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Answer:
Clinical study report. In medicine, a clinical study report (CSR) on a clinical trial is a document, typically very long, providing much detail about the methods and results of a trial. A CSR is a scientific document addressing efficacy and safety, not a sales or marketing tool; its content is similar to that of a peer-reviewed academic paper.
Explanation:
Related Questions
A nucleotide is the building block for a specific biomolecule. It is made up of a pentose sugar, a phosphate group, and a nitrogen base. One of its functions in polymer form is to store genetic information. Which two types of biomolecules are being described in this scenario? A . Nucleic acids and carbohydrates B . Nucleic acids and proteins C . Lipids and nucleic acids D. Proteins and lipids
What are index fossils used to determine?
In which of the following circumstances may animal work begin before receipt of IACUC approval? A. It is a continuing study awaiting three year renewal and for which the renewal protocol has been submitted to the IACUC. B. It is a small pilot study on non-AWAR species. C. It is a teaching activity that uses students' personally owned dogs and cats. D. There are no circumstances in which animal work may begin before IACUC approval.
All of the following statements are true, except: Question 24 options: 1) Renin is a hormone produced by JG cells 2) JG cells are present in the vasa recta 3) Macula densa cells are present in the ascendinng limb of henle's loop and distal convoluted tubule 4) The JG apparatus play a role in BP regulation
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I cant draw it for you but just look up images of what it looks like an just copy it from that.
Final answer:
Enzymes are affected by temperature and pH in their ability to catalyze chemical reactions. Extreme temperatures and pH values can denature enzymes, causing them to lose structure and function. The active site of an enzyme is sensitive to changes in the local environment, affecting its ability to bind substrates.
Explanation:
Enzymes are subject to influences by the local environment, including temperature and pH. Increasing or decreasing the temperature outside of an optimal range can affect the chemical bonds within the enzyme's active site, making them less suitable for binding substrates.
Extreme temperatures can cause enzymes to denature, losing their structure and function. Similarly, extreme pH values can also denature enzymes and affect their ability to bind substrates.
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The following life cycle stages do both complete and incomplete metamorphosis of insects have in common is adult. Thus, option B is correct.
What is larva?
Larva" is a stage in the life cycle of an insect among the following choices given in the question that a caterpillar represents. A Caterpillar represents the larva stage in the life cycle of an insect. The Caterpillar is most specifically Butterfly Larva. In this stage of the Butterfly life cycle, the Caterpillar spends most time eating, growing and shedding their exoskeleton.
Life cycle stages do both complete and incomplete metamorphosis of insects have in common is adult. A Caterpillar represents the larva stage in the life cycle of an insect. The Caterpillar is most specifically Butterfly Larva. Larva" is a stage in the life cycle of an insect among the following choices given in the question that a caterpillar represents.
Therefore, The following life cycle stages do both complete and incomplete metamorphosis of insects have in common is adult. Thus, option B is correct.
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Surface area to volume ratio, in simple means the size of surface area to the volume of substance that can pass through it at a particular time.
Amoeba and some bacteria are flat and have large surface area to volume ratio. So the diffusion rate is very high due to large surface area.
Where as humans have small surface area: volume so diffusion is very slow or does not take place at all.
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Answer:
food for less than a year ago today was a good day for you drink a lot of water and summer vacation visiting with you drink a lot of water and summer vacation visiting with you and your name and address in a bit in me in me in me in
unusually long bones and spinal curvature, as well as vision, cardiac, and respiratory
problems. The syndrome tends to become increasingly severe over time. The following
pedigree shows inheritance of Marfan syndrome in a multigenerational famil (5)y.
8. Wh
5
9. Tra
Th
the
III
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wi
a) How is this syndrome inherited (dominant, recessive or sex-linked)?
2
b) Can you determine individual 114's genotype? Explain.
b.
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c) Individual III and I12 are considering having another child. What is the probability that
this child will have Marfan syndrome? Explain using a Punnett square.
Answers
Answer:
The correct answers are :
a) syndrome Could be autosomal recessive or dominant
b) If it is autosomal recessive - no,
and if it is autosomal dominant - yes, (II-4) - Aa
c) probability of the another child :
Autosomal recessive: Aa x aa 50%
Autosomal dominant: aa x Aa 50%
Explanation:
a) Marfan syndrome could be inherited by the autosomal recessive or dominant pattern on the basis of following characters according the pedigree gives:
- transmitted by anyone regardless of sex male or female
- characters should not skip generations
- A cross between affected person and an normal person should produce approximately half of the affected offspring.
b) Assuming that autosomal dominant than there is two possibilities :
1) in case of I 2 genotype is heterozygous which means it is Aa which will produce Aa Aa aa and aa with crossing with aa as per pedigree however it is incorrect according the offspring given in II.
2) If I 2 is AA- then offspring will be Aa, Aa, Aa and Aa. which is correct according the pedigree.
thus, the answer is - Aa
c) the punnet square as per question is :
II2 - Aa × II1 - aa
A a
a Aa aa
a Aa aa
similar with autosomal recessive
thus, the correct answer is 2 out of 4 that is 50%
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Answer:
0.549 is the frequency of the F allele.
0.495 is the frequency of the Ff genotype.
Explanation:
FF or Ff genotypes determine freckles, ff determines lack of freckels.
In this class of 123 students, 98 have freckles (and 123-98= 25 do not).
If the class is in Hardy-Weinberg equilibrium for this trait, then the genotypic frequency of the ff genotype is:
q²= 25/123
q²=0.203
q=
q= 0.451
q is the frequency of the recessive f allele.
Given p the frequency of the dominant F allele, we know that:
p+q=1, therefore p=1-q
p=0.549 is the frequency of the F allele.
The frequency of the Ff genotype is 2pq. Therefore:
2pq=2×0.549×0.451
2pq=0.495 is the frequency of the Ff genotype.
Final answer:
The frequency of the dominant allele, F, in this class is 0.55. The frequency of the heterozygous genotype, Ff, is 0.495. This is calculated using Hardy-Weinberg equilibrium and observed phenotype frequencies.
Explanation:
To start, we need to calculate the frequency of the recessive allele, f, which is easily calculated as those who do not have freckles. From a total of 123 students, 98 have freckles, leaving 25 students with no freckles, which represents individuals who are homozygous for the recessive trait (ff). As these are the only individuals we can be sure of, we take the square root of their frequency to get the frequency of the recessive allele, q. In this case, q = sqrt(25/123) = 0.45. To find the frequency of the dominant allele, p, we subtract q from 1 (because p + q = 1), so p = 1 - q = 0.55.
Next, we'll calculate the frequency of the heterozygous genotype Ff.
Using Hardy-Weinberg equilibrium, we know this is represented by 2pq. Hence, the frequency of genotype Ff would be 2 × 0.55 × 0.45 = 0.495.
This process offers an example of applying the principles of population genetics and Hardy-Weinberg equilibrium to determine the likely genotype frequencies in a given group of individuals based on observed phenotype frequencies.
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Active transport.
Hope this helps!