What is the slope of a line
parallel to the line 4x – 3y = 16?

Answers

Answer 1

Answer: "Parallel" means the same, which means the slope you find. The formula for slopes is y=mx+b, so we need to put this equation in the right order for that. ('m' is the slope.)
Add 4x to each side, and get -3y=16+4x. Rearrange it to get it in the right order (y=mx+b).
This is -3y=4x+16. So the number in front of 'x' is 'm', which is the slope. You never actually see 'm', it is represented by a number. So four is the slope.

Answer 2

Answer:

Answer:

the given eqaution y=mx+b represents a straight line with slope m and the y intercept b.

So now let us see how to graph the equation y=5x+(-6):

Putting x=0, we get y=-6 which implies one coordinate is (0,-6)

Now putting x=1, we get y=-1 which implies the coordinate is (1,-1)

Putting x=2, we get y=4. So the coordinate is (2,4)

Step-by-step explanation:

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Find an equation of the line satisfying the given conditionsThrough (6,4); perpendicular to 3X + 5Y =38

Solve-picture question

Answers

The answer is 1/3. Basically start at A, you go up one. Then count over to B and it's 3 spaces over, so you get 1/3.

it's D 1/3 cause your going up 1 and over 3 so that should give you a positive cause the line is going up instead of down . now on the other hand if the line was going down it would me -1/3 cause went down one and over negative three, but in ur case it's ↓

D.) 1/3

-Hope this helped you im 100% sure this is right . :)

The lateral area of a cube is 36 square inches. How long is each edge?

Answers

The length of the edge of the given cube that has a lateral area of 36 square inches is: 3 inches.

What is the Lateral Area of a Cube?

Lateral area of a cube = 4a², wherea is the length of each edge of the cube.

Given the parameters:

Lateral area = 36 square inches
Length of each edge = a = ?

4a² = 36

a² = 36/4

a² = 9

a = 3 inches.

Length of each edge of the cube = 3 inches.

Learn more about lateral area of cube on:

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Cubes have three square sides. The area of one side is the edge length squared:
36 = L^2
L = sqrt(36) = 6
The volume of a cube is edge length cubed:
V = L^3 = 216 cubic inches

The following data shows the annual rainfall amounts for Albuquerque over the past ten years. Which of these values should be considered outliers? Precipitation (inches): 9.4, 9.1, 9.8, 10.9, 9.2, 10.7, 9.1, 8.1, 9.1, 9.4

A. 8.1
B. 10.9
C. 8.1 and 10.9
D. None of the above

Answers

Precipitation (inches): 9.4, 9.1, 9.8, 10.9, 9.2, 10.7, 9.1, 8.1, 9.1, 9.4

Arrange in ascending order:
8.1, 9.1, 9.1, 9.1, 9.2, 9.4, 9.4, 9.8, 10.7, 10.9

The outlier is 10.9

Mean = 9.48
Median = 9.3
Q1 = 9.1
Q3 = 9.8
IQR = 0.7
Lower fence: 8.05
Upper fence: 10.85

Solve the following by substitution : -

x + y = 10
x - y = 5

Answers

$\begin{cases} x + y = 10 \n x - y = 5 \end{cases}\n \n \begin{cases} y = 10 -x\n x - y = 5 \end{cases}\n \n \begin{cases} y = 10 -x\n x - (10-x) = 5 \end{cases}\n \n \begin{cases} y = 10 -x\n x - 10+x = 5 \end{cases}\n \n$

$\begin{cases} y = 10 -x\n 2x - 10 = 5 \end{cases}\n \n\begin{cases} y = 10 -x\n 2x = 5 +10 \end{cases}\n \n \begin{cases} y = 10 -x\n 2x =15 \ \ /:2 \end{cases}\n \n \begin{cases} y = 10 -x\n x =(15)/(2) \end{cases}\n \n$

$\begin{cases} y = 10 - 7(1)/(2)\n x =7(1)/(2) \end{cases}\n \n \begin{cases} y = 2(1)/(2)\n x = 8(1)/(2) \end{cases}\n \n$

Your question is -

x + y = 10
x - y = 5

Now, let us solve this system by the substitution method.

According to equation 2 ,

x - y = 5

thus, x = 5 + y

Substituting the value of x in equation 1,

(5 + y) + y = 10

5 + 2y = 10

2y = 10 - 5 = 5

thus, y = 5/2

Substituting the value of y in value of x,

x = 5 + y

= 5 + 5/2

= 15/2

Thus, x = 15/2 ( or 7.5) y = 5/2 ( or 2.5)

What set of reflections would carry triangle ABC onto itself?

Answers

The correct answer is y-axis, x-axis, y-axis, x-axis. The y-axis is the vertical line, and the x-axis is the horizontal line. If the triangle is in the upper right quadrant, and is reflected first over the y-axis, it will be in the upper left quadrant. Then, when the triangle is reflected again over the x-axis, it will be in the lower left quadrant, diagonal to the initial triangle. When the triangle is again reflected over the y-axis, it will be in the lower right quadrant, below the initial triangle. Finally, when the triangle is reflected over the x-axis, it will be on top of the original triangle in the upper right quadrant.

Increase 92 by 35%. need full explanation