1.What basic trigonometric identity would you use to verify that cot x sin x = cos x? . . a. cos^2x+sin^2x=1.
b. cot x= cosx/sinx.
c. cos x= 1/sec x.
d. sin x= 1/csc x. .
2.What basic trigonometric identity would you use to verify that sin^2x+cos^2x/cosx= sec x?.
a. sin x=1/csc x.
b. 1+cot^2x=csc^2x.
c. cos^2x+sin^2x=1.
d. cos x= 1/sec x

Answers

Answer 1
Answer: 1 ) cot x * sin x = cos x
(cos x / sin x) * sin x = cos x 
cos x = cos x
Answer: B ) cot x = cos x / sin x
2 ) ( sin² x + cos² x ) / cos x = sec x
1/cos x = sec x
sec x = sec x
Answer: C ) cos² x + sin² x = 1
Answer 2
Answer:

Answer:

C

Step-by-step explanation:


Related Questions

Two equivalent rational numbers of -13/9
Help me with this Math pleaseee
What is the solution of the system of equations? y = –3x + 8 y = –5x – 2
devin began running a month ago to get back in shape.the first day he ran .5 miles. each day after that he ran 10% more than the previous day for a total of 30 days. use the formula for the sum of a finite geometric series to calculate the total distance devin ran over the 30 days.
6) A student scored an 88, S2, and 76 on three math tests. What does the student need to get on the fourth test to have an average of 85 for all four tests? James wants to use algebra to solve this problem. Which equation should he use? 256 4x 85 256 x 85 85 x 256 256 85x

Is there a relationship between area or perimeter of a rectangle

Answers

Hello,

For a given perimeter (P) there are an infinity of Area (A)
Let's say x the length, and y the wide of the rectangle

P=2(x+y)
A=xy
k=x-y >=0

As (x+y)²-4xy=(x-y)²: A²-4P=k² or P=(A²-k²)/4
In primus, you will find a graph (abacus) giving P for a A and k given.
Negative Area or P are excluded.(just remind the first quadrant, A>=0 and P>=0)

The government’s claims that students earn an average of $4,500 during their summer break from studies. A random sample of students gave had a sample average of $3,975 and a 95% confidence interval was found to be $3,525 < µ < $4,425. This interval is interpreted to mean that:a. because our specific confidence interval does not contain the value $4500 there is a 95% probability that the true average summer earnings is not $4500.b. if we were to repeat our survey many times, then about 95% of all the confidence intervals will contain the value $4500.c. if we repeat our survey many times, then about 95% of our confidence intervals will contain the true value of the average earnings of students.d. there is a 95% probability that the true average earnings are between $3525 and $4425 for all students.

Answers

Answer:

d. there is a 95% probability that the true average earnings are between $3525 and $4425 for all students.

Step-by-step explanation:

95% confidence interval  $3,525 < µ < $4,425 suggests that (choice d) there is a 95% probability that the true average earnings are between $3525 and $4425 for all students.

This result also suggests that (choice a) the true average summer earnings is not $4500, because our specific confidence interval does not contain the value $4500. But 95% probability is about the interval $3,525 < µ < $4,425, not the value $4500.  

Please solve for x:

:)

Answers

Hello!

As you can see, the angles we are given make up a 90 degree angle. We have the equation below.

4x=90

To solve we just divide both sides by 4.

90/4=22.5
x=22.5

I hope this helps!

What do you notice about the y-coordinates before and after a horizontal stretch? A) The y-coordinates increase after a horizontal stretch. B) The y-coordinates decrease after a horizontal stretch. C) The y-coordinates remain the same after a horizontal stretch. D) The y-coordinates are not affected by a horizontal stretch.

Answers