PHYSICS HIGH SCHOOL

Convert the following:a)2500 kilogram into gram.
b)335 hours into seconds.
c)1 day into seconds.​

Answers

Answer 1
Answer:

Explanation:

A) 1 kg = 1000g

2500kg = 2500000g

B 1 hour = 3600 sec

335 hour = 1206000sec

C 1day = 24 hours

1 hour = 3600 sec

24 hours = 86400sec
Answer 2
Answer:

Answers:

a.2500000grams

B.1206000seconds

c.86400seconds.

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Which of the following statements is true about "speed" and "acceleration"?A. When an object has acceleration, its velocity may increase or decrease gradually.
B. When the acceleration of the object is zero, its velocity is also zero.
C. The direction of object velocity is not necessarily the same as that of acceleration.
D. When the object is vertically thrown up to the highest point, the speed and acceleration are zero.
E. When the object is free-falling, the displacement and acceleration direction are the same.

Answers

Answer:

A

Explanation:

An 8.10 kilogram box of mass is kept at a height of 0.99 meters above ground level. What is the potential energy of the box? (given g = 9.8 meters/second2). A. 68 joules. B. 79 joules. C. 81 joules. D. 99 joules. E. 1.0 × 102 joules

Answers

The answer is B. 79 joules.

To calculate this we will use the formula for potential energy (PE):
PE = m * g * h
where m is mass of an object, g is gravitational acceleration, h is a height at which is the object.

It s given:
m = 8.10 kg
g = 9.8 m/s²
h = 0.99 m

After replacing them in the formula for potential energy:
PE = 8.10 * 9.8 * 0.99 = 78.6 J ≈ 79 J

The answer would be 79J because when you multiply 8.1*0.99*9.8 you get 7.89, which rounds to 7.9.

Answer choice (B).

A ball is dropped from a height of 16 feet. Each time it drops h feet, it rebounds 0.81h feet. Find the total distance traveled by the ball.

Answers

The first drop makes the ball travel 16 m.
Then the maximum height decreases to 16 x 0.81
And the distance traveled is twice the distance traveled.
If we make a pattern, this forms a geometric progression in which the common ratio is 0.81 and the first term is 16.
The sum of this series: a / (1 - r)
= 16 ( 1 - 0.81)
= 84 feet
This is the upward height, and the ball returns every time so:
Total distance = 84 x 2
= 168 feet

According to Newton's third law of motion, if you push against a wall, the wall will __________.a. attract you with its low gravity
b. fall over once you overcome its inertia
c. push against you with equal force
d. heat up due to energy transfer

Answers

c. push against you with equal force

What is newton's third law of motion?

Newton's third law simply states that for every action there is an equal and opposite reaction.

So, if object A acts a force upon object B, then object B will exert an opposite yet equal force upon object A.

Newton's third law of motion describes that,

Forces always act in equal but opposite pairs.

Another way of saying this is for every action, there is an equal but opposite reaction.

This means that when you push on a wall, the wall pushes back on you with a force equal in strength to the force you exerted.

A person pushes against a wall (action force), and the wall exerts an equal and opposite force against the person (reaction force).

Therefore,

According to Newton's third law of motion, if you push against a wall, the wall will push against you with equal force.

Learn more about Newton's third law of motion here:

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C. push against you with equal force

A speeder passes a parked police car at a constant speed of 23.3 m/s. At that instant, the police car starts from rest with a uniform acceleration of 2.75 m/s 2 . How much time passes before the speeder is overtaken by the police car? Answer in units of s.

Answers

Answer:

32s

Explanation:

We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:

x=vt=23.3(m)/(s)t

and the police car distance:

x=vt+(at^(2))/(2)=0+(2.75(m)/(s^(2)) t^(2))/(2)=0.73(m)/(s^(2))

Since they both travel the same distance x, we can equal both formulas and solve for t:

0 = 0.73(m)/(s^(2))t^(2)-23.3(m)/(s) t\n\n0=t(0.73(m)/(s^(2))t-23.3(m)/(s) )\n\n

Two solutions exist to the equation; the first one being t=0

The second solution will be:

0.73(m)/(s^(2))t=23.3(m)/(s)\n\nt=(23.3(m)/(s))/(0.73(m)/(s^(2)))=32s

This result allows us to confirm that the police car will take 32s to catch up to the speeder

The main difference between speed and velocity involves A. direction.
B. weight.
C. gravity.
D. distance.

Answers

A. Direction

Speed is just distance divided by time, but velocity is displacement divided by time and displacement has direction. Speed will always be positive, but velocity can be either positive or negative.

The Correct answer to this question for Penn Foster Students is: Direction
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