MATHEMATICS HIGH SCHOOL

Make x the subject of the formula r = \sqrt{ (ax - p)/(q + bx) }

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Answers

Answer 1
Answer:

Answer:

\boxed{x = \frac{p + q {r}^(2) }{a - b {r}^(2) } }

Step-by-step explanation:

Solve \: for \: x: \n = > r = \sqrt{ (ax - p)/(q + bx) } \n \n </p><p>r = \sqrt{ (ax - p)/(q + bx) } \: is \: equivalent \: to \: \sqrt{ (ax - p)/(q + bx) } = r :\n = > \sqrt{ (ax - p)/(q + bx) } = r \n \n Raise \: both \: sides \: to \: the \: power \: of \: two: \n = > (ax - p)/(q + bx) = {r}^(2) \n \n Multiply \: both \: sides \: by \: (q + b x): \n = > ax - p = {r}^(2) (q + bx) \n \n Expand \: out \: terms \: of \: the \: right \: hand \: side: \n = > ax - p = q {r}^(2) + b {r}^(2)x \n \n Subtract \: b {r}^(2)x - p \: from \: both \: sides: \n = > x(a - b {r}^(2) ) = p + q {r}^(2) \n \n Divide \: both \: sides \: by \: a - b {r}^(2) : \n = > x = \frac{p + q {r}^(2) }{a - b {r}^(2) }

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In a biological lab, the cell growth rate of two different organisms is tracked and recorded each week. Given the growth rate, the number of organisms can be determined using the following equations: s(x) = 100 + 23x
m(x) = 90(1.2x)

Complete the table of values.
x 100 + 23x 90(1.2x)
0
1
2
3
4
5
Use the table to determine at approximately which point the number of cells will be the same for each organism.
Graph the system of equations, and show the point of intersection.
Explain what the points graphed for each line represent.
Explain how you can determine the solution to the equation 100 + 23x = 90(1.2x) using the graph from part c.
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Answers

wow that's too much work!!! is this a table or printout?

s(x) = 100 + 23xs(x) = 100 + 23x

m(x) = 90(1.2x)

Help solve with subsitution x+y=1, 2x+3y=-4

Answers

{   x + y = 1    * ( - 2 )
  2 x + 3y = -4

- 2 x - 2 y = - 2
  2 x + 3 y = - 4
_______________
         y = - 6

Subsititute y = - 6 

2 x + 3 y = - 4

2 x + 3 * (-6) = -4

2 x - 18 = - 4

2 x = - 4 + 18

2 x = 14

x = 14 / 2

x = 7

The solution  to the system of equations are:

x = 7 and y = - 6

hope this helps!

you have a 1.5 litre bottle of water and drink 295 millilitres and your friend drinks 135 millilitres, how much water is left

Answers

1,070 milliliters of water is left

a store mixes red fescue worth $12 per pound and chewings fescue worth $16 per pound. The mixture is to sell for $15 per pound. Find out how much of each should be used to make a 552- pound mixture.

Answers

Answer is: 414 pounds of red fescue and 138 pounds of chewings fescue is needed to produce 552 pounds of mixture.

Explanation:
x - how much of red fescue is needed for one pound of mixture
y - how much of chewings fescue is needed for one pound of mixturex*12+ y*16 = 15x + y = 1
so, x=1-y
putting it into first line:(1-y)*12 + y*16 = 15
12 - 12*y + 16*y = 15
4*y = 3
y=3/4
so, x= 1-3/4; x=1/4So to produce 552 pounds of mixture we need..To produce 1 pound of mixture we need: 3/4 pound of red fescue and 1/4 pound of chewing fescue so to produce 552 pounds of miture we need:
552*3/4 - red fescue, which is 414 pounds needed
and
552/4 - chewings fescue, which is 138 pounds needed

Answer:

e+ f = 8 (total solution)

8e + 56f = 20*8 (total saline)

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e+ f = 8

e + 7f = 20

------------ Subtract

-6f = -12

f = 2

e = 6

Which of the following can be a solution to the inequality below?2x > 6.
Pls send help

Answers

Answer:

x>3

Step-by-step explanation:

you divide both sides by 2 then you get three. The sign remains the same.

Nian's graden i 4 1 5 meters long 3 under 10 meter wide what is the area of nians garden

Answers

Answer:

14 meters squared

Step-by-step explanation:

The dimensions of this rectangle are 4 1/5 meters by 10/3 meters. The area of a rectangle is: A=lw, where l is the length and w is the width.

Here, l = 4 1/5 and w = 10/3. We simply multiply them together:

A = (4 1/5) * (10/3)

Let's turn 4 1/5 into an improper fraction to make things easier: 4 1/5 = 21/5. Now:

A = (21/5) * (10/3) = 210/15 = 14

The area is 14 meters squared.

Hope this helps!

Answer:

14m²

Step-by-step explanation:

Area = length × width

length = 4⅕ = 21/5

width = 10/3

Area = 21/5 × 10/3

= 14m²
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