The tangential velocity of a satellite, with the same angular velocity as the Earth and 5x10^7 m distance from Earth's center, is calculated to be approximately 3650 m/s.
The tangential velocity of a satellite is given by the formula v = rω, where 'v' is the tangential velocity, 'r' is the radius (distance from the center of the Earth to the satellite), and 'ω' is the angular velocity. The referenced satellite's angular velocity is the same as that of the Earth, which is approximately 7.292 x 10^-5 rad/s. Given r = 5x10^7 m (the satellite's distance from Earth), we input these values into the formula:
v = (5x10^7 m)(7.292 x 10^-5 rad/s)
Upon calculation, we find that the satellite's tangential velocity is approximately 3650 m/s.
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1. The volume will increase.
2. The change in the volume is 73 mL
From the question given above, the following data were obtained:
Using the Charles' law equation, the new volume of the cylinder can be obtained as follow:
V₁ / T₁ = V₂ / T₂
200 / 273 = V₂ / 373
Cross multiply
273 × V₂ = 200 × 373
273 × V₂ = 74600
Divide both side by 273
V₂ = 74600 / 273
V₂ ≈ 273 mL
From the above calculation, we can see that the new volume increased.
The change in the volume can be obtained as illustrated below:
ΔV = V₂ – V₁
ΔV = 273 – 200
ΔV = 73 mL
Learn more about Charles' law:
The force between the two point charges is "5 N".
The total of almost all of the forces operating on an item is referred to as the magnitude of force. When some of the forces operate in the same direction, this same magnitude rises. Whenever forces occur in opposite directions around an item, the amount of something like the force diminishes.
Distance between charges, d = 6 cm
Attractive force, F = 20 N
Separated, d' = 12 cm
We know the formula,
F =
or,
F ...(Equation 1)
New force will be:
F' ...(Equation 2)
From "Equation 1" and "Equation 2", we get
→
By substituting the values,
F' = 5 N
Thus the approach above is appropriate.
Find out more information about force here:
Answer:
The force between them when they are separated by 12 cm is 5 N.
Explanation:
Distance between two point charges, d = 6 cm
The attractive force between them is 20 N, F = 20 N
Let F' is the force between them when they are separated by 12 cm, d' = 12 cm
The force between point charges is given by the formula as :
........(1)
New force,
............(2)
From (1) and (2) :
So, the force between them when they are separated by 12 cm is 5 N. Hence, this is the required solution.