5 
T = 9.95 N 

Now want the resultant force acting on the 20.0 N block: 
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N 
Units have to be consistent ... so have to convert 75.0 cm to m: 

75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m 
work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J

Final answer:

The total work done on the 20.0 N block as it moves 75.0 cm to the right, with no friction between the table and the block, is 15 Joules.

Explanation:

In physics, work done by a force is given by the formula Work = Force x Distance x Cos θ, where θ is the angle between the force and the direction of motion. Here, the force is the same as the weight of the 20.0 N block (because weight = mass * gravity, and the mass is the weight divided by gravity, so mass * gravity = weight), and because the block moves horizontally (rightward), θ is 0 degrees. The Cos of 0 degrees is 1.

So, the work done on the 20.0 N block as it moves 75.0 cm (or 0.75 meters, because 1 m = 100 cm) to the right is 20.0 N * 0.75 m * 1 = 15 Joules.

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Please help me answer this. Ty

Answers

I think 63, but I'm not sure, how do I delete an answer-

Answer:

x=63

Step-by-step explanation:

∠BAC=∠ACD=x(AB∥CD)

∠BCA=∠BAC=x(base∠s, isos△)

∠？BC+∠BCA=90（ext.∠of△）

27+x=90

x=90-27

x=63

Which relation is a direct variation that contains the ordered pair (2, 7)?

Answers

Choices:
y=4x-1
y=2/7x
y=7/2x
y=7/x

(2,7) ⇒ x = 2 ; y = 7
y = 4x - 1 ⇒ y = 4(2) - 1 ; y = 8 - 1 ; y = 7
y = 2/7x ⇒ y = 2/7(2) ; y = 2/14 ; y = 1/7
y = 7/2x ⇒ y = 7/2(2) ; y = 7/4 ; y = 1 3/4
y = 7/x ⇒ y = 7/2 ; y = 3 1/2

Among the choices, only y = 4x - 1 is the direct variation that contains the ordered pair (2,7)

The direct relation that is a direct variation that contains the ordered pair (2, 7) is; y = (7/2)x

How too work with direct variation?

Given ordered pair is (2, 7)

We know that y = kx is valid for every direct relationship,

Determine k using the y and x, since k = y/x

k = 7/2

k = 3.5

Put the value for k in y = kx and you have y = 3.5x.

Therefore, the direct relation that is a direct variation that contains the ordered pair (2, 7) is y = (7/2)x

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33 is 50 percent of what number?

Answers

66 is the answer
Just double 33 because 50+50 equals 100
Which means 33+33 equals 66. Which in this case 66 is the 100%

Choose the polynomial written in standard form. x3y2 + 4x4y + 10x9 x4y2 + 4x4y5 + 10x2 xy2 + 4x3y8 + 10x2 x4y5 + 4x3y2 + 10x2 is it the second one?

Answers

If you would like to choose the polynomial written in standard form, you can do this like this:

x^3y^2 + 4x^4y + 10x^9
x^4y^2 + 4x^4y^5 + 10x^2
xy^2 + 4x^3y^8 + 10x^2
x^4y^5 + 4x^3y^2 + 10x^2

Writing the polynomial in standard form means that you have to write the terms by descending degree:
x^4y^5 + 4x^3y^2 + 10x^2

The correct result would be x^4y^5 + 4x^3y^2 + 10x^2.

The polynomial written in standard form is the second one: x⁴y² + 4x⁴y⁵ + 10x².

In standard form, polynomials are arranged in descending order of the exponents of the variables, and the coefficients are written without any exponents. The given polynomial follows this format with the terms arranged in descending order of the exponents of x and y, and the coefficients are written as 1, 4, and 10. The exponents for x are 4, 4, and 2, while the exponents for y are 2, 5, and 0 (since any variable raised to the power of 0 is 1).

In conclusion, the second polynomial x⁴y² + 4x⁴y⁵ + 10x² is written in standard form as it follows the arrangement of terms with descending exponents of variables and coefficients written without exponents.

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