You toss 3 fair coins in the air at once.a) List the sample space.
b) What is the probability of getting all 3 heads?
c) What is the probability of getting all 3 tails?
d) What is the probability of getting 1 head and 2 tails?
e) What is the probability of getting 1 tail and 2 heads?
f) What do the probabilities from parts b through e add up to?

Answers

Answer 1

Answer: The probability of a head or tail upon flipping is 50-50. THe asnwers are as followsL
a. {HHH, HHT, HTT, TTT, TTH, THH, HTH, THT}b and c. p = 3C3 * 0.5^3 = 0.125d. from a, p = 3/8 = 0.375e. from a, p = 3/8 = 0.375f. 0.875

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Please help! Find the x-intercepts of the parabola with vertex (-4, 2) and y-intercept (0, -30). Write your answer in this form: (x1, y1), (x2, y2). If necessary, round your answer to the nearest hundredth.
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20% of my money is £2.55 What is 2/5 of it?

What is 5 1/6 (-2/5) written as a fraction

Answers

Answer:

-17/5

Use math papa it gives you the answer all you have to do is unput the equation

Step-by-step explanation:

Three of four numbers have a sum of 22. If the average of the four numbers is 8, what is the fourth number?

Answers

$a+b+c=22\n \n (a+b+c+x)/(4)=8\n \n a+b+c+x=32\n \n 22+x=32\n \n \boxed{x=10}$

Answer:

Step-by-step explanation:

Let's call the four numbers x1, x2, x3, and x4. Their average is (x1 + x2 + x3 + x4)/4 = 8, so x1 + x2 + x3 + x4 = 4 × 8 = 32. And we know that three of the numbers have a sum of 22, so x1 + x2 + x3 = 22.

Subtracting this last equation from the first equation, we have:

$\sf:\implies{x4 = 32 - (x1 + x2 + x3) = }$

$\sf:\implies{32 - 22 = 10}$

So the fourth number is 10.

A 5-column table with 4 rows. The columns are labeled sock 2 and the rows are labeled sock 1. Column 1 contains entries blank, b, b, w, w. Column 2 contains entries b, (b, b), (b, b), (w, b), (w, b). Column 3 contains entries b, (b, b), (b, b), (w, b), (w, b). Column 4 contains entries w, (b, w), (b, w), (w, w), (w, w). Column 5 contains entries w, (b, w), (b, w), (w, w), (w, w).A drawer contains one pair of brown socks and one pair of white socks. The table shows the possible outcomes, or sample space, for choosing a sock, replacing it, and then choosing another sock.

If the first sock is not replaced, how many possible outcomes are there?

How many of these outcomes contain a matching pair of socks?

Answers

Answer:If the first sock is not replaced, how many possible outcomes are there? 12

How many of these outcomes contain a matching pair of socks? 4

Step-by-step explanation:

Answer:

the first one is 12 and the last one is 4

Step-by-step explanation:

i got i right

find the first,fourth,and tenth terms of the arithmetic sequence described by the given rule. A(n)=5+(n-1)(1/6)

Answers

Answer:

First term is 5

Fourth term is 5.5

Tenth term is 6.5

Step-by-step explanation:

Given :The rule as $A(n)=5+(n-1)((1)/(6))$

We have to find find the first,fourth,and tenth terms of the arithmetic sequence.

Consider the given rule ,

$A(n)=5+(n-1)((1)/(6))$

For first term , put n = 1

$A(1)=5+(1-1)((1)/(6))$

Simplify , we have,

$A(1)=5$

For fourth term, Put n = 4

we have,

$A(4)=5+(4-1)((1)/(6))$

Simplify, we have,

$A(4)=5+(3)((1)/(6))$

$A(4)=5+(1)/(2)=5.5$

For tenth term, put n = 10 ,

We have,

$A(10)=5+(10-1)((1)/(6))$

$A(10)=5+(9)((1)/(6))$

$A(4)=5+(3)/(2)=6.5$

Thus, First term is 5

Fourth term is 5.5

Tenth term is 6.5

a₁ = 5 an = a₁ + ( n-1) * r
wyliczymy jednak - so we enumerate
a₁ = 5 + (1-1) * (1/6) = 5 + 0* 1/6 = 5 + 0 = 5
a₄ = 5 + (4 - 1) * (1/6) = 5 + 3 * (1/6) = 5 + 3/6 =5 1/2 = 5,5
a₁₀ = 5 + (10 - 1) * (1/6) = 5 + 9 * (1/6) = 5 + (9/6) = 5 + 3/2 = 6 1/2 = 6,5

sam has 3 cookies jars all three jars contain the same number of cookies if sam gets 7 more he will have 73 cookies

Answers

Answer

21 cookies

Step-by-step explanation

7+a/ 3 = 5
What is the answer

Answers

Answer:

a=8

Step-by-step explanation

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