Find the value of c so that the polynomial P ( x ) = 4x 3 + c x 2 + x + 2 have the same remainder when it is divided by x-2 and x+1?
Answers
For the polynomial P (x) = 4x³ + cx² +x + 2 the value of c is -13.
What is polynomial?
Polynomial is an algebraic expression that has more than two terms. In other words, it is a combination of different variables with mathematical operations.
The given equation of polynomial is,
P (x) = 4x³ + cx² +x + 2 (1)
Since, When polynomial is divided by x-2, and x+1 it gives the same remainder,
This implies that at x=2 and x=-1, the value of the polynomial will be equal.
P(2)=P(-1)
4×(2)³+c(2)²+2+2=4×(-1)³+c(-1)²+(-1)+2
32+4c+4=-4+c+1
3c=-3-36
3c=-39
c=-13
So, the value of c is -13.
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Answer:
Step-by-step explanation:I don't say you have to mark my ans as brainliest but if you think it has really helped you please don't forget to thank me ...
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Answers
m = 18-13 over 8 - 11
m= 5 over -3 or simplified to m= -5 over 3
Answer: Rate of Change and Slope Quick Check
C. -1/3
D. (11,13) (8,18)
B. -2
D. Undefined
D. 55/1
Step-by-step explanation:
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Answers
dy/dx = 5 cos (pi/12 (x-2)) (pi/12)
dy/dx = 5 pi/12 cos(pi/12 (x-2))
Equate to zero:
5 pi/12 cos(pi/12 (x-2)) =0
pi/12 (x-2) = 3pi/2
x = 8
Substituting,
y= -2 + 5sin( pi/12 (8-2)
y = -1.86
Answer:
i got 3
Step-by-step explanation:
Answers
Answer: c 17.9°
Step-by-step explanation:
Answer:
the answer is c
Step-by-step explanation:
I took the test
How do you solve this equation?
Answers
8=8p+13-3p
Subtract 8p and 3p
Thats 5p
Now
8=5p + 13
Subtract 13 from 8
-5 = 5p
Divide -5 by 5
-1 = p
8=8p+13-3p
group like terms
8=8p-3p+13
add like terms
8=5p+13
minus 13 from both sides
8-13=5p+13-13
-5=5p+0
-5=5p
divide both sides by 5
-5/5=5p/5
-1=1p
-1=p
p=-1
Answers
To find the vertical asymptotic equations of the rational function, we must first find the points of intersection of the function with the x-axis. These points are the solutions of the equation f(x) = 0. We decompose the exponential function into the product of two expressions: f(x) = (x² + 9x)(x² - 2x - 15) Now we can set each of the expressions inside the parentheses equal to zero and solve the vertical asymptotic equations: x² + 9x = 0 or x² - 2x - 15 = 0 To solve the first equation, we can factor x out: x(x + 9) = 0 So the two vertical asymptote equations are x = 0 and x + 9 = 0 (that is, x = -9). To solve the second equation, we can use the analysis method or the quadratic formula. Using the analysis method, we can decompose the expression x² - 2x - 15 in the following form: (x - 5)(x + 3) = 0 Therefore, two vertical asymptote equations equal to x - 5 = 0 (that is, x = 5) and x + 3 = 0 (that is, x = -3). So the vertical asymptotic equations of the rational function f(x) = (x² + 9x)(x² - 2x - 15) are equal to x = 0, x = -9, x = 5 and x = -3.