Answer:
Z = 0.8528 < 2.576
The calculated value Z = 0.8528 < 2.576 at 0.01 level of significance
Null hypothesis is Accepted at 0.01 level of significance.
There is no significance difference between the means
Step-by-step explanation:
Given data
size of the sample 'n' = 11
mean of the sample x⁻ =20.5
Mean of the Population μ = 18.7
Standard deviation of Population σ = 7
Test statistic
Z = 0.8528
critical Value
The calculated value Z = 0.8528 < 2.576 at 0.01 level of significance
Null hypothesis is Accepted at 0.01 level of significance.
There is no significance difference between the means
Answer:Answer:
B. 18.7 ± 9.7
Step-by-step explanation:
Answer:
Step-by-step explanation:
The question is incomplete as the method is not given.
However, the question can still be solved.
Given
Make xi the subject in the first equation
Substitute 1 + x2 for xi in the second equation
Open bracket
Collect Like Terms
Solve for x2
Recall that:
The solution to the given system of equations is obtained through substitution. The process involves replacing a variable in one equation with an expression from the other. The final solutions are x1=1 and x2=0.
The system of equations in question is:
1) x1 - x2 = 1
2) 3x1 + x2 = 3
The method to solve this system is through substitution or elimination. First, rewrite the first equation x1 = x2 + 1. This allows us to substitute x1 - 1 for x2 in the second equation, yielding 3(x2 + 1) + x2 = 3, simplifying to 4x2 + 3 = 3. Solving for x2, we get x2 = 0. Substituting x2 into x1 = x2 + 1, we conclude that x1 = 1. Thus, the solution to the system is x1 = 1, x2 = 0.
#SPJ3
Answer:
0.94 cents
Step-by-step explanation:
If you multiply 0.67 with 141 you will see that you will end up with the same answer as above.
0.666 estimates to 0.67
For A to B, or segment AB, we have the points (1,1) and (4,3). (x1, y1) = (1,1) and (x2, y2) = (4,3);
x = 1 + t(4 - 1)
y = 1 + t(3 - 1)
A to B => (x = 1 + 3t, y = 1 + 2t)
We can apply a similar process for BC and AC. For BC we have (x1, y1) = (4,3) and (x2,y2) = (1,7);
x = 4 + t(1 - 4)
y = 3 + t(7 - 3)
B to C => (x = 4 - 3t, y = 3 + 4t)
(x1, y1) = (1, 1) and (x2, y2) = (1, 7);
x = 1 + t(1 - 1)
y = 1 + t(7 - 1)
A to C => (x = 1, y = 1 + 6t)
Here is your graph of the triangle. Desmos is a really great tool to use;
ΔDEF ≅ ΔSRU
ΔDEF ≅ ΔRSU
ΔDEF ≅ ΔRUS
Answer: B.) ΔDEF ≅ ΔSRU
Step-by-step explanation:
The answer is correct on Edge.
B. We can't determine from the given information.
C. Exactly one
D. None