If A is to the left of B on a number line, which of the following must be true?A.) A<B
B.) A=B
C.) A>B

Answers

Answer 1

Answer:

Answer:

A. $A<B$

Step-by-step explanation:

We have been given that A is one the left of B on a number line. We are asked to choose the correct option from our given choices about the given condition.

We know that the value of numbers on number line increases from left to right.

Since A is on the left of B on number line, therefore, the value of a must be less than B and option A is the correct choice.

Answer 2

Answer: A.) A <B I hope i could help you.

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What's the answer 2795÷43
How to plot the point (3,-7) on the coordinate plane
9x+10=11x-10Please show work
Change 50% to a decimal, then a fraction. 0.05, 1/20 0.5, 1/2 0.05, 1/2 0.5, 1/20

Write the equation in slope-intercept form.

2/3(6y+9)=3/5(15x-20)

Answers

$(2)/(3)(6y+9)=(3)/(5)(15x-20)\ \ \ | multiply\ by\ 15\n\n10(6y+9)=9(15x-20)\n\n60y+90=135x-180\ \ \ | subtract\ 90\n\n60y=135x-270\ \ \ | divide\ by\ 60\n\nSlope\ intercept\ form:\ y=2.25x-4.5$

Eric owns and operates the Hot Ham food truck. The expression 3.25b+2h3.25b+2h 3.25b+2h gives the cost of bb b burgers and hh h hot dogs. What is the cost of 44 4 burgers and 66 6 hot dogs?

Answers

Answer:

The cost of 4 burgers and 6 hot dogs is $25.

Step-by-step explanation:

We are given that,

The expression for the cost of 'b' burgers and 'h' hot dogs is $Cost=3.25b+2h$ .

It is required to find the cost of 4 burgers and 6 hot dogs.

So, on substituting, we have,

$Cost=3.25* 4+2* 6$ .

i.e. $Cost=13+12$ .

i.e. Cost = $25

Hence, the cost of 4 burgers and 6 hot dogs is $25.

On a baseball field, the pitchers mound is 60.5 feet from home plate. During practice, a batter hits a ball 186 feet at an angle of 40 degrees to the right of the pitchers mound. An outfielder catches the ball and throws it to the pitcher. Approximately how far does the outfielder throw the ball?!

Answers

Use cosine law to solve for x

$x^2=60.5^2+186^2-2*60.5*186* cos(40^o)\nx^2=38,256.25-17,240.6\nx^2=21,015.65\nx= √(21,015.65) \nx=145$

Answer:

The outfielder threw the ball 145 feet away.

Step-by-step explanation:

We are given that,

Distance of mound from home plate = 60.5 feet

Distance of outfielder from home plate = 186 feet

Angle made by the batter = 40°

So, using the cosine law, we have,

$c^(2)=a^(2)+b^(2)-2ab\cos \theta$

i.e. $c^(2)=(60.5)^(2)+(186)^(2)-2* 60.5* 186* \cos 40$

i.e. $c^(2)=38256.25-22506* 0.766$

i.e. $c^(2)=38256.25-17239.596$

i.e. $c^(2)=21016.654$

i.e. c = ±144.97 ≈ ±145

Since, the distance cannot be negative.

Thus, the outfielder threw the ball 145 feet away.

Compared to its parent function the transformation of the following : y= -3x - 3 + 4a) reflected respect to x-axis, stretched vertically, moved 3 to the left and 4 up

b) stretched horizontally, moved 3 to the right and 4 up

c) reflected with respect to x-axis, stretched vertically, moved 3 to the right and 4 up

d) stretched horizontally, moved 3 to the left and 4 down

Answers

The answer is B
Hope it helps!!

Prove:
lim x^3 = 8.
x approaches 2

Answers

when we compute the value of a limit, all that we do is to change the value of the parameter
lim x^3 = (2)^3= 2x2x2=8
x approaches 2

Simplify the expression

Answers

Answer:

f(x) = 5x² + 2x

g(x) = 6x - 6

Step-by-step explanation:

$(5x^3-8x^2-4x)/(6x^2-18x+12)\n\n6(x^2-3x+2)\ne0\ \iff\ x=(3\pm√(9-8))/(2)\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\n\n\n(5x^3-8x^2-4x)/(6x^2-18x+12)=(x(5x^2-8x-4))/(6(x^2-3x+2))=(x(5x^2-10x+2x-4))/(6(x^2-2x-x+2))=\n\n\n=(x[5x(x-2)+2(x-2)])/(6[x(x-2)-(x-2)]) =(x(x-2)(5x+2))/(6(x-2)(x-1))=(x(5x+2))/(6(x-1))=(5x^2+2x)/(6x-6)\n\n\nf(x)=5x^2+2x\n\ng(x)=6x-6$