lled a 12:3:112:3:1 ratio. Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2:131F2:131 white squash, 3434 yellow squash, and 1010 green squash. Are these data consistent with a 12:3:112:3:1 dominant epistatic model of genetic inheritance( white being dominant)? The null hypothesis for the chi‑square goodness‑of‑fit test is

Answers

Answer 1

Answer:

Here is the full question:

When a species has several variants of a phenotype passed on from generation to generation, we can form a hypothesis about the genetics of the trait based on Mendelian theories of genetic inheritance. For example, in a two-gene dominant epistatic model, the first gene masks the effect of the second gene, leading to the expression of three phenotype variants. Crossing the dominant and recessive homozygote lines would result in a second generation represented by a mix of dominant, intermediate, and recessive phenotype variants in the expected proportions: and respectively, also called a 12:3: 1 ratio.

Such a model can provide the basis for the null hypothesis in a significance test. A cross of white and green summer squash plants gives the number of squash in the second generation F2: 131 white squash, 34 yellow squash, and 10 green squash. Are these data consistent with a 12: 3: 1 dominant epistatic model of genetic inheritance( white being dominant)?

The null hypothesis for the chi-square goodness-of-fit test is

Answer:

The null hypothesis for the chi-square goodness-of-fit test is :

$\mathbf{H_o:p_(white) = (12)/(16), p_(yellow) = (3)/(16); p_(green) = (1)/(16) }$

Step-by-step explanation:

The objective of this question is to state the null hypothesis for the chi-square goodness-of-fit test.

Given that:

There are three colors associated with this model . i,e White , yellow and green and they are in the ratio of 12:3:1

The total number of these color traits associated with this model = 12 + 3 + 1 = 16

Thus ;

The null hypothesis for the chi-square goodness-of-fit test is :

$\mathbf{H_o:p_(white) = (12)/(16), p_(yellow) = (3)/(16); p_(green) = (1)/(16) }$

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Answer:

162.56 cm

Step-by-step explanation:

also you can use a conversion calculator for faster results too

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Your office is raising money for charity by collecting aluminium cans for recycling. They get 36p per kilo of cans. A kilo is approximately 72 cans. They have collected 8645 cans How much money have they raised?

Answers

8645 cans divided by 72 per kilo is 120.069 kilos of cans
120.069 kilos times 0.36 pounds= 43.22 pounds raised

Answer:

£43.23

Step-by-step explanation:

8645 cans divided by 72 per kilo is 120.069 kilos of cans

120.069 kilos times 0.36 pounds

Rounded up to 43.23

A circle has a radius of five an arc in the circle has a central angle of 162 what is the length of the arc enter an exact answer in terms of pie or use with 3.14 for pie and enter your answer as a decimal