A railroad tunnel is shaped like a semiellipseThe height of the tunnel at the center is 58 ft and the vertical clearance must be 29 ft at a point 21 ft from the center. Find an equation for the ellipse.

Answers

Answer 1

Answer: y²/58² + x²/b² = 1
(0,58), (-21,29), and (21,29) are points on the ellipse.

29²/58² + 21²/b² = 1
¼ + 21²/b² = 1
21²/b² = ¾
4·21²/3 = b²
b² = 588

y²/3364 + x²/588 = 1

Answer 2

Answer:

Answer:

Step-by-step explanation:

The equation of ellipse is given as:

$(x^2)/(a^2)+(y^2)/(b^2)=1$ (1)

Now, from the given information, The ellipse passes through (0, 58), (0, -58), (21, 29), thus equation (1) becomes:

$(0)/(a^2)+((58)^2)/(b^2)=1$

⇒ $b^2=(58)^2$

⇒ $b^2=3364$

Also, $((21)^2)/(a^2)+((29)^2)/((58)^2)=1$

⇒ $((21)^2)/(a^2)=1-(841)/(3364)$

⇒ $((21)^2)/(a^2)=(3)/(4)$

⇒ $a^2=(4(441))/(3)$

⇒ $a^2=588$

Now, substituting the values of $a^2 and b^2$ in the equation (1), we have

$(x^2)/(588)+(y^2)/(3364)=1$

which is the required equation for ellipse.

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When can there be a point equidistant from four different points?

Answers

The center of a circle, because of the constant radius, or the center of a square because all the diagonals are equal. If that's what you're asking?

Help please ahahah i hate this sm i really need help

Answers

Answer:

-7/6

Step-by-step explanation:

- take two values of x and their corresponding two values of y

- use the slope formula ( y2 - y1 )/( x2 - x1 )

- i used x values 4 and 10 but you can use any

( -6 - (-13) ) / ( 4 - 10 ) = -7/6

It should be -7/6 hope you got it correct

find the volume of a can of chicken broth that had a diameter of 7.5cm and a height of 11cm. round 5o the neatest tenth

Answers

cans are normally cylinders
Vcylinder=hpir^2

h=11

d/2=r
7.5/2=3.75=r

V=11pi3.75^2
V=11pi14.0625
V=154.6875pi
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A rectangle has a length of 4 2/5 cm and a width of 1 3/10 cm. What is the area of the rectangle?

Answers

If you would like to know what is the area of the rectangle, you can calculate this using the following steps:

the area = a length * a width
x = 4 2/5 cm * 1 3/10 cm
x = 22/5 * 13/10
x = 143/25 = 5 18/25 square cm

The correct result would be 5 18/25 square cm.

PLEASE HELP 15 POINTS WILL GIVE BRAINLYDiego says a quadrilateral with four congruent sides is always a regular polygon. Mai says it never is one. Do you agree with either of them?
Diego is correct
Mia is correct
Both are wrong. If a quadrilateral with 4 congruent sides also has 4 right angles, then it will be a regular polygon.

Answers

A regular polygon all the angles, as well as all the sides, are equal.

Diego's claim is the quadrilateral with four congruent sides is always a regular polygon. He is only mentioning that the sides are equals.

He has not mentioned anything about the angles, the angles may or may not be equals.

In the case, if all the angles are equal too, then the claimed quadrilateral will be a regular polygon as shown in figure(a).

So, for this case, Diego's claim is correct while Mai's claim is also wrong.

While if all the angles are not equal, then the claimed quadrilateral will not be a regular polygon as shown in figure(b).

In this case, Diego's claim is wrong while Mai's claim is correct.

So, overall, considering both the case together, none of them have the correct claim.

So, both are wrong.

Find the sum: (3x2 + 5x − 8) + (5x2 − 13x − 5)8x2 + 8x − 13
8x2 − 8x + 13
8x2 − 8x − 13
8x2 − x − 13

Answers

the third one is true

good luck

(3x^2 + 5x − 8) + (5x^2 − 13x − 5)

3x^2 + 5x − 8
+ 5x^2 − 13x − 5
----------------------------
8x^2 - 8x - 13

The answer is choice C: 8x^2 − 8x − 13

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