PHYSICS HIGH SCHOOL

A ball is shot up from the ground with an initial vertical velocity of 30 m/s. What is the velocity of the ball as it reaches its highest point

Answers

Answer 1

Answer:

Answer:

0 m/s

Explanation:

At the highest point, the vertical velocity is 0 m/s.

There's no horizontal velocity.

So the total velocity at the highest point is 0 m/s.

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A minimum price, set by the government, that must be paid for a good or service is called a _____. A. price wall B. price floor C. price field D. price ceiling
Using newton's second law of motion, if the force on an object is 20n, and its mass is 5g, what is the acceleration? Can someone explain to me in a simple way how to do this? I have tried but the formulas I see are confusing. Thank you :)
Air trapped in the fur of the caribou’s coat functions as _____.
When I bumped the table, the coffee in my cup spilled out. Newton's _____ law explains this reaction.
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A 0.5 kg ball is dropped from rest at a point 1.2m above the floor. The ball rebounds straight upward to a height of 0.7m. What are the magnitude and direction of the impulse of the net force applied to the ball during the collision with the floor.

Answers

Answer:

4.281 kgm/s upward

Explanation:

Impulse:This can be defined product of force and time. The S.I unit of impulse is Ns.

From Newton's second law of motion,

Impulse = Change in momentum.

I = mΔv....................... Equation 1.

Where m = mass of the ball, Δv = change in velocity of the ball

and Δv = v -u

Where u = velocity of the ball before it hit the floor, v = velocity of the ball after if hit the floor

I = m(v-u) -------------- Equation 2

But

the initial kinetic energy of the ball = potential energy at the initial height (1.2 m above)

1/2mu² = mgh₁

Where h₁ = initial height. or height of the ball before collision

making u the subject of the equation,

u = √(2gh₁)........................ Equation 3

Where h₁ = 1.2 m g = 9.81 m/s²

Substitute into equation 3

u = √(2×1.2×9.81)

u =√(23.544)

u = -4.852 m/s.

Note: u is negative because the ball was moving downward at the first instance.

Similarly,

v = √(2gh₂)............................. Equation 3

h₂ = height of the ball after collision

Given: h₂ = 0.7 m, g = 9.81 m/s²

Substitute into equation

v = √(2×9.81×0.7)

v = √13.734

v = 3.71 m/s.

Also given: m = 0.5 kg,

Substituting into equation 2

I = 0.5(3.71-(4.852)

I = 0.5(8.562)

I = 4.281 kgm/s. Upward.

Thus the impulse = 4.281 kgm/s upward

To test the hypothesis that plants grow faster in green light, a student set up 3 of the same type of plants. She placed the first plant under a green light, the second plant under a regular light bulb, and the third plant under a red light. What is the dependent variable in this experiment?

Answers

The dependent variable is the speed of plant growth, and the-plant's general health and welfare.

The hypothesis is defective. It should talk about whether the plant is
DEPRIVED of any green light. The way the experiment is described,
the results won't be clear. The "regular" light bulb has a lot of green
wavelengths in it, along with a lot of other stuff that the plant may or
may not be interested in. So the plant's response to the green light
AND the 'regular' light may be very similar.

Moons orbit planets and planets orbit theSun. Is Kepler’s constant the same for both
circumstances?

Answers

What Kepler's constant ? ? ! ?

The only constant in Kepler's laws is in the third one, where it says something to the
effect that (square of a body's period) / (cube of its distance from the central body)
is a constant.

That means it's a constant for multiple little ones orbiting the same central body.
But it's not the same constant for other central bodies.

It's one constant for the planets, asteroids, and comets orbiting the sun.

It's a different constant for the moon, TV satellites, weather satellites,
and military satellites orbiting the Earth.

John is traveling north at 20 meters/second and his friend Betty is traveling south at 20 meters/second. If north is the positive direction, what are John and Betty's speeds?

Answers

Answer:

The John 's speed is 20 m/s.

The Betty's speed is 20 m/s

Explanation:

Given that,

John is traveling north at 20 meters/second and his friend Betty is traveling south at 20 meters/second.

We need to calculate the John and Betty's speeds

We know that,

The speed is a scalar quantity. its has only magnitude.

Hence, The John 's speed is 20 m/s.

The Betty's speed is 20 m/s

Both of their speeds are 20 m/s.
Direction is not involved in describing speed.

Sound waves, water waves, and light waves are all alike in that they all

Answers

Sound and water waves are longitudinal waves, they require a medium to travel through and occilate particles 90 degrees to the wave motion
Light is a transverse wave. It doesnt require a medium to travel through.
All three reflect, refract and diffract

Light is difficult to think of because it acts in ways which waves cannot explain in some cirumstances. It acts like a particle (called photons) in some conditions, but acts like a normal sound or water wave does in others. Try not to get too caught up in light being a wave or a particle because even physists dont know how to explain it yet.

Final answer:

Sound waves, water waves, and light waves all spread out from a source and can transfer energy without transporting matter. They obey the principle of superposition and can be reflected, refracted, and diffracted. Examples also in many practical scenarios support the concept.

Explanation:

All sound waves, water waves, and light waves share some common properties as they are all types of wave motion. These waves all spread out from a source and can transfer energy without transporting matter. They also follow the principle of superposition, where the resultant wave amplitude is the sum of the individual wave amplitudes. Additionally, they can be reflected, refracted, and diffracted.

For example, when throwing a pebble into a pond, the water waves spread out in rings from where the pebble was dropped (the source). The waves transfer the energy of the impact through the water, yet the water molecules themselves don't travel in the direction of the wave's motion—they merely move up and down.

The same principles apply to sound waves and light waves, though the type of energy transferred and the manner in which they're affected by the medium they're passing through can differ.