Answer:
The characteristic properties are hard and brittle solids having high melting and boiling point
Explanation:
Ionic compounds are the type of chemical compounds that are formed by ionic bonding. An ionic compound is composed of two oppositely charged ions that are held together by electrostatic forces of attraction.
They are solids at room temperature and usually have a crystalline structure and have high melting and boiling point. Ionic compounds are hard but also brittle.
A. glass
B. pottery
C. ice
D. gold
Gold is malleable while glass, pottery, and ice are not.
Malleability is the ability of a material to be hammered or rolled into thin sheets without breaking. Gold is highly malleable and can be shaped into various forms, such as jewelry and gold leaf. Glass, pottery, and ice, on the other hand, are not malleable because they will break or shatter when hammered or rolled into thin sheets.
Gold is malleable because its metallic bonds allow its atoms to slide past one another without breaking. Glass, pottery, and ice lack these bonds and have a more rigid structure, making them non-malleable. Instead, glass and pottery are brittle, while ice can fracture under stress due to its molecular structure.
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Answer:
If we have
Then
This is a Acidic Solution
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(1) 154.3 g (3) 171.3 g
(2) 155.3 g (4) 308.6 g
The molar mass of barium hydroxide is 171.3 g/mol (option 3).
Molar mass is the mass of a given substance divided by its amount, measured in moles. It is commonly expressed in grams per mole.
The molar mass of a compound can be calculated by summing up the atomic masses of the constituent elements. According to this question, barium hydroxide was given. The molarmass can be calculated as follows:
Ba(OH)₂ = 137.33 + (16 + 1)2
= 137.33 + 34
= 171.3g/mol (option 3).
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B. stroke.
C. kidney damage.
D. all of the above.
Answer: The empirical formula for the given compound is
Explanation:
We are given:
Percentage of H = 17.6 %
Percentage of N = 82.4 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of H = 17.6 g
Mass of N = 82.4 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Hydrogen =
Moles of Nitrogen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.88 moles.
For Hydrogen =
For Nitrogen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of H : N = 3 : 1
Hence, the empirical formula for the given compound is