Isabella solved the following equation: 4x − 2x + 8 = 6(x + 4) Step Work Justification 1 4x − 2x + 8 = 6x + 24 Distributive Property 2 2x + 8 = 6x + 24 Combine like terms 3 −4x + 8 = 24 Addition Property of Equality 4 −4x = 16 Subtraction Property of Equality 5 x = −4 Division Property of Equality Which step has an incorrect justification?

Answers

Answer 1

Answer:

Answer:

step 3 has incorrect justification.

Step-by-step explanation:

because it was combine like terms but 8 is still in left hand side. So,combine like terms 3 has incorrect justification.

Answer 2

Answer:

Answer:

Step 3

Step-by-step explanation: Combine like terms but 8 is still in the left side, so combine like terms 3 has incorrect justification.

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In math, I am stuck on a question: What is 83/9's mixed number or whole number?

Answers

83/9 is an improper fraction. Meaning, the numerator is greater than the denominator.

If you were to convert 83/9 into a mixed number (a number with a whole number and a fraction) you would get 9 and 2/9

83/9 is a improper fraction

when it is 9 2/9 it is a mixed and the numbers like 1, 2, 3,4 are whole because no fractions are there

How does this model demonstrate the Pythagorean Theorem?Three squares whose corners touch so that the respective edges form a triangle. The smallest square has a side labeled six and is made up of thirty-six smaller squares. The largest square has a side labeled ten and is made up of one hundred smaller squares. The third square has a side labeled eight and is made up of sixty-four smaller squares.

A.
The sum of the lengths of the shortest and the longest sides is equal to twice the length of the middle side. So double the length of the longer leg of any right triangle is equal to the sum of the shorter leg and the hypotenuse.

B.
The sum of the area of the two smaller squares is equal to the area of the larger square. So the sum of the lengths of the two legs of any right triangle squared is equal to the length of the hypotenuse squared.

C.
The sum of the area of the smallest and the largest squares is equal to the area of the middle square. So the sum of the lengths of the shorter leg and the hypotenuse of any right triangle squared is equal to the length of the middle leg squared.

D.
The length of the longest side minus two equals the length of the middle side. The length of the middle side minus two equals the length of the shortest side. So the length of the short leg of any right triangle is equal to the length of the middle leg minus 2, and the length of the hypotenuse is equal to the length of the middle leg plus 2.

Answers

" B is your best choice but it is very badly stated. this gives an Example of the Pythagorean theorem. it does Not demonstrate it. B is written incorrectly, it should say "sum of squares of the lengths of the legs" Not "sum of the lengths of the two legs of any right angle squared"

Jake sold 39 tickets to the the school fair and Jeanie sold 12 tickets. What is the ratio in the simplest for of the number of tickets Jeanne sold to the number of tickets Jake sold?a. 13/4
b.39/12
c.12/39
d.4/13

sorry if I am asking so many questions

Answers

$(number\ of\ tickets\ Janne)/(number\ of\ tickets\ Jake)=(12)/(39)=(12:3)/(39:3)=(4)/(13)\n\nAnswer:\boxed{D.\ (4)/(13)}$

jake:Jeanie
39:12
39=3*13
12=3*2*2
so (3*13)/(3*2*2)
we can factor out the 3/3 or 1
so 13/4
jake:Jeanie is 13/4

A store sells 8 cans of nuts for $20 how much would it cost to buy 7 cans of nuts?

Answers

The answer to this question is 17.5. Because i divided 20 by 8 and got 2.5 and times it by 7.
17.5

To get your answer you divide $20 by 8 to get $2.50 then you multiply it by 7 to get $17.50. Hope I helped

What is

Please answer

Answers

Answer:

$\mathrm{Decimal:\quad }\:38.8$

Step-by-step explanation:

$(\left(3-11\right)^2+\left(5-11\right)^2+\left(13-11\right)^2+\left(14-11\right)^2+\left(20-11\right)^2)/(5)\n\left(3-11\right)^2+\left(5-11\right)^2+\left(13-11\right)^2+\left(14-11\right)^2+\left(20-11\right)^2=194\n\left(3-11\right)^2+\left(5-11\right)^2+\left(13-11\right)^2+\left(14-11\right)^2+\left(20-11\right)^2\n\left(3-11\right)^2=64\n\left(3-11\right)^2\n\mathrm{Subtract\:the\:numbers:}\:3-11=-8\n=\left(-8\right)^2$

$\mathrm{Apply\:exponent\:rule}:\quad\left(a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}\n\left(-8\right)^2=8^2\n8^2=64\n\left(5-11\right)^2=36\n\left(5-11\right)^2\n\mathrm{Subtract\:the\:numbers:}\:5-11=-6\n=\left(-6\right)^2\n\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}\n\left(-6\right)^2=6^2\n=6^2\n6^2=36\n\left(13-11\right)^2=4\n\left(13-11\right)^2\n\mathrm{Subtract\:the\:numbers:}\:13-11=2\n=2^2\n2^2=4\n\left(14-11\right)^2=9$

$\mathrm{Subtract\:the\:numbers:}\:14-11=3\n=3^2\n3^2=9\n\left(20-11\right)^2=81\n\left(20-11\right)^2\n\mathrm{Subtract\:the\:numbers:}\:20-11=9\n=9^2\n9^2=8\n=64+36+4+9+81\n\mathrm{Add\:the\:numbers:}\:64+36+4+9+81=194\n=194\n=(194)/(5)\n\mathrm{Decimal:\quad }\:38.8$