PHYSICS HIGH SCHOOL

Minerals mined for titanium are

Answers

Answer 1

Answer:

Answer: Minerals that are mined for titanium are ilmenite and rutile.

Explanation:

Titanium is the 22nd element of the periodic table. It symbol is "Ti"

The minerals which are mined to extract titanium are ilmenite $(FeTiO_3)$ and Rutile $(TiO_2)$

Titanium is extracted from ilmenite with a process of acid leaching using fluorosilicic acid $(H_2SiF_6)$

Titanium is extracted from rutile by converting it into titanium(IV) chloride, and then reducing it to titanium using either magnesium or sodium.

Therefore, Mineral that are used to mine Titanium are ilmenite and rutile.

Answer 2

Answer: They are ilmenite, leucoxene, and rutile.

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A rubber ball moving at a speed of 5 m/s hit a flat wall and returned to the thrower at 5 m/s. Which statementcorrectly describes the momentum of the rubber ball?a. Its magnitude increased and its direction changed.b. Its magnitude increased but its direction remained the same.c. Its magnitude remained the same but its direction changed.d. Its magnitude and its direction both remained the same.
Hiytreawretyuiouytrdsedrtyuiougfdgiojgfchjkljhjkl;kjhbjkljhbnjknjbnjknbvnm,nbm,nmjj
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A compound microscope that has an eyepiece lens with a magnification of 10X and an objective lens with a magnification of 25X will have a total magnification of __________ times.

The energy transferred from the water in the kettle to the surroundings in 2 hours is46 200 J.

The mass of water in the kettle is 0.50 kg.

The specific heat capacity of water is 4200 J/kg °C.

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Calculate the average power output from the water in the kettle to the surroundings in 2 hours

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The Last one ☝️ I think

You have a very old service manifold and the high-pressure gauge on this service manifold set has a continuous scale, calibrated to read from 0 to 500 psig. TRUE or FALSE.

Answers

That statement is FALSE

the scale that calibrated to read from 0 to 500 is usually the standard used by the new kind of service

the older one usually only take up to 340

hope this helps

Three friends tie three ropes in a knot and pull on the ropes in different directions. Adrienne (rope 1) exerts a 20-N force in the positive x-direction, and Jim (rope 2) exerts a 40-N force at an angle 53∘ above the negative x-axis. Luis (rope 3) exerts a force that balances the first two so that the knot does not move.a. Use equilibrium conditions to find F LonKx and F LonKy.
b. Use equilibrium conditions to determine the magnitude of F⃗ LonK.
c. Use equilibrium conditions to determine the angle θ that describes the direction of F⃗ LonK. Use positive values if the force is directed above the positive x-axis and negative values if it is directed below the positive x-axis.
d. Construct a force diagram for the knot.

Answers

Answer:

Part a)

$F = 4 \hat i - 32\hat j$

Part b)

Magnitude of the force is given as

$F = 32.2 N$

Part c)

As we know that Y component of the force is negative so here the force is directed below the X axis

$\theta = -82.9 degree$

Explanation:

Part a)

Adrienne apply the force of 20 N along +X direction and Jim apply force of 40 N at 53 degree above negative X axis

so we will have

$F_1 = 20 \hat i$

$F_2 = 40cos53(-\hat i) + 40 sin53(\hat j)$

$F_2 = -24\hat i + 32\hat j$

now let say the force exerted by Luis is F such that sum of all forces must be zero

now we have

$F_1 + F_2 + F_3 = 0$

so we have

$20\hat i -24\hat i + 32\hat j + F = 0$

$-4\hat i + 32\hat j + F = 0$

$F = 4 \hat i - 32\hat j$

Part b)

Magnitude of the force is given as

$F = √(4^2 + 32^2)$

$F = 32.2 N$

Part c)

As we know that Y component of the force is negative so here the force is directed below the X axis

So here we have

$tan\theta = -(32)/(4)$

$\theta = -82.9 degree$

Electromagnetic induction occurs only when the current in the primary coil is constant. true or false

Answers

yes its True that Electromagnetic induction occurs only when the current in the primary coil is constant.

Two identical capacitors are arranged in a circuit. What is the ratio of the equivalent capacitance of the circuit when the capacitors are in series to that when they are in parallel?

Answers

Ceq in series is calculated by 1/C1 + 1/C2 + ....
While, in parallel, Ceq= C1 + C2 + ...

So the ratio is 1/Ceq = Ceq

PLEASE HELP!! ILL MARK BRAINLYEST!!New substances are produced in a chemical change.

True
False

Answers

The Answer is true hope this helps

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