Answer:
Step-by-step explanation:
y = 10x + 50
x ---> no of weeks
y - intercept = 50
Answer:
one comic book costs $5
Step-by-step explanation:
let cost of comic book = $x
let cost of vinyl = $y
according to the question:
6x = y + 3x
y = 6x - 3x
y = 3x (1)
y = $15 (2)
substituting the value of y from equation (2) into equation (1)
15 = 3x
x = 15/3 = 5
thus, cost of one comic book = $5
Answer:
5$.
Step-by-step explanation:
Let's denote the cost of one Sailor Moon comic book as x .
The cost of 6 Sailor Moon comic books is 6x.
According to the given information, the cost of a Nirvana vinyl plus 3 comic books is equal to the cost of 6 Sailor Moon comic books.
So, 15 + 3x = 6x , as the vinyl costs $15.
Now, let's solve for x :
Subtract 3x from both sides: 15 = 3x
Divide by 3: x = 5
Therefore, the cost of one Sailor Moon comic book is $5.
Answer:
When evaluating an algebraic expression the first thing you do is that you observe what would be the first operation applied on the expression.
In order to determine that you need to know the basic concept of PEMDAS
Where as
P stands for Parentheses (brackets)
E stands for exponents
M stands for multiplication
D stands for division
A stands for addition
S stands for subtraction
This is the order that needs to be kept in mind while solving the expression
Step 2: 5x – 3x – 5 = 20
Step 3: 2x – 5 = 20
Which of these is most likely the next step?
Answer:
a) f(16) = 42
b) f(16) = 54
c) f(16) = 162
d) f(16) = 30
Step-by-step explanation:
a) y = mx + b ∧ m = (f(8) - f(4))/(8-4) ⇒ m = (18 - 6)/(8 - 4) = 3
b = y - mx = 6 - 3(4) = 6 - 12 = - 6
f(16) = 3(16) - 6 = 42
b) y = kxⁿ ∧ f(4) = 6 = k4ⁿ ∧ f(8) = 18 = k8ⁿ ⇒ 18/6 = (k8ⁿ)/(k4ⁿ) ⇒ 3 = 2ⁿ
n = ㏑(3) / ㏑(2) ⇒ k = y/xⁿ ⇒ k = 6/4ⁿ = 2/3
f(16) = 2/3 × 16ⁿ = 54
c) y = aeᵇˣ ∧ f(4) = 6 = aeᵇ⁴ ∧ f(8) = 18 = aeᵇ⁸ ⇒ 18/6 = (aeᵇ⁸)/(aeᵇ⁴) ⇒ 3 = e⁴ᵇ
b = ㏑(3/4) ∧ a = y / eᵇˣ ⇒ a = 6 / e⁴ᵇ = 2
f(16) = 2eᵇ¹⁶ = 162
d) y = a㏑(bx) ∧ f(4) = 6 = a㏑(b4) ∧ f(8) = 18 = a㏑(b8)
⇒ 18 - 6 = a㏑(b8) - a㏑(b4) ⇒ 12 = a㏑(8b/4b) ⇒ a = 12 / ㏑(2)
f(4) = 6 = a㏑(4b) ⇒ b = (√2)/4
f(16) = a㏑(b16) = 30