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3. A metal fabricating plant currently has five major pieces under contract each with a deadline for completion. Let X be the number of pieces completed by their deadlines, and suppose it's PMF p(x) is given by x 0 1 2 3 4 5 p(x) .05 .1 .15 .25 .35 .1 (a) Find and plot the CDF of X. (b) Use the CDF to find the probability that between one and four pieces, inclusive, are completed by their deadline

Answers

Answer 1

Answer:

Answer:

a) The cumulative distribution function would be given by:

x 0 1 2 3 4 5

F(X) 0.05 0.15 0.30 0.55 0.9 1

b) $P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85$

And replacing we got:

$P(1 \leq X \leq 4) =0.85$

Step-by-step explanation:

For this case we have the following probability distribution function given:

x 0 1 2 3 4 5

P(X) 0.05 0.1 0.15 0.25 0.35 0.1

We satisfy the conditions in order to have a probability distribution:

1) $\sum_(i=1)^n P(X_i)=1$

2) $P(X_i) \geq 0, i=1,2,..,n$

Part a

The cumulative distribution function would be given by:

x 0 1 2 3 4 5

F(X) 0.05 0.15 0.30 0.55 0.9 1

Part b

For this case we want to find this probability:

$P(1 \leq X \leq 4) = F(4) -F(0) =0.9-0.05 = 0.85$

And replacing we got:

$P(1 \leq X \leq 4) =0.85$

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Lines m and n are parallel. The equation of line m is y=3x+3. What is the equation of line n?

Answers

The equation for line n is y = 3x + c

What is the equation of a straight line ?

An equation of a straight line is given by y = mx+c, where m is the slope and c is the intercept on the y axis.

In the question it is given that

Lines m and n are parallel to each other.

The equation of line m is y=3x+3

The equation of line n =?

The parallel lines m an n will have same slope but different intercept.

So the slope in the line equation y=3x+3 is 3

m = 3

Taking c as the intercept by the line n on y axis.

The equation for line n is y = 3x + c

To know more about equation of a straight line

brainly.com/question/959487

#SPJ2

Answer:

y=3x-1

Step-by-step explanation:

You would have to change the y-intercept but that's all. Also, I put this answer into my ttm and got it right.

Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ability to hit the ball so far. Designers, therefore, have proposed that new golf courses need to be built expecting that the average golfer can hit the ball more than 230 yards on average. A random sample of 177 golfers show that their mean driving distance is 230.7 yards, with a standard deviation of 41.8.1. Set up the null and alternative hypotheses to test for the designers belief.
a. H0 : µ ≥ 230 versus Ha : µ < 230
b. H0 : µ = 230.7 versus Ha : µ ≠ 230.7
c. H0 : µ ≥ 230.7 versus Ha : µ < 230.7
d. H0 : µ ≤ 230.7 versus Ha : µ > 230.7
e. H0 : µ ≤ 230 versus Ha : µ > 230
2. Find the value of the standardized test statistic.
a. 0.125
b. -0.125
c. 0.223
d. -0.7
e. 0.7
3. Find the P-value for the above mentioned test.
a. 0.8237
b. 0.0228
c. 0.5871
d. 0.4118
e. 0.0871

Answers

Answer:

a) e) H0 : µ ≤ 230 versus Ha : µ > 230

b) $t=(230.7-230)/((41.8)/(√(177)))=0.223$

c. 0.223

c) $p_v =P(t_((176))>0.223)=0.4118$

d. 0.4118

Step-by-step explanation:

Information given

$\bar X=230.7$ represent the sample mean

$s=41.8$ represent the sample standard deviation

$n=177$ sample size

$\mu_o =230$ represent the value to verify

t would represent the statistic

$p_v$ represent the p value

Part a

We want to verify if the true mean is higher than 230 yards, the system of hypothesis would be:

Null hypothesis: $\mu \leq 230$

Alternative hypothesis: $\mu > 230$

The best option would be:

H0 : µ ≤ 230 versus Ha : µ > 230

Part b

The statistic is given by:

$t=(\bar X-\mu_o)/((s)/(√(n)))$ (1)

Replacing the info given we got:

$t=(230.7-230)/((41.8)/(√(177)))=0.223$

Part c

The degrees of freedom are:

$df=n-1=177-1=176$

The p value would be given by:

$p_v =P(t_((176))>0.223)=0.4118$

d. 0.4118

The area of a circle is 127 square units. What would the circumference of the circle be?

Answers

Answer:

Area of the circle = π×r²

127 = 3.14 × r²

=> 127/3.14 = r²

=> 40.44 = r²

=> √40.44 = r

=> r = 6.35

Circumference of the circle = 2πr

= 2×22/7×6.35

=279.4/7

= 39.91

= 40 units

) At a certain college, students are allowed to choose between online and in-person learning. 70% of the students choose online learning and 30% choose to come to campus for in-person instruction. Assume that the probability that a person studying online will contract the coronavirus is .02 and the probability that a person attending class in-person contracts the virus is .35 . (a) What is the probability that a person attending this college (either online or in-person) will contract the virus

Answers

Answer:

Probability = 0.119

Step-by-step explanation:

P (Coronavirus) = P(Person online & corona) or P(Person offline & corona)

(0.70 x 0.02) + (0.30 x 0.35)

0.014 + 0.105

0.119

The number line below represents which combined inequality?number line with a closed circle on negative 4 and 3 with shading in between

x greater than or equal to −4 and x less than or equal to 3
x greater than or equal to −4 or x less than or equal to 3
x less than or equal to −4 and x greater than or equal to 3
x less than or equal to −4 or x greater than or equal to 3