A study conducted to assist the impact of caffeine consumption, smoking, alchohol consumption, and physical activity on cardiovascular disease. Suppose that 40% of participants consume caffeine and smoke. If 8 participants are evaluated what is the probability that: A. Exactly half of them consume caffene and they smoke?

Answers

Answer 1

Answer:

Answer:

8.4

Step-by-step explanation:

Related Questions

A school newspaper reporter decides to randomly survey 18 students to see if they will attend Tet festivities this year. Based on past years, she knows that 11% of students attend Tet festivities. We are interested in the number of students who will attend the festivities. Find the probability that more than 2 students will attend.
Choices :A. 40.1 metersB. 12.3 metersC. 19.2 metersD. 47 meters
There are 80 participants in a competition. The average score of each participant is 58.5. The average score of the male participants is 64 and the average score of the female participants is 56. How many male participants are there in the competition?
Carol keeps her toys in a box that is shaped like a rectangular prism. The height of the box is 24 inches, the width is 36 inches, and the length is 36 inches. Convert the dimensions from inches to feet, then find the volume of the toy box in cubic feet. Remember that 12 inches = 1 foot. A. 8 ft 3 B. 12 ft 3 C. 18 ft 3 D. 36 ft 3
PLEASE HELPHow do I solve 7,9, and 10 also what are the answers?

What is the domain of the function f (x) = StartFraction x + 1 Over x squared minus 6 x + 8 EndFraction?

Answers

Answer:

D Edg

Step-by-step explanation:

all real numbers except 2 and 4

Answer: (-∞, 2)∪(2, 3]∪(4, ∞)

Step-by-step explanation:

Domain is the allowed x values in the function. The numerator, x + 1 will be defined for all numbers. But that fraction wont be, the minute that fractions denominator is equal to zero, your entire function becomes undefined.

So lets figure out what number will make this undefined. Then we'll know the functions domain is everywhere but that x value.

Make x^2 - 6x + 8 = 0

What two numbers multiply to equal +8 but add to equal -6? Thats -4 and -2.

(x - 4)(x - 2) = 0 This means the function is undefined when x equals 4 and 2

(-∞, 2)∪(2, 3]∪(4, ∞)

F(x)=2

x

2

−

5

x

−

8

2x

2

−5x−8

g

(

x

)

=

g(x)=

−

5

x

+

4

−5x+4

Find:

(

g

∘

f

)

(

x

)

Find: (g∘f)(x)

Answers

Answer:

$(g\ o\ f)(x) = -10x^2 + 25x + 44$

Step-by-step explanation:

Given

$f(x) = 2x^2 - 5x - 8$

$g(x) = -5x+4$

Required

$Find:\ (g\ o\ f)(x)$

In functions;

$(g\ o\ f)(x) = g(f(x))$

Substitute $f(x) = 2x^2 - 5x - 8$ in $(g\ o\ f)(x) = g(f(x))$

$(g\ o\ f)(x) = g(f(2x^2 - 5x - 8))$

Solving for $g(f(2x^2 - 5x - 8))$

If $g(x) = -5x+4$

then

$g(f(2x^2 - 5x - 8)) = -5(2x^2 - 5x - 8) + 4$

Open Bracket

$g(f(2x^2 - 5x - 8)) = -10x^2 + 25x + 40 + 4$

$g(f(2x^2 - 5x - 8)) = -10x^2 + 25x + 44$

Recall that:

$(g\ o\ f)(x) = g(f(2x^2 - 5x - 8))$

This implies that

$(g\ o\ f)(x) = -10x^2 + 25x + 44$

A square has sides of 16 units. Squares x + 1 by x + 1 units are cut out of each corner, and then the sides are folded up to create an open box. Express the volume V of the box as a function in terms of x. V(x)=

Answers

A distance of (x+1) is cut in from both sides, so the base dimensions are

... 16 -2(x+1) = 14-2x

The depth of the fold is (x+1), so that is the depth of the box.

The volume is ...

... V(x) = (x+1)(14 -2x)²

tanya makes 5/8 of the foul shots she attempts during a basketball practice, if she took 48 shots, how many did she make?

Answers

calculate $(5)/(8)$ × 48 = 5 × 6 = 30

she had 30 foul shots hence 48 - 30 = 18

She made 18 shots

Made 5 shots every 8 attempts so if there were 48 attempts lets brake them in groups of 8.

48/8= 6 groups
5 made shots in each of the 6 groups is
5•6= 30 made shots.

30 shots were made out of 48 attempts

Every day a kindergarten class chooses randomly one of the 50 state flags to hang on the wall, without regard to previous choices, We are interested in the flags that are chosen on Monday, Tuesday and Wednesday of next week.a) Describe a sample space \Omega and a probability measure P to model this experiment.

b) What is the probability that the class hangs Wisconsin's flag on Monday, Michigan's flag on Tuesday, and California's flag on Wednesday.?

c) What is the probability that Wisconsin's flag will be hung at least two of the three days?

Answers

Answer:

a.) P(x = X) = $(1)/(50)$

b.) $(1)/(50) *(1)/(50) *(1)/(50) = (1)/(125000)$

c.) 0.00118

Step-by-step explanation:

The sample space Ω = flags of all 50 states

a.) Any one of the flags is randomly chosen. Therefore we can write the

probability measure as P(x = X) = $(1)/(50)$ , for all the elements of the sample

space, that is for all x ∈ Ω.

b.) the probability that the class hangs Wisconsin's flag on Monday,

Michigan's flag on Tuesday, and California's flag on Wednesday

= $(1)/(50) *(1)/(50) *(1)/(50) = (1)/(125000)$

c.) the probability that Wisconsin's flag will be hung at least two of the three days

= Probability that Wisconsin's flag will be hung on two days + Probability that Wisconsin's flag will be hung on three days

= P(x = 2) + P(x = 3)

= $(\binom{3}{2}* (1)/(50) * (1)/(50)* (49)/(50)) + (\binom{3}{3}* (1)/(50) * (1)/(50)* (1)/(50))\n$

= $(147)/(125000) + (1)/(125000)$

= $(148)/(125000)$

= 0.00118

Final answer:

The sample space for this experiment is all the possible combinations of flags from the 50 U.S. states for the three days. The probability of hanging Wisconsin's flag on Monday, Michigan's on Tuesday, and California's on Wednesday is 1/125,000. The probability of hanging Wisconsin's flag at least two of the three days is 294/125,000.

Explanation:

a) The sample space Ω for this experiment comprises of all possible combinations of flags from the 50 U.S. states for the three days. Hence, the total number of outcomes in the sample space Ω would be 50*50*50 = 125,000. Every outcome in this space is equally likely, so the probability measure P would assign a probability of 1/125,000 to each outcome.

b) As each day's choice is independent of the others and each state's flag is equally likely to be chosen, the probability that Wisconsin's flag is hung on Monday, Michigan's flag is hung on Tuesday, and California's flag is hung on Wednesday would be (1/50) * (1/50) * (1/50) = 1/125,000.

c) To find the probability that Wisconsin's flag will be hung at least two of the three days, we have to add the probabilities for the three situations where Wisconsin's flag is hung exactly twice plus the situation where Wisconsin's flag is hung all three days. The final probability would be [(3 * (1/50)² * (49/50)) + (1/50)³] = 294/125,000.

Learn more about Probability here:

brainly.com/question/22962752

#SPJ3

Hello can you please help me posted picture of question

Answers

This is true statement.

Sample space is made from all the possible outcomes that an event can have.
For example when tossing a coin, the possible outcomes are Head and Tail so the sample space will be {Head, Tail}.

Thus, option A is the correct answer

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